Subspaces and Span

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  • Опубліковано 25 бер 2019
  • Now that we know what vector spaces are, let's learn about subspaces. These are smaller spaces contained within a larger vector space that are themselves vector spaces.
    Script by Howard Whittle
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КОМЕНТАРІ • 128

  • @republicraider8336
    @republicraider8336 Рік тому +59

    You've just explained in 5 minutes what took my professor four weeks to half explain. Thank you.

  • @dominiquedewet3311
    @dominiquedewet3311 5 років тому +212

    No professor of mine is able to compete with your brilliant explanations. Something seemingly complicated made so simple.

    • @damiankarsyn9653
      @damiankarsyn9653 3 роки тому +1

      i guess it is pretty randomly asking but does anyone know a good place to watch newly released series online?

    • @biglexica7339
      @biglexica7339 2 роки тому +2

      @@damiankarsyn9653 no

    • @andrewkorsten2423
      @andrewkorsten2423 9 місяців тому

      @@damiankarsyn9653 what series?

    • @GoldenTiger01
      @GoldenTiger01 5 місяців тому +2

      @@andrewkorsten2423 Fourier series?

  • @alish2001
    @alish2001 4 роки тому +163

    I literally have a midterm in 2 hours you are a godsend

    • @micoluk9446
      @micoluk9446 2 роки тому +1

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    • @DARTH-R3VAN
      @DARTH-R3VAN 2 роки тому

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    • @micoluk9446
      @micoluk9446 2 роки тому

      @@DARTH-R3VAN just like with ur mom

    • @tomatrix7525
      @tomatrix7525 2 роки тому +12

      Yup we’re fucked

    • @DARTH-R3VAN
      @DARTH-R3VAN 2 роки тому

      @@tomatrix7525 like our moms

  • @linnsandvik6308
    @linnsandvik6308 3 роки тому +22

    I really appreciate that you are speaking so clearly! It makes your videos easy to follow despite my hearing loss:)

  • @snpthompson
    @snpthompson Рік тому +3

    you are the best! i hope you continue to upload these videos because you are the best teacher i’ve had! i know that so many others you have helped would agree

  • @andrewkorsten2423
    @andrewkorsten2423 9 місяців тому +3

    I am just doing video 33. I went to the last ones to check out whether the quality is going out, or the topics are too complex. But every video has only positive comment, which are clarly not farmed. IT's clear that the series is highly effective in teaching us the bascis. I am brushing up on math overall, and it feels great to be doing this course.

  • @noahbarrow7979
    @noahbarrow7979 3 роки тому +29

    this linear algebra playlist of yours is the absolute best i've come across on the internet. Thank you for being so lucid and lending so much clarity to these (sometimes) abstract concepts. Are you making a differential equations playlist? Would love to see some ODE!!

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  3 роки тому +16

      Yes I've been meaning to do that for a while! Just looking for the right writer.

    • @tejasgowdakr4700
      @tejasgowdakr4700 2 роки тому +1

      @@ProfessorDaveExplains pls do PDE also (love from india )

    • @thedoc6413
      @thedoc6413 Рік тому

      @@ProfessorDaveExplainsdo you still plan on doing this?

  • @neham1008
    @neham1008 Рік тому +1

    bro you are the best at teaching this. I'm sooo grateful for your videos. Thank you so much! I was stressing out like crazy for my upcoming quiz until I came upon your teaching videos.

  • @zeffdronin6422
    @zeffdronin6422 2 місяці тому

    you really a gem. i cannot express enough gratitude for your videos, and im certain im not the only one to feel this way. thank you!

  • @arnavkanathia757
    @arnavkanathia757 3 роки тому +1

    great professor just teaching complicating things with such ease

  • @enweremfavour5315
    @enweremfavour5315 2 роки тому +7

    You have made algebra easier for me compared to our boring lecturers. Thanks a lot. Much love ❤️ from Nigeria 🇳🇬

  • @anas8296
    @anas8296 7 місяців тому

    in 5 minutes , you have perfectly explained what my professor failed to teach us for 4 hours, much appreciated

  • @user-yg6lf3ig2q
    @user-yg6lf3ig2q 2 роки тому

    You are really explaining brillians as we are always doing right in checking comprehension

  • @mehmettoktas5430
    @mehmettoktas5430 3 роки тому +1

    Thanks for ur quality learning style Professor.Thanks from Turkey.

  • @ramankumar41
    @ramankumar41 Рік тому

    nice explanation Prof. Dave

  • @annaduong9830
    @annaduong9830 3 роки тому +9

    I did love this vid so much. It helped me to understand the basis of vector spaces which had taken me a lot of time to learn in the class.

  • @navaerick86
    @navaerick86 7 місяців тому

    Wish I had a professor like you

  • @nataliatothemoon
    @nataliatothemoon 3 роки тому

    Praying Tanaka is so lucky to have found you Professor Dave.

  • @mdmahmudhasan1645
    @mdmahmudhasan1645 2 роки тому +1

    Clear explanation, carry on.

  • @mrtoys3094
    @mrtoys3094 3 роки тому

    Thank you for saving my semester professor much love from Kenyatta university ( Nairobi Kenya)

  • @user-uv3up3xe1r
    @user-uv3up3xe1r 16 днів тому

    Thank you so much!

  • @abu-bakrmohamed1707
    @abu-bakrmohamed1707 2 роки тому

    WOW , u made everything clear for me thank u so much :)

  • @zandertaljaard5431
    @zandertaljaard5431 2 місяці тому +1

    Note to viewers:
    The vector space V (as in the video) is also a subspace of itself.
    Hence, S does not have to be strictly smaller than V, as Dave slightly misleadingly stated in the introduction.

  • @kalpeshyadav1391
    @kalpeshyadav1391 3 роки тому

    Awesone very nice explanation

  • @Smoothcurveup52
    @Smoothcurveup52 Рік тому

    Wow wonderful explaination

  • @HWFieldGoal
    @HWFieldGoal 2 роки тому

    Thank you it is help full lecture!!!!

  • @honeycocoa1907
    @honeycocoa1907 5 місяців тому

    argh thank you so much i was having a hard time understanding all this. The video is so good i had to watch it 3 time lol

  • @joshuawang9401
    @joshuawang9401 3 роки тому

    TY professor!

  • @user-fy2ud4fq4g
    @user-fy2ud4fq4g 4 місяці тому +2

    5:12 what if we multiplied by a negative scalar? Would we still get a matrix in the specified form?

  • @sakinsayeem419
    @sakinsayeem419 Рік тому

    Can you please explain what you meant by 'Any sum of these elements" in 3:20

  • @PrawjektSilvia
    @PrawjektSilvia 3 місяці тому

    I think it's important to note that a subspace must also contain the additive identity. In the case of vectors, it must contain the zero vector. Great video!

  • @dr.walidsoula
    @dr.walidsoula 2 роки тому

    Very nice,Thx

  • @Abdulrahman-hb6fy
    @Abdulrahman-hb6fy 3 місяці тому

    the span of any number of elements of vector V is also a subspace of V
    a span is the smallest subspace of V that contains this set of elements
    span is important for describing vector spaces

  • @k_nito7954
    @k_nito7954 9 місяців тому +3

    Hey sir! I was just wondering, can the scalar for the 1st rule of Vector Spaces be a negative? If yes, wouldn't it make the matrix in the 1st question of Checking Comprehension not a subspace? Since the -b in the bottom row would turn positive

    • @t.gmultiplex2838
      @t.gmultiplex2838 6 місяців тому

      I'm not a professor but if you are talking about the 2bd question in last then if 2nd row if b becomes positive then b in first row will to -b thus form will remain same

  • @josephbadana5002
    @josephbadana5002 4 роки тому

    thanK you so much.

  • @nafiurrahman722
    @nafiurrahman722 9 місяців тому

    I didnt understand the part where span of V is the smallest subspace of V. How come? The a1V1+a2V2+a3V3 (if linearly independent) is the entire R3 right?

  • @thefrenchiestfry8147
    @thefrenchiestfry8147 2 роки тому +2

    For closure under addition, do the vectors that are added to vectors in a subspace have to be part of the subspace themselves?

  • @gamensmpro2819
    @gamensmpro2819 2 роки тому

    Thanks

  • @manishbhanga
    @manishbhanga 4 роки тому +23

    What if c is negative?

    • @Christian-mn8dh
      @Christian-mn8dh Рік тому +1

      exactly what I was thinking

    • @arwaomer9795
      @arwaomer9795 Рік тому

      Me too😅

    • @endabenson701
      @endabenson701 11 місяців тому +5

      Think it still works cause the bottom will be positive and the top will be negative, in other words, the bottom is the negative of the top line which is negative. A bit confusing but I think the rule he stated was that the bottom line is the negative of the top line, not that the bottom line itself is necessarily negative.

  • @pwny4995
    @pwny4995 2 роки тому +3

    What are the difference between a Span and a Subspace?

  • @longvo2083
    @longvo2083 2 роки тому +2

    Why the first question of the comprehensive is true? Could someone explain it please?

  • @JJ-pz2dx
    @JJ-pz2dx 2 місяці тому

    I have a midterm in 3 hours 😩 thank you so much

  • @quantumleap7964
    @quantumleap7964 Рік тому

    here is an interesting idea, since points in cartesian space are just sums of the i-hat and j-hat basis vectors with real coefficients technically speaking all of the 2-d coordinates system is simply span(i_hat,j_hat). Similarily the 3-d cartesian system is just span(i_hat,j_hat,k_hat)

  • @simondx6694
    @simondx6694 5 років тому +38

    I already miss your long hair

  • @arefinsiddque6666
    @arefinsiddque6666 2 роки тому +1

    Sir, multiply vector x with any negative constant value. Then, will the resultant vector x belong to the set S?

  • @nobody48803
    @nobody48803 Місяць тому

    awesome

  • @kaanylmaz1008
    @kaanylmaz1008 2 роки тому +1

    teşekkürler, iyi geldi

  • @zxcxdr1
    @zxcxdr1 2 роки тому

    English is my third language, and you still explain better than my professors in my mother tounge

  • @alhadibalouch8442
    @alhadibalouch8442 4 роки тому +1

    i have a midterm tomorrow thx

  • @Christian-mn8dh
    @Christian-mn8dh Рік тому +1

    2:20 is it really closed under scalar multiplication? what if c is negative???

    • @carultch
      @carultch Рік тому

      No issue if c is negative. The original vectors can be any vectors in the form of [[x],[0],[-x]], where x is any real number. The multiplier c, can also be any real number. Multiplying any two real numbers together, also gets a real number, and x*c will still be the negative of -x*c.

  • @karlmax61
    @karlmax61 3 роки тому +1

    PLEASE MAKE LECTURES ON REAL ANALYSIS

  • @qingyangzhang887
    @qingyangzhang887 5 років тому +3

    Thank you so much. By definition would a vector space be a (very useless) subspace of itself?

    • @AEPPLE_MUSIC
      @AEPPLE_MUSIC 2 роки тому +2

      Know it's too late but for anyone with a similar question: V is in itself a subspace of V.

    • @twi4458
      @twi4458 2 роки тому

      @@AEPPLE_MUSIC Makes sense

    • @shriyanshkatiyar5807
      @shriyanshkatiyar5807 Рік тому

      YES OFCOURSE! IT WOULD BE. 🙂

  • @animeparadise2461
    @animeparadise2461 10 місяців тому

    Sir in Example of subspace what if we take the value of scalar as negative then the 1st property will not be held . Please help me with my doubt.

  • @bouyancyyang943
    @bouyancyyang943 2 роки тому

    in 5:09 (2), can their span be in real number instead of a & b?

    • @amartyapanwar3164
      @amartyapanwar3164 Рік тому

      well, you assume a and b to be constants that are also real numbers. so the span, as a result, will be a real number, as you're not dealing with any variables here...hope this helps :)

  • @lankaputhra4825
    @lankaputhra4825 27 днів тому

    What if sub space doesn’t include identity O but satisfies closure .
    It’s not a vector space is it? Still a subspace?
    If so not every subspace is vector space. Am I missing something ?

  • @Sunny-qe5el
    @Sunny-qe5el 3 роки тому +1

    Multiplying zero scalar to a vector will yield zero result,
    So, in case of subspace, we could say that it is closed for scalar multiplication?

    • @Christian-mn8dh
      @Christian-mn8dh Рік тому

      c = 0 makes me think of another question. If c = 0, then the vector is [0,0,0]. which means it's not maintaining the [x,0,-x] form??? idk. pls help

  • @curtpiazza1688
    @curtpiazza1688 3 місяці тому +1

    Great ! Thanx! 😂

  • @devendraonly239
    @devendraonly239 5 місяців тому

    2:00 why we are checking its closed or not, since its a subset of vector space..
    Confused!

    • @arvind9438
      @arvind9438 3 місяці тому

      we are trying to check if it is indeed a subset , thats why

  • @wenanyaugustine3311
    @wenanyaugustine3311 10 місяців тому +1

    what if you had used -1 as a scalar to multiply?

  • @suprememaster1951
    @suprememaster1951 2 роки тому +1

    Every subspace of R5 that contains a nonzero vector must contain a line. Is this statement true?

  • @BagavaanSriKrishn
    @BagavaanSriKrishn 9 місяців тому +3

    Watching 10 min before exam

  • @kapjoteh
    @kapjoteh 3 роки тому +4

    2:28 what if c was -1

    • @bigilpandi7722
      @bigilpandi7722 3 роки тому

      Scalar positive integer

    • @multitude1337
      @multitude1337 2 роки тому +1

      @@bigilpandi7722 wrong

    • @multitude1337
      @multitude1337 2 роки тому +3

      c can be any real number, remember it's a scalar, so it can be negative. thus, it will still work as the first component of the x vector has the opposite sign of the third component of the x vector, so it still satisfies this closure property

    • @Christian-mn8dh
      @Christian-mn8dh Рік тому

      @@multitude1337 so what does 'form' really mean? im confused

    • @carultch
      @carultch Рік тому

      @@Christian-mn8dh Think of form as meaning pattern. A vector in the form of [[x],[0],[-x]] means that you can put any (real in this case) number in the position of the x, in both the first and final entry of this vector. So this means that [[4], [0], [-4]] as well as [[-6], [0], [-6]] are vectors of this form. They have something in common, in that their first and final entries are negatives of each other, and they have zero for the middle entry.
      Note that the nested brackets is my way of indicating the vertical matrix, in an inline text description. Think of the innermost brackets as individual rows, and the outermost bracket as the full matrix of those rows. In this case, there's just one entry per row, since vectors in linear algebra are considered vertical matrices.

  • @hse2951
    @hse2951 3 роки тому +1

    I don't understand R 2*2 Could you explained it

    • @johanjimenez1249
      @johanjimenez1249 3 роки тому

      he made a video called understanding vector space

    • @carultch
      @carultch Рік тому

      The R refers to real numbers. The 2x2 refers to 2x2 square matrices. Putting it together, it refers to the set of all square matrices with 2 rows and 2 columns that contain any real number in each of the 4 entries.

  • @Dilshannarankotuwa
    @Dilshannarankotuwa Рік тому

  • @leoncraftmc
    @leoncraftmc 2 роки тому

    2:09, why is it “-(cx)”?
    c * (-x) is -cx

    • @ammyvl1
      @ammyvl1 2 роки тому +1

      just to illustrate that it's some number in the form -x better

    • @carultch
      @carultch Рік тому

      Multiplication of real numbers is associative and commutative, so you can rearrange the parentheses and negative sign, however you prefer.

  • @hero_of_winds7311
    @hero_of_winds7311 4 місяці тому

    Can someone explain #2 to me?

  • @justthenamekevin
    @justthenamekevin 2 роки тому

    french: Span is written as Vect

  • @mcalkis5771
    @mcalkis5771 2 роки тому

    Why the hell am I getting "Feet finder" ads on UA-cam?? And on math tutorials of all places???

  • @syedannasali8039
    @syedannasali8039 Рік тому

    Hrs of lec

  • @killercat50y
    @killercat50y 2 роки тому

    Don't know if you will ever see this comment, but thank you. You are getting me through my college linear algebra class. My teacher is so bad at explaining things, and you make it so simple to understand.

    • @ryanblanch2764
      @ryanblanch2764 Рік тому

      Same with my Linear Algebra Course. This is helping a lot.

  • @rajanraju4194
    @rajanraju4194 5 років тому

    Private videos ??

  • @vaibhavshilar7697
    @vaibhavshilar7697 3 роки тому +1

    Sir Hindi

  • @hassannabil7309
    @hassannabil7309 4 місяці тому +2

    Midterm in 20 minutes 💀💀