A tiny version. Take √3 common in 1st term of l.h.s. gives √3(5+ 2 .√3 .√2 ) i.e √3 (√3+√2)^2 Removing root gives eqn 3^1/4 ( √3+√2) - 3^1/4 .√2= x^3/ 4 i.e 3^ 3/ 4= x ^3/ 4 Gives x = 3 Ramanujam will happy to see .
Thanks for your comments!! Very true, because he proposed and derived few of his work on denesting of nested radicals (with square roots and cube roots) in formula form and this is based on that. Thanks for watching 🙏
Excellent
...thanks for sharing...it was a wonderful explanation....x=3
Thanks a lot for your interesting and joyful solutions ^.^
A tiny version.
Take √3 common in 1st term of l.h.s. gives
√3(5+ 2 .√3 .√2 ) i.e
√3 (√3+√2)^2
Removing root gives eqn
3^1/4 ( √3+√2) - 3^1/4 .√2= x^3/ 4 i.e
3^ 3/ 4= x ^3/ 4
Gives x = 3
Ramanujam will happy to see .
Nice solution.
Thanks for sharing 🙏
3
Very clever.
Why is this Ramanujan's. It seems too simple for someone of his caliber!
Thanks for your comments!!
Very true, because he proposed and derived few of his work on denesting of nested radicals (with square roots and cube roots) in formula form and this is based on that.
Thanks for watching 🙏
X=3