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Dynamics - Lesson 12: Relative Motion with Translating Axis
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- Опубліковано 4 бер 2018
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JEFF! I've recommended you to all my friends in the past year multiple times in statics. I'm a week and a half into dynamics and I've watched almost half of your videos! Please consider putting up more as your videos have been a saving grace. God bless you sir.
once again, jeff Hanson is saving my ME grades (:
seriously thank you, you teach better than my professor could ever dream of
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Keep em coming jeff! These are keeping my afloat in dynamics but we have moved pass this part now and into work of a force. You are my lifesaver.
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Thanks again. You have a talent for breaking a problem down in to simple simple steps.
I really wish Professors spent more time training to be good teachers instead of just good at bringing in research dollars.
Thank you Dr. Jeff Hanson! These videos have been really helping me understand dynamics a bit better.
My lecturer sucks so I learn Dynamics (Mechanical Engineering) from your channel. Keep them coming my lifesaver!!!
man this cleared up so many misconceptions not that i dont undestand what is being talked about but rather i now understand how to set up relative motion problems.
you deserve a Nobel prize for how you explain the problems .. thanks again ..
Studying for my FE after working for 5 years and I am rusty! Your videos are magnificent: you thread the needle of simplifying the explanation while preserving nuance. I love when you call out what we're "ignoring."
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I absolutely love these videos! I am currently using these for my dynamics class at UT.
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DR. Hanson, thank you for another amazing lecture on Relative Motion with Translating Axis. Many problems in dynamics also uses different formulas for solid and correct computations
This is really cool, please go on till the end of the course
The first exam coming up in dynamics at the University of Houston, you sir have been a great help in statics and dynamics, thank you for spending the time and effort to make these videos!
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Thank you so much, professor. You have saved our lives. May God bless you. Please add more videos on dynamics. We are waiting for you do upload more videos.
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Thank you...sir... your lecture helps me to understand this portion clearly....
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Isn't the angel theta= arctan(-50/-4000)?
FINALLY FOUND A COMMENT LIKE THIS. THOUGHT SO TOO.
I hope u finish the dynamic course because i really depend on it
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I hope a bunch are uploaded at once :(
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Thank you
I am confused, when you took the arctan, you did 4000/50 which is adjacent/opposite, but tan is Opposite/adjacent?
if you used the resultant acceleration of car A instead of breaking it into components would that answer also be correct?
how to find the angle?
I always wondered what the blurred logo was in the corner of the screen. NOW I PROCESS FORBIDDEN KNOWLEDGE
Can someone explain to me why he didn't directly get the resultant of 300 km/hr in the y-direction and the 4000 km/hr in the x-direction? I'm confused in that part, thanks in advance.
"Where's my calculator?.....𝒸ₐₗ𝒸ᵤₗₐₜₒᵣ" 12:04 lol
9:45 Why cant the acceleration of CarA be the resultant acceleration?
To get a relative value you have to be on the same axis. The velocity of A and B both move along the y-axis. But the acceleration resultant of A has two directions ( x and y-axis) it moves along. To solve this you can use the vector notation for the components of A and B (also lot easier than angles ).
how to split into components choosing which side as sin cos? Confused :(
when it comes to the components I cannot understand it !
Help Needed ! Anyone plz !
the component nearer to the angle is cos.the other one is sin.
Hi Jeff ....
My teacher is teaching the same stuff but he have given be a bunch of equations ... With first and second derivatives of E r and E theta .... And I have no idea what he is talking about ... Can you please go over that content.... If you want I can email you the pics
Rahul walia do you have a twitter acount?
خالد الجميلي yes I have a Twitter account @Rahulwalia8510
خالد الجميلي thank you
the blurred out TTU logo lol
You're my hero jeff handsome baby! xx
long live the the jeff and the jeffs
Can someone tell me how he got that angle?
Using the i and j components. Arctan(50/4000) = .716 degrees
0:55
great video :)
The radius curvature should be the reciprocal of radius......... I think there is something wrong with the calculation.
PLEASE FINISH THE COURSE IM BEGGING YOU