Finding g from freefall - Required Practical - A-level Physics

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  • Опубліковано 8 січ 2025

КОМЕНТАРІ • 31

  • @ScienceShorts
    @ScienceShorts  6 років тому +3

    Watch me do it for reals: ua-cam.com/video/ri8YdBuNpsE/v-deo.html

  • @EdUnleashed1
    @EdUnleashed1 6 років тому +6

    Just the experiment I needed, thanks!

  • @azm1851
    @azm1851 5 років тому +4

    Such a great teacher! Thank god you exist !

  • @joshvir262
    @joshvir262 6 років тому +4

    Loving the videos

  • @michaelhunt2222
    @michaelhunt2222 6 років тому +4

    This is very useful thank you!

  • @boss4078
    @boss4078 4 роки тому +7

    Hey can someone explain to me this percentage uncertainty and why it is e.g. half the range. (I don't get it). The % un in V. (I don't get).

    • @sandunigunawardena5570
      @sandunigunawardena5570 4 роки тому +8

      For a single reading Uncertainty is ( precision ÷ 2 )
      If we take multiple readings, Absolute Uncertainty = (Range ÷ 2)
      Percentage uncertainty = ( [absolute uncertainty ÷ avarage reading] × 100%] )
      Percentage difference = ( [difference between the standard value and experimental value] ÷ standard value × 100% )

    • @sandunigunawardena5570
      @sandunigunawardena5570 4 роки тому +2

      Speacil case
      When using a metre rule to record the uncertainty of the reading, there is an uncertainty of the reading at both ends if the object. So the total uncertainty of the reading is the addition of uncertainties at the 2 ends.
      Uncertainty of metre rule = 0.5 + 0.5 = (plus or minus) 1mm

    • @sandunigunawardena5570
      @sandunigunawardena5570 4 роки тому +2

      Hope this will help you :)

    • @beatek3912
      @beatek3912 2 роки тому

      @@sandunigunawardena5570 the special case you mentioned is called a zero error. may be worth mentioning that every apparatus the you need to manually "match" the zero to your measurement contains a 0 error

  • @st.angelone018
    @st.angelone018 3 роки тому +3

    You crazy bro

    • @ScienceShorts
      @ScienceShorts  3 роки тому +3

      I am?!

    • @st.angelone018
      @st.angelone018 3 роки тому +2

      @@ScienceShorts haha 😂😂 in a good way btw. Much love from Spain 🔥

  • @uniqueunonymous1055
    @uniqueunonymous1055 6 років тому +2

    ayye bro i want aan a in a level physics cie .plz tell me what to you dont have full course for cie

  • @spirosgrivas7848
    @spirosgrivas7848 6 років тому +1

    Great! Thank you!

  • @the_hasnat
    @the_hasnat 4 роки тому +1

    why not just use a ball bearing?

  • @naheemahakinwale8403
    @naheemahakinwale8403 5 років тому +5

    Why is uncertainty 1/2 the length of the card? So what if we took the top as the reference point?

    • @zainismail7703
      @zainismail7703 3 роки тому

      So you got thr answer yet?

    • @benasbarciauskas3322
      @benasbarciauskas3322 3 роки тому

      @@zainismail7703 its's because he's measuring the middle of the card as the card still accelerates as it's falling making it a happy medium to take a measurement from (therefore inducing uncertainty)

    • @zainismail7703
      @zainismail7703 3 роки тому

      @@benasbarciauskas3322 tests finished last week but thanks.

    • @benasbarciauskas3322
      @benasbarciauskas3322 3 роки тому

      @Zain Ismail did it come up?

  • @Username-ww2cd
    @Username-ww2cd 4 роки тому +1

    Why is the uncertainty of v² double that of v instead of it squared?

    • @Sama-eq8dp
      @Sama-eq8dp 4 роки тому +1

      you always times the uncertainty by the power being raised. So t^2 will have an uncertainty *2, length ^3 (volume) will have uncertainty*3.

    • @Username-ww2cd
      @Username-ww2cd 4 роки тому +1

      Sama Thank you!

  • @jamesrobbins1296
    @jamesrobbins1296 5 років тому +5

    Smart gang where u at?

  • @gateau3144
    @gateau3144 3 роки тому +1

    ur hands are hot