Heat Capacity, Specific Heat, and Calorimetry
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- Опубліковано 24 лис 2015
- We can use coffee cups to do simple experiments to figure out how quickly different materials heat up and cool down. It's called calorimetry. Take a look!
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"He knows lot about science stuffs, Professor David explains! Turuttu ! "
Lol
It's dave*
@@DvolWOLF no it's chemistry Jesus
I love that too lol I'm always singing along 😂
How tf does that sound like "turuttu" to you ?
you are amazing
what the teacher do in 50 min
you did it in 5 min
I always wondered why it would take them 30 minutes to explain a concept which can be done in 2 minutes.
@@JihadAlAnsari because then they wouldn't have jobs lol
اا والله ^_*
indeed
@@JihadAlAnsari because they are teaching 20+ people who learn in different ways, they also need to go over multiple topics at a time. Imagine you have a 2 minute class and don’t pay attention for one minute (zone out) you’re done for!
Hello guys,
just to help you guys out the equations is missing negative in the calculation. To end up with the Ans: 2.19 J/g °C i thought i would simplify for those that may need it.
Don't forget the metal is losing energy and the water or liquid is gaining energy 'joules' So :- Qmetal/metal DT " -850J /(4.82) (-80.5°C) = 2.190665189.
COOL WELL EXPLAINED VIDEO THOUGH.
hope this helped.
It's my 2nd semester of first-year university chemistry... and of course, Professor Dave saves me once again.
Same here and agreed 🥹
@@yunyung lmao same as well
Then why am I doing this in 10th grade. Not fair
Then why am I doing this in 10th grade. Not fair
@@riruruuu bcaz what that person is doing is a intro chem course, they refresh the basics first then dive into the harder stuff as they progress
At the beginning, it thought I would be really difficult, but you explained it well! I see that you omitted the cancelation of the negative signs of the metal q and the metal Delta temperature, that confused me at first but made me think a little harder (which was good!). Thank you again!
hello sir ! my self rishabh , i am from india. today fortunately i came to your channel. your style of teaching is fantastic it attracts me a lot . thanks for free education. you are making a great effort to make this world Literate wish you all the best. you cover the topics very earlier and effectivily it is very benificial for all
Same bro
I didn't do the comprehension I was to busy jamming to the sick beats
check out the song at the end of any clip in my organic chemistry practice problems series. that's the dopest beat of them all.
Wow you're right I'm adding it to my playlist rn ✌🏾
@@ProfessorDaveExplains Why are you using Celsius and not Kelvin? The equations I saw multply by Kelvin not Celsius. Won't you get a wrong result this way? Please help.
Thanks Professor Dave for doing something in four minuets my professor couldn't do in forty minuets. Explain the material.
I would much prefer you use the equality of heat lost = heat gained. q(water) = -q(metal) Thus you can be consistent in the determination of delta T as final T - initial T. Your video is really nice for an introduction to the concept of calorimetry but may be confusing when instructors discuss exothermic changes which are given a negative q or delta H.
How do I always get suggestions on what I'm currently learning in class!? 😮 Professor Dave is psychic!
This dude is so amazing even the teacher all over the philippines LINKED his vids for me and my class mates to whatch
It was a couple years I haven't learn about different of heat capacity or specific heat. Thanks for explaining us.
The best part is your video is concise and useful . thanks
I know this video was a while ago but if you ever do remakes, putting everything in standard units would be awesome so it's consistent with college courses. Like kg, K, and all that.
The visuals you put in are so helpful, thanks! ;]
so u are a studend of thermodynamics?
Why is he using Celsius and not Kelvin? The equations I saw multply by Kelvin not Celsius. Won't you get a wrong result this way? Please help.
Awesome video hit the nail right on the head
This really helped my understanding of this topic thank you!
Thank you Professor Dave!!!!!
i have long graduated and sometimes this very simple thing is not remembered (we cant remember everything right), so this video is an excellent video for a short revision.
thank you professor Dave, for eplaining me calorimetry in simple words.
I love your content so much but bro you your intro is the funniest thing ever it really made my day
Dave, you are really good.Thank you very much.
I love this man!
Thank you so much, your amazing! ❤️
You are very fantastic prof. Thank you for making this channel
😊😊👍👍👍
Wow, I needed that visualization. 👀👌 This is good stuff.
Liked and subscribed. Thank you professor Dave, this is dope
Very insightful helped me to understand that coffee cup experiment
thank you so much jesus i have a test tomorrow and you came in clutch ❤❤❤❤❤❤❤❤
Thankyou for the video on Heat Capacity, Specific Heat, and Calorimetry.-Alexis Kironde.
Such a wholesome comment written like an email
This is UA-cam you didint have to be that formal take a chill pill😂
sir, will you define heat capacity with some other lab activities??
thank u very much really its clear more about calorimeter
very nice explained sir
lovee the introoo
i already start singing it when i click on ur video
thank you brother, u help alot of fellow studs by ur lecs
GOD BLESS YOU!!
Great videos! Keep it up!
At a village a mother heats 4 liters of water with a paraffin stove from a temperature of 18 °C. She later noticed that 20 g of the paraffin was used up. Calculate the final temperature of the water if the heat value of paraffin is 31 MJ/kg and the specific heat capacity of water is 4187 J/kg. °C.
Τhank you very much for sharing!
I am watching you lectures to revise material which is needed in order to earn my master's degree.
The only thing that I would like to say is that since the volume of the water has two significant figures, the end result should have two significant figures too [2.2 J/(gr*°C)] (3:38).
Apropos, I couldn't find a metal that has this specific heat; could you reveal it to me?
Awesome comprehension question!
very great video! prof dave
Hello prof. , im confused by the concept of this question which is contrast to my understanding, the solution explains that the q of the diamond is equal to the "-" q of the water (q[diamond]= - q[water]. Why did the water absorbed heat and has a negative value?
5. As a purity check for industrial diamonds, a 10.25-carat diamond (1 carat = 0.2000 g) is heated to 74.21 oC and immersed in 26.05 g of water in a calorimeter. The initial temperature of the water is 27.20 oC. If the specific heat of diamond is 0.519 J/g oC, what is the final temperature of the water?
I have another question is
Does material has high heat capacity means to faster speed in change of temperature , in the condition of provide same heat to different material?
Thanks that helped alot
But did you assume that the metal started up at 25.5°C when the question doesn't mention it. I thought that when the starting temperature isn't mentioned we just take the standard which is 25. So my answer was slightly different, s≈1.958J/g°C
Your videos r very useful but can u plz talk about thermal decompostion
lovely explaination
What's the difference between ''heat transfer'' and ''change in temperature''?
That's great explanation
THANK YOU !
THANK YOU FOR THIS!!!
For practical reasons, the change in water temperature is to be recorded in time. When the graphic peaks, that is the temperature change for the given equations. That is because the calorimeter change heat with the environment as well. Your thoughts?
Hello sir.. thanks for this video. Just wanna ask how to measure sp of soluble solids like sugar? pls reply thanks
Nice lecture
3:45 why was the difference in water temperature not subtracted from the temperature of the metal, and why the total temperature was subtracted from the temperature of metal?
Thanks Dave.
Why is 66.5 degrees not a negative change in temperature at 3:05? The temperature of the metal decreases to reach the final temperature, right?
In the problem 4.82g of an unknown metal is heated to 115.0c and then placed in 35L of water at 28.7c,which then heats uptp 34.5c.What is the specific heat of the metal?
For the waterq=(4.186 j/g) (35g)(5.8c)
how or where did you get the 5.8cand for the Metal 850j =s(4.82g)(80.5c)
S=2.19 j/g cwhere or how to get 80.5c as these temperatures are not mentioned in the question and also when i multiply the specific heat and the temperature i dont get 2.19 j/g ci get 4.82*80.5=388.01
Please explain at your earliest convenience as iam in a dark dark place
I love you Professor Dave
I have my examen in 1 hour and I so nervious, thanks for help me
That last q helped me understand that I understood. Tnku
where did he get the 9.25g and 66.2 C in his computation for specific heat of metal?
Please prof, I have a question on the enthalpy as, If the elementary step A to B has a reaction enthalpy of XKJ and the activation energy of the reverse step B to A is YKJ, then the activation energy of the process A to B would be what?
Thank you so much !!
What is the initial value of metal temperature?
Amei a explicação ❤🎉 muito obrigada! O Brasil te assiste!!
Bless this video
Very intelligently explains. Prof Dave is the best
The best explainer❤
thank u so much omg
2:31 Is the specificheat before or after the water absorbs the heat from the rock?
Superb bro!!
Nice lecture sir
shouldn't be the q in computing for the specific heat capacity of metal be negative? Heat was released by the metal isn't it?
My native language is Spanish but I study in Brazil so all my classes are in Portuguese and the only way that I found to understand this topic was theses videos in English hhahahahah, I love your videos
Really? kkkkkkk I'm from Brazil
I am from Bangladesh. Really your lecture help me.
Sir, how specific heat different from conductivity or with other mode of heat transfer....
Specific heat is not a means of heat transfer , it is the characteristic property of every substance and is different for all.
does this mean that specific heat or q=+ve , it is raising temperature by 1 degree
thamks
3:45 Why is the metal's temperature variation 80.5 °C? Shouldn't it be 5.8°C?
Thanks!!
to think this the same dude who be cussin out flat earthers i love this guy frl
Thank you bro 🙏
thank you sir
I need the latent heat and specific heat capacity of "Geraniol"....Can you help me?
I'm confused, how did you calculate the specific heat of an object?
Me too 😢😢😢
Helps alot
Omg. Thank you! Im a chemistry major but this type of problem was so confusing to me. Thanks!
Zeima Rodriguez bruh i’m in 6th grade tryna figure this out😭
Thank you
My physics teacher is ass
You made my day
Hi, umm.. I had a question about the metal and water example... When you were calculating the specific heat of the metal, why did you choose the ΔT to be the difference of temperature between the temperature of the boiling water and temperature of the water on coffee cup?
So the metal starts out in the boiling water, and it ends up in the cup at equilibrium, so those are the two temperatures for the metal!
Thank you
wouldnt q= -850? since delata T =final - initial? ---> (34.5-28.7) ...?
I will do anything to make u my physics teacher....Thanks for these amazing videos !!!!!!! 🤩
He looks like Ranveer Kapoor
thank you sir.l was not able to understand the concept clearly when l was taught at school.this video helped me tremendously....😂😂😂😂😁📣
for the comprehension part don't you have to convert ml --> grams because "m" is for grams in he equation?
nvm
I am from Egypt , Really Thnx 💙
Quick question. How are you supposed to do the equation of water is in milliliters?
If amount of water is given in milliliters, then you have to translate to mass through the density of water. For water, for what it's worth, 1 mL is approximately 1 gram.
That is, unless you have volumetric heat capacity values available to you.
Hi Professor Dave
THANK YOU! Your videos are very helpful with my SAT Chemistry prep.
I have a question tho, how do you get delta T for the second equation of the metal?
the initial temperature of the metal is 115 so you have to use that!
@@ProfessorDaveExplains sir why we are taking the subtraction whether both are differently placed?
Hi@@ProfessorDaveExplains, I also have a question. Why are we subtracting from the initial temp for the delta T (change in temp) and not from the final temp (i.e. 34.5 C - 115 C)?
what is the calibration constant?
i have a question that how we find the specific heat of copper at 300 Kelvin...can u explain this experiment with instrument
by the method shown in this video, measuring the temperature change when the hot metal is put in water
These videos are very helpful. But just one suggestion, put them into an organized playlist of some sort so that people don't have to go around and search for the next topic
buddy all of my tutorials are immaculately organized into playlists! did you even think to check before commenting?
Don't we use -q for released?
For the comprehension question:
In the question itself, you said that the unknown metal was placed in 35mL of water. However, when solving for the water, you wrote 35g. Was that a mistake or was it intentional?
water is 1.0 g/mL!
vry usefull..gd way of teachnggggg
a little lost on the final answer if anyone can help. Why did we subtract the heat of 115 for the metal by the final temperature of the water. I thought we were looking for the specific heat of the metal only
that's the change in temperature for the metal