Large Tesla Turbine, live steam test.
Вставка
- Опубліковано 26 гру 2014
- This is out third prototype of a Tesla turbine. Here we are trying to determine the best running speed of the turbine. Top speed is 6350 rpm at marker 9:52. This is in excess of 414 mph at the outer blade at less than 50 psi. The resonance frequency of the turbine is between 4250 and 4500 rpm. At 4700 rpm the turbine exceeds this frequency, the vibration ceases and the efficiency improves. 5400 looks like a viable operating speed for this 22 inch diameter turbine.
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations.
For starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physic...
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
• Large Tesla Turbine, l...
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
Tesla had his little 6" one doing over 100K RPMs. His larger ones exploded... This thing was cool to watch! I wouldn't want to be standing near it, but it was fun to watch from here! =D I like it!
Fun fact 6000 rpm is 100 rotations per second... think about that 😲 that heavy disc is spinning fast!
Маленькие турбины держат 50000 об/мин
your car is doing the same :D
>tesla turbine
no that the GTX 480's fan after installing Windows 10 and it's various animations on screen
Your neighbours would be happy with this sound! Excellent job!
Neat! I let the folks at WBCQ in Maine know about your turbine. They talked up the idea of making their own electric power from burning wood.
Nice steam siren
it just keeps climbing! that's awesome!
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
Now this I love, this shows real promise!!! I've been looking for a low steam pressure turbine for my other inventions and this is it.This could be used for car engine waste heat.
Mark Osborn Agreed
where the hell do i buy one right now
or car exaust.
@@joeylawell3590Charlie Solis
Need stage 2!
Sounds just like a Pyle National steam locomotive headlight dynamo spooling-up.
I want to see a step by step tesla turbine being made and also the 12 inch perminent magnets spoke about in the other video
Do you have anything for sale at this time?
If you could get it passed the speed of light you could build a time machine.
Or it would just disappear and then reappear with some dude in a sailors uniform molecularly molded into the turbine casing.
It would begin to spin in the opposite direction
@@888WulfDog888lol got the reference
Great speed
Water boils in a vacuum at room temperature all you need are two chambers and a condenser coil making it so the steam goes from one to the other passing through your engine or turbine as the steam condenses the vacuum is maintained so the energy requirements are minimal to start and a set amount of water to use.
@LazicStefan When the steam condenses the vacuum is restored you can prove this if you put a little hot water in a soda bottle shake it up release the air and then reseal it and put it in the freezer it will collapse you will get condensation with a temperature difference and as you only need a few degrees of variance from hot to cold it is a very efficient system.
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
@@ourhouseisfull11 wow bro can I see the full video from start of the actual build and can u explain where what how etc pls we should really start a group to get these out to the masses and beat these elite controllers of energy now before this world wide grid and cash is replaced by a quantum computer that only allows us to use so much energy from the smart grid...
@@ourhouseisfull11 I copy-pasted this paragraph for my future reference.
this sort of energy provider is only suitable offgrid and needs a special sound-suppression containment to make it a reliable unit
Underground is the best option. You can also put in a cooler tower to turn some amount of the steam back into water using earth's cooling. Also helps with safety being surrounding by earth.
Sounds like a ge90 jet engine at full throttle
that is insanely fast
Why you don’t use air with this psi and count the reps?and by the way how many plates in Tesla turbine?
Hi Don - tks for sharing - sounds fun!
I see you've used one plate of steel - 22"
I have questions - doubtless it works with steam low pressure (around 3,5 kgf/cm² - 50 psi). Rotation is feasible, how about torque? How many kg of steam at 50psi?
thank you for kindness
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
i know this is an old video but can you remember where the main amount of noise comes from, would you say vibration of the case housing or the actual spinning discs themselves? thanks
The noise comes from the rotor itself. Anything moving at high speed in air is going to make noise. This rotor is spinning at 400 miles per hour at 6300 rpm.
Sweet safety moccasins 😎
Yes they are
Did you test power out from the generator
how much water was used to get the turbine moving? Did you measure it?
The forces acting on the turbine plates must be immense, are the plates cutter blades for a petrol stone cutter?
If I was in the area of this running, I wouldn't be any closer than 100 yards.. The thing is likely to start bending time and gravity! lol.
Great project.. 👍🏼
idiot that think is far more stable than any regullar turbine :D
You're probably right! That's how it's done anyway. This could potentially leave the operator with body parts fused to the metal casing of this machine! That would be bad ... Really BAD! Not something you can UNDO!
@@sparkimoto science though.
@@jvon3885It's bad science if you ignore the math that means you would need material 20,000x stronger than crystal graphite to build an efficient power plant generator. 😂 Thin low weight discs and high G's don't mix. Tesla realized this, idiots today have not.
lmao
Just out of curiosity what is the temperature of the steam before entering the turbine and after exiting the turbine.
Entrance was 275 F and exit was 192 slightly over expanded.
Put a prop on it and you can fly at that rpm.... steam punk plane 🤩
Wire a flat starship coil on the outter side of the disk and you would. E generating an insanely high voltage. Then run it to a source a great distance away then step it down.
What kind of torque would you get from something like that type of motor using steam?
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
@@ourhouseisfull11 -- But how much torque?
Tesla power super
Wow 50 psi has a lot of energy
It only takes twice atmospheric pressure to achieve supersonic flow when expanding steam with the correct C/D nozzle and this is a very efficient process in excess of 65% thermal efficiency. It is my opinion that Tesla Turbines can only produce torque using reynolds numbers exceeding laminar flow and above subsonic entrance speeds suggested by the converging nozzles in the machines Tesla patented. He patented his failures. That is why nobody can make his machines work...... they do not understand them. What he patented and what was tested that produced torque where not the same machinery. Thanks for comment.
I doubt if it has the torque to drive the electric motor. But what if u mount an ingition coil from a motorcycle on one end and use that to charge a 12v batterybank?
It easily generates 480 volts 3 phase A/C. Why would we waste time with a 12 volt dc system?
how many discs do you use? it doesnt look like you used many of them. maybe 3 you should use more 5 are good or 10.
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
The Romans used the turbine to mill the weat.
Can you do the same with alcohol or acetone at lower temperatures?
no
Very wet steam!
When tesla supervised the building and installation of his turbine at Niagra,NY, he was pissed because he said "they didn't build it the way I designed it " If you build the Tesla Turbine according to the patent design it will work !!!!!!!!!!!!
his turbines aren't at Niagara, his AC generators were. 1895/96.
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
Is that running off saturated steam?
Use hydraulic fluid or motor oil.... Steam doesn't grab onto the discs the way oil would
On magnetic bearing it would go a lot faster.
I wanted to see how did it go with a load
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
i need one please
how many discs and at what diameter are they?
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
very steamy, chu chu
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
I am interested in just one aspect of the Tesla Turbine! How much air is being moved at full power! How many CFM? If it's an extreme amount, then I have some great ideas to utilize this COMPRESSION OF AIR! i DON'T care about the torque on the crankshaft! Let it run free and give me JUST the AIR FORCE! Or would this even be practical? nO wiat ... I see you said 50 PSI! YES! PERFECT! tHAT'S The kind of numbers I was looking for! I got to go and do some prototyping! This just might work after all!!!
????
all the best
Putting on a motorcycle clutch and transmission it would be the opposite of giving gas to go fast Man 😂 but trying not to burn it out haha 😆🤯😂🤣 I got to try it
How much power can you make with this turbine?
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
Imagine one of the bearings failed at the rpm!!!
Imagine being married! But don't do that...... again. I'll take my chances on the bearings.
@@ourhouseisfull11 smart move
класна парова турбіна
Put a belt drive on it and run something!!
It was sold a long time ago and it is running something...... an off grid steam powered generator.
speed is meaningless without torque, how much power can you get out of it?
Not enough, we have gone towards the impulse style turbine instead. Check out this instead. More power with 1/3 steam volume. ua-cam.com/video/2n--jgfY5-A/v-deo.html
tesla gives hight rpm with low torque so you would use a transmission to relieve turbine from stress and keep it at hight rpm coz higher rpm=higher efficiency.
This turbine i suspect have turque without transmission becouse of a discs sizes. it it is uneficient we will see in future.
Speed is cool no matter what.
@@orionti6215 this was the drawback with the Tesla turbine, the size required makes it physically unfeasible.
The most electric energy is extracted at high frequencies
Speed = energy.
You can convert both voltage and frequency later.
You size your generator to the turbine. Not the turbine to the generator.
Omg! Dont stand so close.
safer than marriage by a wide margin.
how many watts can that produce?
6700 watts per hour.
*GTX 480
extremely insane to stand by an unrated impeller at those speeds
LMFAO..... I tell you the truth. I am the engineer, designer and overseer of the fabrication and precision balance of this unit from start to finish. It was thoroughly tested by me personally. So i have absolute confidence in myself and the devise. I have no fear of standing next to the turbine. It is a very calculated and mitigated risk. So i take issue with the term "extremely insane". Marriage in this country is extremely insane and far more potentially destructive. Stop the insanity. Divorce the bitch.
he must not know that they are solid lol thinking of a traditional turbine lol dude i think its awesome
@@ourhouseisfull11 What will this thing do when hooked up to a generator that is charging batteries?
What would you attach this to as far as gearing it down, so that you could run a generator head that requires 3000 RPM?
If it were me, I'd use a worm gear on the output shaft driving a large pinion gear and jack shaft.
I'd use a belt
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
whats the purpose of this test?
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
estan mas locos que una cabra en las mediciones
Lol the Tesla works better with fluids. Steam turbines inject closer to the center and vent at outer edge. You are losing like 40% of your potential output! FYI I was a boiler specialist in the Air Force.
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
@Don I see you multiply Mass by Square feet to get foot pounds (not foot².pounds)...
Does it really look to you like 25 kilogrammes is spinning here?
@@simonmasters3295 these are 5, 22 inch plates, 2 10 gauge, 3 14 gauge. so yeah its about 25kg spinning there. thats pretty easy math.
All speed and no torque stories...nice turbine though
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
Почему это звучит как v8
Tedla turbines are .. well.. crap compared to anything we have today
Like what?
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
Gad make my teeth hurt. For the beginner read USN publications ( boiler maker 3&2 and Machinist Mate (3&2. Read these do the math and you will know more than your questions you asked. As for the BOOK go to the NALCO boiler hand book. or Be a Nuclear Engineer. Just saying.
The amount of energy used to spin this thing is a step in the wrong direction. People need to improve on a micro scale. This is just someone trying to make thing go brrrrrrrr.
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
no work done, no use fullness. waste of time to see. I thought someone had made one that actually pulled a motor.
ua-cam.com/video/aR50ZbKisek/v-deo.html
How many ppl come here complaining like they can do better? It's amazing at the arrogance of some ppl. My opinion.
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
Tesla micro turbine - 1300 Wt (1,3 kW) electric power - ua-cam.com/video/6JvIlccCHlQ/v-deo.html
That teach is nearly worthless.
I agree Greg. This high speed is somewhat impressive but absolutely worthless if it can't maintain a reasonable speed under a load (like a generator that is charging batteries or powering something). As I watched I kept thinking "Hook this thing up to a load of some kind and let's see what it can do"............
@@rolfc9714
You don't know how power generation works
@@MrDeicide1 enlighten me on why my thinking is wrong.
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
I git nothing on this video purposes....wasting time
because you’re incompetent
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations. Foer starters we are going to be using a rotational kinetic energy calculator. The link is here:
www.omnicalculator.com/physics/rotational-kinetic-energy
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
ua-cam.com/video/q3_wnLB8bn0/v-deo.html
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
@@ourhouseisfull11 my head hurts but im impressed