Hey, I really appreciate your videos, thank you so much! I was just wondering though, I watched the video of you doing it, and, do you know why I might get results that give me a R/L of 20.4? I used a 0.37 mm wire and increased the pd by 0.5 V each time, keeping the current at around 0.25 A.
I had a question Sir.If the resistance is too low, how come the wire will heat up as we know if resistance decreases,temp also decreases.Did u mean as resistance decreases,current increases which heats up the wire.But if so the temperature will increase anyway no matter how much the resistance is.And let's say the resistance decreases,shouldn't the resistivity decrease as well as they are proportional? Hope you will reply!!
for the uncertainty graph, mo error bars are really small so I usually make them but then say that as the error bars are small, the uncertainty of the gradient is small. does that make sense?
When you multiply two variables that have uncertainty, the new uncertainty is the sum of the uncertainties of each of the variables. So when we square the diameter value our new uncertainty is double the uncertainty we found when measuring the diameter of the wire.
So what of power dissipated changes through out experiment, it changes along with Length, R changes along with length so they compensate for each other so how does that affect resistivity.
thx for the vid. really helps a lot. Just a question though. around 2:45 why does the power being dissipated not being constant mean that the resistivity won't be constant? i don't see the relationship between power and resistivity. unless you meant that as the current fluctuates so would the temperature, hence the resistivity would not be constant.
My understanding is that as the power dissipation due to heating increases, the temperature of the wire will increase. this causes the current in the wire to decrease, meaning the resistance of the wire will increase causing the resistivity of the wire to increase as the resistivity is proportional to the resistance since the length and cross sectional area remain constant. but I'm not sure, Electricity in textbooks is filled with half explained concepts its really frustrating
Wait doesn't if resistant goes up as well doesn't the wire heat up? And why would temperature increasing cause an Increase in resistivity and not a decrease?
bit late but yes an increase in temperature does cause an increase in resistance. and from the equation we see resistivity is proportional to resistance. so if temperature increases so should resistivity.
Watch me do it for reals: ua-cam.com/video/2JvatsWcGmA/v-deo.html
You should do a second channel where you go through stuff in even more detail...call it “Science Trousers” because they’re like shorts but longer :)
Haha...
Trousers
very funny
He should actually do this
Thanks so much, you really saved me from physics a level 👍🏻👍🏻
Thanks for making these! I'm definitely getting an A* now, thanks to you.
Did you get the A*?
Did you get the A*?
Did you get the A*?
did you get the A*?
did you get the A*?
wow I can't express my gratitude in words!
Amin toofani expressed it through his guitar
Please make an astrophysics series!! Super useful
To change resistance you could also use a Rheostat.
No, we do say "resistance" instead of "reesistance"
But if you avoid arrest, don't we say you are "reesisting arrest"?
@@ScienceShorts Good point
Shrug - I think it's just up to the person 😊
9702 syllables right
Hey, I really appreciate your videos, thank you so much!
I was just wondering though, I watched the video of you doing it, and, do you know why I might get results that give me a R/L of 20.4?
I used a 0.37 mm wire and increased the pd by 0.5 V each time, keeping the current at around 0.25 A.
I had a question Sir.If the resistance is too low, how come the wire will heat up as we know if resistance decreases,temp also decreases.Did u mean as resistance decreases,current increases which heats up the wire.But if so the temperature will increase anyway no matter how much the resistance is.And let's say the resistance decreases,shouldn't the resistivity decrease as well as they are proportional? Hope you will reply!!
Why does P =I^2R changing mean that the resistivity will also change?
p= heat lost. more heat lost= resistivity changes. something like that. lmao 1 year ago u prob dont even need this
for the uncertainty graph, mo error bars are really small so I usually make them but then say that as the error bars are small, the uncertainty of the gradient is small. does that make sense?
If festivity can change with temperature, at what temperature is resistivity of a wire measured as a standard?
Hiya Science Shorts, do you mind if you cover superconductors? Or have you already in another video?
please can you make more GCSE revision for all three sciences
On my to-do list :)
@@ScienceShorts thanks so much
Why do you time uncertainty of diameter of wire by 2, Thank you for the this content really helps
As area is diameter squared, the unc in A is double that of d.
When you multiply two variables that have uncertainty, the new uncertainty is the sum of the uncertainties of each of the variables. So when we square the diameter value our new uncertainty is double the uncertainty we found when measuring the diameter of the wire.
So what of power dissipated changes through out experiment, it changes along with Length, R changes along with length so they compensate for each other so how does that affect resistivity.
thx for the vid. really helps a lot. Just a question though. around 2:45 why does the power being dissipated not being constant mean that the resistivity won't be constant? i don't see the relationship between power and resistivity. unless you meant that as the current fluctuates so would the temperature, hence the resistivity would not be constant.
I have the same question
My understanding is that as the power dissipation due to heating increases, the temperature of the wire will increase. this causes the current in the wire to decrease, meaning the resistance of the wire will increase causing the resistivity of the wire to increase as the resistivity is proportional to the resistance since the length and cross sectional area remain constant. but I'm not sure, Electricity in textbooks is filled with half explained concepts its really frustrating
How come a wire heat up if it has low resistance?!?
The current causes heating, low resistance usually means high current
Your handwriting is so beautiful!
Lol! You're either being sarky, or you're very much in the minority! 😂
@@ScienceShorts Noooo I mean your handwriting is great.. sincerely 😹
Thanks!
(It really isn't though) 😂
How do you find the percentage uncertainty?
Thanks so muchh
Wait doesn't if resistant goes up as well doesn't the wire heat up? And why would temperature increasing cause an Increase in resistivity and not a decrease?
bit late but yes an increase in temperature does cause an increase in resistance. and from the equation we see resistivity is proportional to resistance. so if temperature increases so should resistivity.
can you pls make a video on electronics and operational amplifier
Can you please make a video on capillary rise of liquid due to surface tension ...??
Will you do kahoots this year?
Lol, noooo - it only takes one joker to ruin it with bots.
@@ScienceShorts Damn, shame I was just doing GCSE last year! Anyway, cheers for the reply!
hey, can you please release videos for op-amps and communication systems??? I love your videos so much
Nayana Das he's already done that
What was row
Legend
Can we plz have a video on transport equation? It will be really appreciated!
Don't spam, or you will be banned.
@@ScienceShorts what do you mean?
Real electricity doesn't behave as physics teachers say it does.
"I am very clever"
Beasty
Only in Ohio. 🥶🤯💀
If you improved handwriting it would help a lot, some words were hard to read
but you can listen to what he's saying right? what he speaks and writes is the same