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Best videos on woodward-fieser rules
Thank you so much.
Thanks to your video, I now know exactly what an exocyclic double bond is. Thank you so much!!!
You are so welcome!
Last example is wrongly calculated .
Exactly
No, It is correct. It is the example of cross conjugation.
Homoanular was supposed to be 253nm
Me: frustrating by leaurning for an examthis Hero 2 Years ago: Hold my beer
In the example of exocyclic double bond, 4th and 5th both are heteroannular, then why one have 1 exocyclic double bond and other have 2?
In the initial part of the video, identification of exocyclic double bond is clearly explained.
Your exocyclic double bond for the last question is incomplete.
How?. I guess he calculated exact.. bcz in last structure, only double bond of RING-C is exocyclic to ring B, all other bonds are endocyclic
No, It is complete.
Thank you
Agreat video thank you so much 🌹😻😻FROM IRAQ LOVE TO YOU 🌹❤️🔥
hi but pertaining your last question why is is that you chose only one double bond extending conjugation
What's the Absorption maxima? How can I calculate that? You just tell about Lambda Maxima.... What's the Absorption Maxima? Help please help
For the fifth example it's 5×5 not 5×4
Yes, you are right. I have already corrected in the same video.
Thanks
Welcome
5th one answer is 343
No, answer is 313 nm. we will not consider extreme left double bond due to cross conjugation.
i tend to defer with your last example computation, there's no double bond extending conjugation
We take base value for the diene system. any extra double bond is considered as the double bond extending conjugation.
Good
Sir aape acrylic ka man Galt rkha he
No, ye sahi hai. kuchh books me 1 or 2-3 nm ka difference mil sakta hai.
Last is wrong
acyclic system has 217 nm value.
Best videos on woodward-fieser rules
Thank you so much.
Thanks to your video, I now know exactly what an exocyclic double bond is. Thank you so much!!!
You are so welcome!
Last example is wrongly calculated .
Exactly
No, It is correct. It is the example of cross conjugation.
Homoanular was supposed to be 253nm
Me: frustrating by leaurning for an exam
this Hero 2 Years ago: Hold my beer
In the example of exocyclic double bond, 4th and 5th both are heteroannular, then why one have 1 exocyclic double bond and other have 2?
In the initial part of the video, identification of exocyclic double bond is clearly explained.
Your exocyclic double bond for the last question is incomplete.
How?. I guess he calculated exact.. bcz in last structure, only double bond of RING-C is exocyclic to ring B, all other bonds are endocyclic
No, It is complete.
Thank you
Agreat video thank you so much 🌹😻😻FROM IRAQ
LOVE TO YOU 🌹❤️🔥
hi but pertaining your last question why is is that you chose only one double bond extending conjugation
What's the Absorption maxima?
How can I calculate that?
You just tell about Lambda Maxima....
What's the Absorption Maxima?
Help please help
For the fifth example it's 5×5 not 5×4
Yes, you are right. I have already corrected in the same video.
Thanks
Welcome
5th one answer is 343
No, answer is 313 nm. we will not consider extreme left double bond due to cross conjugation.
i tend to defer with your last example computation, there's no double bond extending conjugation
We take base value for the diene system. any extra double bond is considered as the double bond extending conjugation.
Good
Thank you
Sir aape acrylic ka man Galt rkha he
No, ye sahi hai. kuchh books me 1 or 2-3 nm ka difference mil sakta hai.
Last is wrong
acyclic system has 217 nm value.