Professors who use Pearson Publisher have the option to disable his videos in the homework. My instructor removed all his vids except for like two of them but I am in an accelerated summer course at a community college. I googled and found all Dr. Anderson vids on youtube. Thank the physics lords!!! I made an A in my uni physics I course, while employed full time. Hoping to get the same results for physics level II. This man has single handedly helped me pass.
I wished I had you as teacher in my early schoolday's perhaps then I could have a positive result. You'r a excellent teacher keep doing that good work, thanks and kind regards
Thank you, professor! Your videos are amazing:) How do we know that the integral of (x^2+y^2)^-3/2 = 1/y^2? I understood y is a constant, but It’s still confusing. How did you get the 1/y^2
You take the improper integral of 1/(x^2+y^2)^3/2 from 0 to infinity, plugging in infinity we see that the value of the anti derivative there “vanishes” and we are just left with 1/y^2
asem shaat, In this special case, yes. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
you don't really need to solve it. It's in the "table of integrals" section of your textbook just look it up. unless your professor is making you solve it by hand... then i'm so sorry for you
Its mainly because E0 can change based on the material between the line of charge and the point, it represents the permittivity of free space but if there was something inbetween the line of charge and the point, E0 could be different.
Professors who use Pearson Publisher have the option to disable his videos in the homework. My instructor removed all his vids except for like two of them but I am in an accelerated summer course at a community college. I googled and found all Dr. Anderson vids on youtube. Thank the physics lords!!! I made an A in my uni physics I course, while employed full time. Hoping to get the same results for physics level II. This man has single handedly helped me pass.
Great video, I don’t know why people are not showing you more appreciation. Keep up the good work. Thank you,
this is the best explanation straight to the point. Thank you!
I wished I had you as teacher in my early schoolday's perhaps then I could have a positive result.
You'r a excellent teacher keep doing that good work, thanks and kind regards
Honestly, it's soo good.
Why his videos are so underrated.
God Bless you.
Underrated? I've got millions of views. Of course, most of those are from my mom, but still.
Cheers,
Dr. A
Great Explanation👍
Amazing!
so good
you're a life saver
I do no know why you don't have a lot of views your explanation is awesome
I am from india.
I like the lesson .
Thank you 😁 sir
Thank you so much ,professor your lecture just make me love physics
Awesome, love to hear that.
Cheers,
Dr. A
Man you saved my life
just wow!!
Thank you, professor! Your videos are amazing:)
How do we know that the integral of (x^2+y^2)^-3/2 = 1/y^2? I understood y is a constant, but It’s still confusing. How did you get the 1/y^2
You take the improper integral of 1/(x^2+y^2)^3/2 from 0 to infinity, plugging in infinity we see that the value of the anti derivative there “vanishes” and we are just left with 1/y^2
the (fake) end was literally wonderful :D
thank you sir
#DUNN
do this integral.... oh you can look it up in the book
I have a question.
Is Ey = Enet ?
asem shaat,
In this special case, yes.
Thanks for the comment, and keep up with the physics!
You might also like my new website: www.universityphysics.education
Cheers,
Dr. A
How you know it an infinite line chart do they have to tell you in the problem??
Yes, the problem should specify.
Cheers,
Dr. A
I CAME HERE ONLY FOR THE INTEGRAL TO BE RESOLVED!!! WHY Y'ALL ASSUME I CAN DO IT???
you don't really need to solve it. It's in the "table of integrals" section of your textbook just look it up. unless your professor is making you solve it by hand... then i'm so sorry for you
dat fake out at the end =/
Why don't you write k for 1/4pieE0, aren't they equivanlent?
They're literally the same, k is a name for 1/4piepsilon0
Its mainly because E0 can change based on the material between the line of charge and the point, it represents the permittivity of free space but if there was something inbetween the line of charge and the point, E0 could be different.
First one to dislike
you are the first and the last.
@@gokublack9080 thanks 😊
@@harshbardhan8589 why though?