Відео

I divided by 2, found the prime factorization of 45, and then used properties of logarithms to get the answer.

Não é por nada que a galera que resolve estudar cálculos fica tudo meio birolaybe.

K=5,,(K)^³ --(k)^2=100

2³x=50, x= 50/3 log2

I used to be able to calculate this when I was a student at UC. I was very good. Now, over 12 years later. Nope! If you don't go to the gym, the muscles shrink. I never encountered a reason to calculate logs. Physics a few times. Trig even more. Wet noodle.

(k+1)^6=64 |k+1|=2 k1=1 k2=-3

x=ln9(90)=2.0479516371 9^2.0479516371=90

8^x+8^x=100 8^x=50 x=log8(50) x=1.8812853966 (I guess we don't need more digits). 2*8^1.8812853966=100.000000001751951 (this should be accurate enough).

I hope this video is supposed to be a joke. It is a one step answer: (X/3)^6 = 4^6 X^6=(4x3)^6 X^6=12^6 X=12. I'm still hoping this is a joke

Lo hiceeee

x=log30/log3=(log10+log3)/log3≈(1+0,48)/0,48≈37/12≈3+(1/12). Absolute error is about 1/80.

x=(log100-log2)/log8≈(2-0,3)/0,9≈17/9. Absolute error is about 0,0076.

x=log 90 x=1+log 10 the base of the log is 9

Amazing you explain well my fellow Mathematician ❤

Watching and learning ❤❤

What if we apply ln instead of log, from the beginning? The final result will be the same?

x^4-6x^3+9x^2-4x=0 , x(x^3-6x^2+9x-4)=0 , x(x-4)(x^2-2x+1)=0 , solu , x= 0 , 4 , / x^2-2x+1=0 , x= (2+/-V(4-4))/2 , x= 1 , not a solu , / 1 -4 -2 8 1 -4

x log3=log30 x=log(3×10)/log3 x=(log3+log10)/log3 x=1+log3(10)

X is +/- 12. OK 😂😂

X&y both equal to 8& minus 9

38

In south korea. This is 7grade (= middle school 1gread) easy calcuration.

Aha X = ?????

Why the crap did you separate 5 and 2? Just keep them at 10!!! Log 10 equals 1!!! That leaves you 1+1/log 3

A

He did it long for to have many comments :)

(X/3)^6=4^6 X=±12 X=±6±6Sqrt[3]i It’s in my head.

Good, very good

X=12

9^x+9^x=144 x=Log[9,8]+1=1+(3/2)Log[3,2] It’s in my head.

Live simple life brother... don't make it complex unnecessarily... 😂

Trying to figure out how: (a+b)^2 = a^2 + b^2 + 2ab. ???

Whhhhat?) √2+√x=2. √x=2-√2. X=4-4√2+2. X=6-4√2

1:45 x≠y ??? 😳 x=y => x²-(x)=73; x²-x-73=0 => => x=(1±vʼ293)/2≈(1±17.12)/2 (x,y)≈( 9.06, 9.06),(-8.06,-8.06) 😁 1:55 y=-x-1 => x²-(-x-1)=73 x²+x-72=0 => (x-8)(x+9)=0 => => x1=8; x2=-9 => y1=-8-1=-9 y2=-(-9)-1=8 => (x,y)=( 8,-9),(-9, 8) 😁

√2+√x=2 √x=2-√2 Square both side (√x)^2=(2-√2)^2 Solve it X=4+2-4√2 =6-4√2

-(2×2)=-4

x=log72/log9=(log9+log8)/log9≈(0,95+0,9)/0,95≈37/19≈1,947. Absolute error is about 0,001.

A resposta é x=5

In the lack of brackets, the order of arithmetic operations should be + , -, * and then /. I think the answer would be 0.

You think we are stupid?. You gave us the answer as ??. What else do you want 😢

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Why to apply log??

X = 2

(X+5)^6=7^6 X+5=7 X=7-5=2

38

x1=2; x2= -12

x=(log20-log3)/log5≈(1,3-0,48)/0,7≈1,1714. Absolute error is about 0,0073.

x=log20/log4≈13/6. Absolute error is about 0,0057.

x≈sqrt10