How to Crack The Ramanujan Radical Challenge

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Are you ready to tackle the Ramanujan Radical Challenge on de-nesting nested radicals? Join us as we delve into this intriguing puzzle and uncover strategies to crack it! Whether you're a math enthusiast or just love a good brain teaser, this video is for you. Let's unlock the secrets behind Ramanujan's radical equations together!"
Topics Covered:
1. Understanding the basics of radical equations using Ramanujan's approach
2. Analyzing the de-nesting of the given equation.
3. Step-by-step approach to solving the radical equation.
4. Tips and tricks for handling tricky radical system of equations like a pro.
5. Algebraic identities and manipulations while solving equations.
Timestamps:
0:00 Introduction
0:44 De-nesting nested radical
1:15 Algebraic manipulations
3:04 Solving system of equation
7:20 Evaluating x
8:53 Answer
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Thanks for Watching!
‪@infyGyan‬

[@iamprit]

Excellent

[@mohammedsaysrashid3587]

...thanks for sharing...it was a wonderful explanation....x=3

[@woobjun2582]

Thanks a lot for your interesting and joyful solutions ^.^

[@tejpalsingh366]

3

[@roberttelarket4934]

Very clever.
Why is this Ramanujan's. It seems too simple for someone of his caliber!

[@infyGyan]

Thanks for your comments!!
Very true, because he proposed and derived few of his work on denesting of nested radicals (with square roots and cube roots) in formula form and this is based on that.
Thanks for watching 🙏

[@tejpalsingh366]

A tiny version.
Take √3 common in 1st term of l.h.s. gives
√3(5+ 2 .√3 .√2 ) i.e
√3 (√3+√2)^2
Removing root gives eqn
3^1/4 ( √3+√2) - 3^1/4 .√2= x^3/ 4 i.e
3^ 3/ 4= x ^3/ 4
Gives x = 3
Ramanujam will happy to see .

[@infyGyan]

Nice solution.
Thanks for sharing 🙏

[@RajeshKumar-wu7ox]

X=3