independent is what you change, dependent is what you measure. You are changing the current, and measuring the terminal PD (IR). Another way of looking at it is looking at the graph. The independent is normally on the x axis
I understand changing the resistance of the variable resistor changes the current, but then why is the independent variable the current? Should it not be the resistance as that is what we are directly changing, and the current changing is just an effect of that?
@@allanmathew7133 It seems you have to know the graph and how to find emf and internal resistance from it. emf = y-intercept and internal resistance = negative gradient of a V-I graph.
Watch me do it for reals: ua-cam.com/video/xoxDlu0kswQ/v-deo.html
Thank you for these videos really helps a lot
Great video
This video is great and very helpful, thanks
2:05 Would R count as an independent variable, and would I count as a dependent variable, since it is dependent on changing R? Thanks!
independent is what you change, dependent is what you measure. You are changing the current, and measuring the terminal PD (IR). Another way of looking at it is looking at the graph. The independent is normally on the x axis
Nice video
i was copying along and then i was sketching graph and did straight line proportional on like all the other ones before 😭😭
lovely
Respected teacher I need complete lectures of A level physics and notes, cecomend me some links.
you took the hard out of this topic and made something else hard
i agree
I understand changing the resistance of the variable resistor changes the current, but then why is the independent variable the current? Should it not be the resistance as that is what we are directly changing, and the current changing is just an effect of that?
The graph is based on current not resistance that is why.
Could you do the practical regarding the investigation of the motion of an object in a fluid.
Can questions on this appear in Paper 1?
please anyone answer lmao
I'd like to know this as well
@@allanmathew7133 It seems you have to know the graph and how to find emf and internal resistance from it. emf = y-intercept and internal resistance = negative gradient of a V-I graph.
It actually did 😂 just it didnt tell you it had internal resistance, you had to infer it.
@@flypig1 yeah ffs
@@AbdullahiIdri2001 ikr
👌🏻😎
Great video