Wouldn't the variable "a" not be a constant? as the dq is in the y direction as is "a"? You are a great professor, I passed my PHY 1 exam because of the URP!
The variable "a" is constant. It is the radius of the thin ring which has the same value regardless of the location of "dq". I hope that helps, thanks for the kudos, and congrats on passing your PHY 1 exam!
I have a question: will the negative charge move around the ring 💍 passing through the center side, or will it move up and down the horizontal position of the ring?
When teaching my students, would it be sufficient if they understand why we can approximate the ring as a point charge Q in the middle of the ring without the integration?
Mr. P, why does the negative point charge oscillate in simple harmonic motion when the rod is positive? Instead, I assume it should be attracted to it and clung to the rod completely.
The net force in the y-direction on the negative point charge is zero when it is along the horizontal axis of the ring. Perhaps you missed that it's a ring and not a rod?
I watched this video the day before a test and the FRQ was exactly the same as what this video covered. Thanks Flipping Physics!
You are a legend. Just in case you forgot!
About to start my Physics C Mechanics class tomorrow!
Amazing video once again
Thanks for the love!
Wouldn't the variable "a" not be a constant? as the dq is in the y direction as is "a"?
You are a great professor, I passed my PHY 1 exam because of the URP!
The variable "a" is constant. It is the radius of the thin ring which has the same value regardless of the location of "dq". I hope that helps, thanks for the kudos, and congrats on passing your PHY 1 exam!
I have a question: will the negative charge move around the ring 💍 passing through the center side, or will it move up and down the horizontal position of the ring?
When teaching my students, would it be sufficient if they understand why we can approximate the ring as a point charge Q in the middle of the ring without the integration?
Man I thought I was out of the woods from mechanics last year...
You are not
Mr. P, why does the negative point charge oscillate in simple harmonic motion when the rod is positive? Instead, I assume it should be attracted to it and clung to the rod completely.
The net force in the y-direction on the negative point charge is zero when it is along the horizontal axis of the ring. Perhaps you missed that it's a ring and not a rod?
@@FlippingPhysics Even if we assume it is a ring, there should be a simple attraction, but still why is it in a SHM?
Jingle
Jangle