Spha mncwango it has to do with geometry, draw a straight line at b parallels to Va and look at the relation between the line and it's angle, notice you could have done sin60 -cos 60
be careful, i had the same question initially, the equation he used in example 1 is not the relative equation,(does not contain omega cross with a position vector), he used angle 30 because Vb/a is perpendicular to the link AB, and he simply finds Vb/a from the given Va
Dynamics is one of those modules that I’m glad I never have to do again 😹😹
I understand this better than ever before. Thank you!
Great video. Quick and efficient. Thank you
Awesome video, really helpful!
Great video
i have final exam in three hours ... you saved me XD
I get at 3:10
Perfect
May I ask a question, Sir? About cos60, shouldn't it be equal to 0.5, then -1wcos60=-1 (where w=2) Thank you
Great videos.... Thanks! Although I do make Vb= 4.732i - 1j
Wow i'm feeling as if i have passed my exam!!
Shouldnt r C/B being -5 ??
u forgot the omega in the second example 8:09
10:35 K should be in +direction and 0.3 times 6k (r b/a) was the wrong direction
Why is the angle 30 in the first example he works out anyone please explain.
Spha mncwango it has to do with geometry, draw a straight line at b parallels to Va and look at the relation between the line and it's angle, notice you could have done sin60 -cos 60
be careful, i had the same question initially, the equation he used in example 1 is not the relative equation,(does not contain omega cross with a position vector), he used angle 30 because Vb/a is perpendicular to the link AB, and he simply finds Vb/a from the given Va
can you go any faster???