Real Analysis 57 | Integration by Substitution

Поділитися
Вставка
  • Опубліковано 22 гру 2024

КОМЕНТАРІ • 17

  • @scollyer.tuition
    @scollyer.tuition 2 роки тому +13

    This is a very nicely structured lecture. And I'm glad to see someone cleanly explaining the requirement for bijectivity - this is very often omitted, or poorly explained.

  • @FraserIland
    @FraserIland 2 роки тому +8

    Congratulations!
    This is by far the highest quality lecture about Integration by Substitution which I have ever seen from a teacher or a book. Well done indeed.

  • @sinanakhostin6604
    @sinanakhostin6604 2 роки тому +1

    Excellent lecture. The last example is very interesting and clarifying the backward substitution rule.

  • @japedr
    @japedr 2 роки тому

    13:35 just a quick clarification. In general, the denominator would be equal to |cos t|, as we are taking the positive square root. But in the region of integration it is nonnegative, so the simplification is correct here.

  • @silentintegrals9104
    @silentintegrals9104 2 роки тому

    💕💕💕💕💕 awesome, solving integrals is so much fun 💕💕💕💕💕

  • @kz1662
    @kz1662 Рік тому

    thank you for these lectures !!

  • @sureacademykaklk6038
    @sureacademykaklk6038 5 місяців тому +1

    Sir how can you shift dt to RHS
    It is not independent

    • @brightsideofmaths
      @brightsideofmaths  5 місяців тому

      I don't really understand your question. Can you explain more?

  • @matejzadny8421
    @matejzadny8421 6 місяців тому

    great video,☝

  • @tsunningwah3471
    @tsunningwah3471 Рік тому

  • @PrzemyslawSliwinski
    @PrzemyslawSliwinski 2 роки тому

    12:53 - if the upper limit is 10, we just can take ϕ(t) = sin(t/10) and call it a day?

    • @brightsideofmaths
      @brightsideofmaths  2 роки тому +2

      10 would be a problem here since the function is not defined at 1.