your videos helps a lot during university exam. Its a quick review of a chapter or a topic. very well explained and very simplified to understand. Thank you, we appreciate your lectures.
In the homework question we can clearly see that it is a bounded lattice because the least element = a and greatest element = e. Now complement of b is c as well as d because LUB(b,c) = e and GLB(b,c) = a. And LUB(b,d) = e and GLB(b,d) = a. Similarly complement of d is b as well as c. And complement of c also exists. Complement of a is e and complement of e is a. We can see that complement of every element exist. Therefore it is a complemented lattice.
Answer to H.W. 11:30 GE = e and LE = a so Bounded Lattice. Comp(GE) = LE and Comp(LE) = GE => Comp(a) = e and Comp(e) = a Also, Comp(b) = d then Comp(d) = b Also, Comp(c) = e So, Complement of every elements exists. Therefore, given Hasse Diagram is Complemented Lattice.
B already has a complement d and a already has a complement e so why do you wanna check b and a since the rule every element has atleast one complement
Sir if we get to know for a single element that there exists no complement can we conclude it by explaining for a single element itself or should we show all the other possibilities.
Why LUB and GLB of "b" and "e" does not exist...? As for GLB we can reach till "a" from both "b" and "e" (transitively) as "a" is related to "b" and "b" is related to "e" that means in the relation set there must be a pair of (a,e) but as drawing a hasse diagram all transitive edges are removed so it is looking as if "e" is not related to "a" but it is related....so "a" should be a lower bound of "e"....right....? Similarly for LUB in the case of "g".....
Homework Problem 11:30
a complemented lattice as every element has a complement
your videos helps a lot during university exam. Its a quick review of a chapter or a topic. very well explained and very simplified to understand. Thank you, we appreciate your lectures.
In the homework question we can clearly see that it is a bounded lattice because the least element = a and greatest element = e.
Now complement of b is c as well as d because LUB(b,c) = e and GLB(b,c) = a. And LUB(b,d) = e and GLB(b,d) = a.
Similarly complement of d is b as well as c. And complement of c also exists.
Complement of a is e and complement of e is a.
We can see that complement of every element exist.
Therefore it is a complemented lattice.
Good Luck for 2022 Neso Team. Keep on making such interactive videos. Thanks for the amazing work.
bhai har jahag hai?
Answer to H.W. 11:30
GE = e and LE = a so Bounded Lattice.
Comp(GE) = LE and Comp(LE) = GE => Comp(a) = e and Comp(e) = a
Also, Comp(b) = d then Comp(d) = b
Also, Comp(c) = e
So, Complement of every elements exists. Therefore, given Hasse Diagram is Complemented Lattice.
Home work problem------->It is a complemented lattice because every element has a complement
Whats about the least upper bound of a and b which is b hence it's not complimented laatice ??
@@kirtirawat4634least UB(b,a) is c where both are meeting
B already has a complement d and a already has a complement e so why do you wanna check b and a since the rule every element has atleast one complement
Your videos really helped clear my concepts. Thank you.
You have explained the logic behind these relationship.
THANK YOU A LOT OF CAUSE TOMMORROW S MY EXAM AND YOUR VIDEO HAS CLEAR MY EVERY DOBUT THANKS A LOT SIR
Yes it is a bounded and complemented lattice 🫶
9:40 goosebumps😮💨🥶
Thanks for the video. It would be helpful to include why complemented lattices are useful in the video.
Outstanding sir...
Thank you 😃
Sir if we get to know for a single element that there exists no complement can we conclude it by explaining for a single element itself or should we show all the other possibilities.
Homework question. The given lattice is a bounded lattice and also a complemented lattice.
Thank you Sir
But What About E? Gave me such a good laugh lol thanks
Yes, it is a bounded lattice as well as it is a complemented lattice.
Answer - it is bounded as well as complemented lattice
yes last lattice is boundend becase there is greatest element and least element, and is complemented lattice because c is complement of b and d
Yrr itne ache lecture me kitne Kam views ate he, koi padhta likhta ni he kya 🥲
Teri tarah ni haina sb... Pdaku
yes its a complimented lttice mere exam mein aaya tha ye question
11:29 is true
last questions have complemented lattice
Home question is complemented lattice
Why LUB and GLB of "b" and "e" does not exist...?
As for GLB we can reach till "a" from both "b" and "e" (transitively) as "a" is related to "b" and "b" is related to "e" that means in the relation set there must be a pair of (a,e) but as drawing a hasse diagram all transitive edges are removed so it is looking as if "e" is not related to "a" but it is related....so "a" should be a lower bound of "e"....right....?
Similarly for LUB in the case of "g".....
this hasse diagram is valid. aRc and cRe so automatically aRe
@@sandeepmukherjee8927 so that means GLB and LUB of (a,e) should exist..... Right?
@@te_b_52_siddeshpatankar14 yes obviously and join of a and e will be e and meet of a and e will be a
It is complemented lattice
ANSWER OF THE HOMEWORK IS IT IS COMPLEMENT LATTICE
Kis kis ka kal exam hai
+1