Lattice

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  • Опубліковано 27 сер 2024
  • Discrete Mathematics: Lattice
    Topics discussed:
    1) The definition of Lattice.
    2) Identifying if the given Hasse Diagram is a Lattice.
    3) Identifying if the given Poset is a Lattice.
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    Music:
    Axol x Alex Skrindo - You [NCS Release]
    #DiscreteMathematicsByNeso #DiscreteMaths #PartialOrdering #HasseDiagram

КОМЕНТАРІ • 85

  • @_PAYALGAIKWAD
    @_PAYALGAIKWAD 2 роки тому +54

    all videos are arranged so well in a proper sequence

  • @trusttheprocess4775
    @trusttheprocess4775 2 роки тому +21

    Fantastic videos. These videos are alone going to help me pass maths this semester.

  • @nins1709
    @nins1709 Рік тому +5

    Thank you so much. Your one lecture clears all my doubts about the lattice topic

  • @benalbritton
    @benalbritton Рік тому +25

    FYI, you don't call the symbol for the empty set "phi". Phi is a greek letter that looks a little similar to the symbol for the empty set, but mathematicians are not using the greek letter phi in this case, it is just it's own symbol that denotes the empty set.

    • @AkamiChannel
      @AkamiChannel 4 місяці тому

      Yeah that was surprising for such a well-presented and informative video to make this error

  • @barlog6679
    @barlog6679 2 роки тому +64

    wouldn't b GLB(f,g) = e?

    • @agnidebmukherjee9756
      @agnidebmukherjee9756 2 роки тому +3

      Yes true..

    • @agnidebmukherjee9756
      @agnidebmukherjee9756 2 роки тому +2

      @@adityanprakash1281 not at all

    • @csbytes137
      @csbytes137 2 роки тому +1

      Same doubt

    • @barlog6679
      @barlog6679 2 роки тому +46

      i figured it out, the elements that can be GLB in (f,g) are e and b. Since you cannnot determine whether e is greater than b or b is greater than e due to the lack of relationship between e and b, there is no GLB. The same logic applies to determine the GLB and LUB of other pair of elements.

    • @its_ayush7286
      @its_ayush7286 Рік тому +3

      @@barlog6679 thank you for pointing out my same question and also for giving the answer of it. That is something that i didn't know.

  • @madapanameena1320
    @madapanameena1320 6 місяців тому +2

    From figure (a)
    Consider the incomparable pair (d,g)
    GLB(d,g)=f
    LUB(d,g)=¢( null set)
    So, this is not lattice.
    I have doubt .. please clarify that.

  • @pranavnyavanandi9710
    @pranavnyavanandi9710 2 роки тому +4

    Please list the related playlist in the video description as well, it makes it much easier to navigate.

  • @marcusmors8485
    @marcusmors8485 4 місяці тому

    Thank you, it was easy to understand and you set the previous knowledge requirements from the start.

  • @ambikas4905
    @ambikas4905 2 роки тому +4

    Well explained,with more examples,there is no doubt n understand

  • @ankitpanwar5032
    @ankitpanwar5032 Рік тому +3

    Thank you❤❤ neso academy, I grateful to for my sessional exams

  • @bj_ets8010
    @bj_ets8010 2 роки тому +5

    You are a life saviour sir🔥💯💥

  • @kashmirking2446
    @kashmirking2446 2 роки тому +3

    Thank u so much sir.....all videos are in proper sequences

  • @y.8901
    @y.8901 Рік тому +4

    Hello, at 7:25 can we say that the lower bounds of (f,g) are b,e,c,a but since b and e are not comparable -> No upper bound ?

    • @doesnotexist8873
      @doesnotexist8873 Рік тому

      yes

    • @rajeshprajapati6662
      @rajeshprajapati6662 11 місяців тому

      Upper bound of (f,g) is h. There is no lower bound for (f,g). You should have written "No Lower Bound".

    • @prithwihegde349
      @prithwihegde349 4 місяці тому

      ​@@rajeshprajapati6662hey y e can't be considered as GLB?
      Please could you explain...

  • @chiragmehta2955
    @chiragmehta2955 Рік тому

    sir your voice so soothing ..after hearing that it makes maths a very easy subject. thank u for ur hardwork.

  • @yeongwooh4921
    @yeongwooh4921 Рік тому +4

    GLB(f,g) for all pair isn't defined, thus the set is empty. since the two preceding lower bounds are incomparable, we can't define greatest lower bound.

    • @wrath2801
      @wrath2801 10 місяців тому

      bhai tu IIT ka hai?

  • @jordynbell02
    @jordynbell02 2 роки тому +3

    This video is absolutely amazing!

  • @_PAYALGAIKWAD
    @_PAYALGAIKWAD 2 роки тому +5

    thanks a lot sir..Your videos are so easy to understand and organised...

  • @praveenkumarchettiyar2695
    @praveenkumarchettiyar2695 18 днів тому +1

    Thankyou sir you rescued me a day before exam 😊😅

  • @DuongNguyen-en1pi
    @DuongNguyen-en1pi 2 роки тому +8

    6:12, example 2 (a), what is the GLB and LUB of pair (d and g)?

    • @enes5345
      @enes5345 2 роки тому +2

      GLB d and LUB g

    • @marah8158
      @marah8158 7 місяців тому

      @@enes5345
      couldn't be like this?
      GLB is f
      LUB is ø
      how GLB is d when they first meet in f?

  • @zeusbgmi6476
    @zeusbgmi6476 Рік тому +1

    This is somewhere excellence is found!

  • @mahendrakergaurav5867
    @mahendrakergaurav5867 Рік тому +2

    thanks man,apppreciate your work

  • @teneplays
    @teneplays Рік тому +2

    8:45 example 3 was the same as in my notebook

  • @user-vk9vx8uk2p
    @user-vk9vx8uk2p 10 місяців тому

    this guy is an amazing teacher omg

  • @likithgannarapu8454
    @likithgannarapu8454 2 роки тому +3

    at 8:15 in example(c) why didn't you consider (b,c) as incomparable????

    • @rajeshprajapati6662
      @rajeshprajapati6662 11 місяців тому

      You can consider it and you will find that unrelated pair (b,c) has GLB = a and LUB = g.

  • @egehanyildiz
    @egehanyildiz Рік тому +1

    sir in example (b) isnt GLB of f and g is a? By following the path downwards we can find a lowerbound

    • @rajeshprajapati6662
      @rajeshprajapati6662 11 місяців тому +2

      Lower bound of (f,g) - abce
      Let's check for GLB :
      a - All elements of LB related to a ? No [Using Hasse Diagram]
      b - All elements of LB related to b ? No [Using Hasse Diagram]
      c - All elements of LB related to c ? Obviously No [Using Hasse Diagram]
      e - All elements of LB related to e ? Obviously No [Using Hasse Diagram]
      So, GLB = Phi

    • @anushiya4453
      @anushiya4453 7 місяців тому

      thanks man!@@rajeshprajapati6662

  • @Akshay_pratap_singh_007
    @Akshay_pratap_singh_007 Рік тому +1

    Very well explanation Sir !!

  • @saiyedasiddika3974
    @saiyedasiddika3974 2 роки тому +1

    It’s really helpful

  • @satyamtiwari331
    @satyamtiwari331 5 місяців тому

    fantastic explanation

  • @arunsuresh8547
    @arunsuresh8547 6 місяців тому

    In fig (c) why don't you consider f,e and d,c as incomparable pairs ?

  • @osamansr5281
    @osamansr5281 Рік тому +1

    what does the "rank" of a lattice mean? what's a "rank-1" lattice?

  • @isai5813
    @isai5813 2 роки тому +5

    Please add python and Dynamic programming courses too

  • @suhankrishna4567
    @suhankrishna4567 4 місяці тому

    i will pass because of you. god bless you!

  • @bbmathematics224
    @bbmathematics224 5 місяців тому

    Excellent method..❤

  • @sidrahwaris7885
    @sidrahwaris7885 29 днів тому

    thank u so muchhhh very helpfullll!!!!!!!

  • @engineerguruji2
    @engineerguruji2 2 роки тому +1

    Thanks so much

  • @brainexercise1234
    @brainexercise1234 11 місяців тому

    Nice explanation

  • @pahadiraishgamer1777
    @pahadiraishgamer1777 Рік тому +1

    Very helpfull

  • @Bbdu75yg
    @Bbdu75yg Рік тому +1

    Amazing !🎉🎉🎉🎉

  • @bhaktikhokad7113
    @bhaktikhokad7113 Рік тому

    nice expalined properly

  • @kasiiragavarapu673
    @kasiiragavarapu673 Рік тому

    At 6:17 why don't we consider (g, d) to check either they have glb and lup

    • @doesnotexist8873
      @doesnotexist8873 Рік тому +2

      because d is related to g through transitive property

  • @engineerguruji2
    @engineerguruji2 2 роки тому +2

    Good morning every one

  • @shivanikj3047
    @shivanikj3047 2 роки тому

    Thank you 😃

  • @Kuldeepsingh.
    @Kuldeepsingh. 2 роки тому

    great video sir

  • @leonthethird7494
    @leonthethird7494 Рік тому

    You're a legend

  • @lloydmoore6507
    @lloydmoore6507 Рік тому

    Doesn't 3 also divide 12?

  • @aaravjayalwal3416
    @aaravjayalwal3416 Рік тому +1

    Way better than nptel

  • @nehakhanolkar3861
    @nehakhanolkar3861 5 місяців тому

    Can someone please explain what do we mean by 'incomparable elements '.

  • @parmeshwariswami3530
    @parmeshwariswami3530 6 місяців тому

    Sir ji direct product of lattice explain videos

  • @amruta2114
    @amruta2114 Рік тому

    Thku

  • @AnushkaSingh-sl3zn
    @AnushkaSingh-sl3zn 5 місяців тому

    b,c ???

  • @shankarpubg9413
    @shankarpubg9413 8 місяців тому

    Wow 😲

  • @sabrinahhewitt119
    @sabrinahhewitt119 7 місяців тому

    Love🎉

  • @noelomidze2079
    @noelomidze2079 Рік тому

    კიუელები გამოჩნდით xd

  • @08_it_aditkumar15
    @08_it_aditkumar15 Рік тому +1

    Wtf?

  • @arunsuresh8547
    @arunsuresh8547 6 місяців тому

    In fig (c) why don't you consider f,e and d,c as incomparable pairs ?