Hi Arun. Can you explain me few doubts here. As per the manufacturer information, the DC motors can be operated at 1.5V to 5V n 500W power consumption. Let's assume each motor is supplied with 5V, then to run the motor at said RPM, it requires P\V=I i.e 500\5=100A. Capacitor ratings are 2.7V n 40F. Charge stored on capacitor Q = capacitance C x applied (rated) DC Voltage V. That is Q = C x V. In your case as you said, 4V. Observation 1. Any capacitor must not be connected across a rail of voltage greater than the rating given on it. In your case, capacitor ratings 2.7V n applied voltage is 4 -->(×). As said Q = C x V, Q = 40F x 4V = 160columbs. The current by definition flow of charge per second. In this case Q = 160 & Q/t could be 160A. It may drive a single motor for 1.5 seconds only but, in your case found two motors require 200A@5V-->(×). So, this is not the genuine experiment..
Dear sir, your calculation is wrong.Here the motor is being operated by 2.5 bolts and the current is 150 milliamperes, hence the power of the motor P=vi =2.5×0.150 =0.375w As soon as a 4 volt solar panel is installed, its voltage reduces to 2.5 volts and is installed only for a short period of time because the condenser is completely discharged, hence the voltage drop between the solar panels. Actual voltage of the motor point is about 2.5 volt. I do not upload any fake videos on my channel, all videos are real.
Hi Arun. Can you explain me few doubts here. As per the manufacturer information, the DC motors can be operated at 1.5V to 5V n 500W power consumption. Let's assume each motor is supplied with 5V, then to run the motor at said RPM, it requires P\V=I i.e 500\5=100A.
Capacitor ratings are 2.7V n 40F. Charge stored on capacitor Q = capacitance C x applied (rated) DC Voltage V. That is Q = C x V. In your case as you said, 4V.
Observation 1. Any capacitor must not be connected across a rail of voltage greater than the rating given on it. In your case, capacitor ratings 2.7V n applied voltage is 4 -->(×).
As said Q = C x V, Q = 40F x 4V = 160columbs. The current by definition flow of charge per second. In this case Q = 160 & Q/t could be 160A. It may drive a single motor for 1.5 seconds only but, in your case found two motors require 200A@5V-->(×).
So, this is not the genuine experiment..
Dear sir, your calculation is wrong.Here the motor is being operated by 2.5 bolts and the current is 150 milliamperes, hence the power of the motor
P=vi
=2.5×0.150
=0.375w
As soon as a 4 volt solar panel is installed, its voltage reduces to 2.5 volts and is installed only for a short period of time because the condenser is completely discharged, hence the voltage drop between the solar panels. Actual voltage of the motor point is about 2.5 volt.
I do not upload any fake videos on my channel, all videos are real.