I have a doubt sir. When you are explaining about the first example of cross conjugated dienes at 10.20 minutes , you are adding base value 215nm with 2 beta ring residue 24nm and one exocyclic 5nm and total is 244nm. In this example why we are not taking Homo annular diene value?
The homoanular diene you are looking at is not part of the alpha beta conjugated system we are considering. He said we would have to consider the alkene with the highest number of ring residues. So the alkene to the right was considered as the conjugated system. The alkene on the left wasn't considered because the alkene on the right has the highest number of ring residues.
Thanks alot. But the last example, please why didn’t we add the edo yip pic double bond.
Last wale example me ek exocyclic bond hain sir
shouldn't we add another 5nm for the last example because there is an exocyclic double bond
Yes
No the double bond is not exocyclic since it is a diene
Thank you, your lessons are very detailed and helpful .
You are welcome!
Sir last example mn exocyclic double bond add kun ni kiya plz reason day dain
Watch it carefully again, you will understand
We will consider only that exocyclic double bond which is included in conjugation?
Right
How is the last example homoannular ?
In the same cyclic enone
Sir for the last example
Why didn’t you add the exocyclic when calculating?
There is no exocyclic in last example
wow this is amazing thank you very much
11:54 when we should've calculate the homoannular diene component(39) to find lambda max value?
Thanks❤
Thank you very very much❤️❤️
Sir plz do a video for retrosynthesis
It will be very helpful
Plz sir
Okay sure
Yes sir, plz make videos on retro synthesis.. your explanation are so awesome and you teaching style so nice .. we can easily understand...
@@ChemWis thank u Sir........ Actually the retrosynthesis make me in trouble that's y sir ........
Thank u so much sir .Its very helpfull for us🙏🙏😊
Thank you but last example is not homoannular diene😊
Why it's not homoannular ?
How to find a lambda max for a same molecule that have a pi bond different position
Ex ., CH2=CH-O-CH3 & CH3-O-CH=CH2
I have a doubt sir. When you are explaining about the first example of cross conjugated dienes at 10.20 minutes , you are adding base value 215nm with 2 beta ring residue 24nm and one exocyclic 5nm and total is 244nm. In this example why we are not taking Homo annular diene value?
The homoanular diene you are looking at is not part of the alpha beta conjugated system we are considering. He said we would have to consider the alkene with the highest number of ring residues. So the alkene to the right was considered as the conjugated system. The alkene on the left wasn't considered because the alkene on the right has the highest number of ring residues.
For aldehyde, base value is 207. Not 210
Nice explanation
Thank you sir
Welcome
Sir last example is not homoannular
excellent 💫
Thank you!
You're welcome!
Great👍
Thanks for the complements!
Clinical 🔥
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1st view 👍👍👍
Please sir bto