I think the problem is solved just at the point when it is found that x= ln30/ln4. The rest is unnecessary , a useless dilation to arrive to an impractical form
Listen you guys are geniuses.But I haven't done math in like forty years so I find this interesting period where can I take a online course to run a stuff
yeah... unless the problem specified that your final answer could ONLY contain logs of primes... but even then: x = (ln(2) + ln(3) + ln(5))/(2ln(2)). lol I lost it at the change of base, like... in that case, screw it... x = log_4(30).
That's exactly what I thought ... then use a calculator ... But the 'answer' arrived at is left in logs, so I guess there's instructions like "do not use a calculator, and simplify as far as possible to prime numbers etc" Otherwise it's wandering around quite a bit.
Советский школьник решил бы эту задачу в 3 раза быстрее. Не легче ли сразу было представить логарифм 30, как 2*15, а не разводить эту многоэтажную канитель!
Its teachers like these that make students hate math. Pointless, endless and robotic steps. What math exam paper would have enough time for this solution
From the viewpoint of someone who is not adept at logarithms, I have to accept each step as being sanely conceived. But, each step leads to a sort of insanity leading to a true unreality.
If you were talking an assessment exam, you would not have the time to preform that many LOGS. That’s great when you are a student in the classroom, but in the real world you only have so many minutes to solve 30 and x. So what is quickest way to simplify a math equation like that?
4^x = 30 take the log to base 4 of both sides(because 4 is what is being raised to a power): log_4(4^x) = log_4(30) which gives x = log_4(30) since log_a(b) = log(b)/log(a), x = log(30)/log(4) STOP THERE
I think the problem is solved just at the point when it is found that x= ln30/ln4. The rest is unnecessary , a useless dilation to arrive to an impractical form
exactly...super boring after that finding
Listen you guys are geniuses.But I haven't done math in like forty years so I find this interesting period where can I take a online course to run a stuff
I concur with you!
yeah... unless the problem specified that your final answer could ONLY contain logs of primes... but even then: x = (ln(2) + ln(3) + ln(5))/(2ln(2)).
lol I lost it at the change of base, like... in that case, screw it... x = log_4(30).
100% - I got 2.45 from log30/log4. Not ln but log...
This is easy. Simply divide Monday by Friday then multiply by the month or March.
Νothing interesting, simple application of logarithms
It was interesting. I can’t stop watching it
After x is expressed as log of 30 devided by log 4 to the same base, everything else is pointless
That's exactly what I thought ... then use a calculator ... But the 'answer' arrived at is left in logs, so I guess there's instructions like "do not use a calculator, and simplify as far as possible to prime numbers etc" Otherwise it's wandering around quite a bit.
Советский школьник решил бы эту задачу в 3 раза быстрее. Не легче ли сразу было представить логарифм 30, как 2*15, а не разводить эту многоэтажную канитель!
Everything he did after x=log30/log4, I said "Yeah, but why?" "Yeah, but why?" "Yeah, but why?"
I think you will find he likes logs. Some sort of addiction
@@ruperttristanblythe7512 I liked the change of base thing. I either didn't know or didn't remember that.
Every step after x = log30/log 4 is completely unnecessary.
Not bragging and I'm aware it was intended to be simple but I did this in my head in less than 10 seconds. Nice instruction.
Short way is x= ln30/ln4. But its a cool explanation! Showing all rules which could be used.Good training for my brain :-)
Its teachers like these that make students hate math. Pointless, endless and robotic steps. What math exam paper would have enough time for this solution
Problem is that there is no definition of done for this problem.
Easiest solution would be log 30 base 4, using just definition of log.
x=log 30 base 4=(log3base2+log5b2)/2 ans
log_4(30)=x
the problem should state that x is a real number. if x (or rather z) were complex, then there are infinitely-many solutions.
2.4534 in 2 minutes with a basic calculator. Now to watch the video and see how I should’ve done it
I’m not a math guy but I like my answer better. I feel the “correct” answer is more a re-write of the problem than a solution.
x = 2.45
From the viewpoint of someone who is not adept at logarithms, I have to accept each step as being sanely conceived.
But, each step leads to a sort of insanity leading to a true unreality.
2,455
Solution presented is nicer than ln(30)/ln(4) ?
no
If you were talking an assessment exam, you would not have the time to preform that many LOGS.
That’s great when you are a student in the classroom, but in the real world you only have so many
minutes to solve 30 and x. So what is quickest way to simplify a math equation like that?
4^x = 30
take the log to base 4 of both sides(because 4 is what is being raised to a power): log_4(4^x) = log_4(30)
which gives x = log_4(30)
since log_a(b) = log(b)/log(a),
x = log(30)/log(4) STOP THERE
This is so dumb
Directly
X=Log4(30) [Log 30 to base 4]
And this is the simplest form, because it has one term one Log .
Log b / log a is not log b/a continúe learning log
4×4×1.875=30
30=4제곱 2.1875?
👍
boring so what is the numb er?
The number is log. Hope that helps.
Log 30/log 4?
Two and a bit?
x=log30/log4
✌️
Хорошими делами прославиться нельзя , а вот такими - 22 тыс.за 6 дней можно
Дерзайте, покажите, что сможете лучше!
22 thousand logs?
@@ruperttristanblythe7512 Да уж , с этим не поспоришь )
Nice one
In a moment, there will be a "nice olympiad/entrance problem" of 4x = 8. What a kindergarten is this?
This is an olympiad problem in Germany? Tomorrow 2+2=x will be an Olympic problem...
In Germany they like their logs
Just use a calculator, it is this sort of video that puts people off maths, of what practical use is this?
БАРАН ЧТО ЛИ
I beg your pardon?
太逗了，比中國教師還可怕，還能再囉嗦點嗎😅😅😅