GMAT Inequalities 700+ questions

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  • Опубліковано 27 гру 2024

КОМЕНТАРІ • 26

  • @lgiacomazzi
    @lgiacomazzi 5 років тому +13

    I believe the exercise on minute 18:00 the answer was supposed to be C. I think you just got the answer choices mixed up

  • @dristhisharma1294
    @dristhisharma1294 5 років тому +3

    The one and the only channel on UA-cam with no bullshit only study. And infact one of the most oldest channel.

  • @srijonabhadra3672
    @srijonabhadra3672 4 роки тому +4

    At 18:11, I guess the answer should be 'C'

  • @pv7005
    @pv7005 2 роки тому

    Great video, was really helpful and each question was a great choice, thank you

  • @palashrawat401
    @palashrawat401 3 роки тому +1

    11:30- Great Question to revise (watch till the end for the final trap)

  • @arynt5960
    @arynt5960 2 роки тому

    In the fourth question, you arrived at the conclusion that x > y after statement 1. How did you arrive at the conclusion?
    Cannot understand. If we take x = -2, then why would be -2 +0.5 = -1.5 In this case x < y. Let me know if i have understood something wrong?

  • @rajanya
    @rajanya 4 роки тому

    In 23:36 , what if x= -2 and y is also equal to - 2. Then how can we say for sure that they have different signs? What if x = -3 and y = -1?

    • @AnkurBorwankar
      @AnkurBorwankar 4 роки тому

      By the first statement, xy < 0 , so either x or y must be negative but they can't both be negative.

    • @suvankarjana8652
      @suvankarjana8652 2 роки тому

      @Rajanya Dey, U targeted the explanation instead of targetting the question, the explanation is faulty and not valid for -3, -1 .... Let's put it this way, since xy

  • @Prerana2121
    @Prerana2121 4 роки тому

    At 8:21 Ques 2. If we have taken x< 0 , then why isn't it y= -x -x = -2x? why didn't we consider other x to be negative too?? Please clarify and help.

  • @madenvo
    @madenvo 5 років тому +3

    Isn't the answer to q3, C? 5a>4a. The question does not ask if 5a>4. Please clarify.

  • @mustafabohra4957
    @mustafabohra4957 5 років тому +3

    The answer to question no.2 should be A?

  • @gauravphore1333
    @gauravphore1333 3 роки тому

    Thank you very much. Great video

  • @suvankarjana8652
    @suvankarjana8652 2 роки тому

    The problem with question no. 3 is that the first statement says (x+y)^2 = 9a , and this is sufficient to answer since for this statement the value of x^2 + y^2 will never come down below 4.5a ........... U can take any values of positive x and y (or both negative) and try it as he said... A separate inequation exists proving this : (x - y)^2 = x^2 - 2xy + y^2 >=0, and we have x^2 + y^2 >= 2xy.

  • @vijayarana6931
    @vijayarana6931 5 років тому

    thanks really useful

  • @balkrushnavaghasia5340
    @balkrushnavaghasia5340 5 років тому

    In the 1st Question, why y can't be destroyed ?

    • @helpinghands9485
      @helpinghands9485 4 роки тому +1

      thats because we cannot multiply or divide by y , cause we can only do that operation with positive numbers , we dont know if y was positive , hope that helps

    • @Lucas-wd6yd
      @Lucas-wd6yd 4 роки тому

      @@helpinghands9485 Thanks for this answer, I have the same doubt.

    • @helpinghands9485
      @helpinghands9485 4 роки тому +5

      Hi , i have a small correction that i would like to state , The reason that we cannot cut off y , is because there is a small chance that y can be 0 , so imagine this , if ab=bc ,so here it does not mean that we can cut off b and a =c . because if b=0 and a =4 and c =10 then 0=0, so that doesnt mean that a=c all the time and we can cut off b from both sides so , when ab=bc it means , ab-bc=0, which leads to b(a-c)=0 , and this means either b=0 or a=c

  • @shubhama2908
    @shubhama2908 4 роки тому

    Great stuff, appreciate for sharing, just the last question could've been a bit more explicit.

  • @DakshGargas
    @DakshGargas 4 роки тому

    Thanks :) Loved it :D