Thank you very much for your uploads. I watched them every morning for two weeks, practiced and just passed my test yesterday. I owe it to you my friend cheers!
I just wanted to say thank you for making this very beneficial series. My accuplacer test is tomorrow and I feel more confident having watched and learned these problems. Please continue to make these so others may benefit from your vast knowledge. Thanks!
thank you for not only showing us how to do it but u have us do questions over the videos we watch, of course i have subscribed and this has been super helpful so thank u now i have confidence i will pass.
I dont recall ever learning the AC method. I'm having a hard time with number six. Do you have any videos better explaining the AC method by chance. Otherwise your videos are amazing and really helping me with this. i should of maybe given myself a bit more time before i scheduled my test but I think I'll manage
It is called the ac method. If you have a quadratic in standard form ax^2+bx+c you place the product of a and c on the top and b on the bottom. Then come up with two integers that multiply to give you a*c (top number) and add to give you b (bottom number) Does that make sense?
maths gotserved is there a simpler method to solving it without having to do all of that? Because I've never learned anything about that method. Or can you do a separate video explaining the ac method?
Also, the accuplacer test doesn't provide a good enough calculator to take the math part and we're not allowed to use our own so can you teach a simpler way to solving for long divisions?
For #8, when you got -x=7 why did you divide -x and 7 with a -1? I thought you had to flip the signs, meaning if -x is a negative, then I would have divide both -x and 7 by +1?
In question 6 solution, using the ac(?) method, does it matter which side (left & right) that the factors are placed? I'm also still unclear how the factored version of the numerator replaces the original numerator formula. Is it just a substitution method used to simplify the equation?
Excellent question. It does not matter which one goes to the left or right. After factoring the numerator you substitute the factored form into the expanded form then reduce common factors.
Your answer for number 9 is incorrect it's actually D . Instead of dividing at the end you cancel out the x on the left side of the equal sign and then add it on to the right and it becomes positive that way .
3x-8x-6=-2 Distribute the -2 to the parenthesis -5x-6=-2 Combine like terms -5x=4 added 6 to both sides canceling the -6 on the right side x= -5/4 or 1.25
I just wanted to say thank you for making this very beneficial series. My accuplacer test is tomorrow and I feel more confident having watched and learned these problems. Please continue to make these so others may benefit from your vast knowledge. Thanks!
Thank you very much for your uploads. I watched them every morning for two weeks, practiced and just passed my test yesterday. I owe it to you my friend cheers!
Thanks to you I scored very high on my Accuplacer test!!!! Thank you for all of your videos
I just wanted to say thank you for making this very beneficial series. My accuplacer test is tomorrow and I feel more confident having watched and learned these problems. Please continue to make these so others may benefit from your vast knowledge. Thanks!
Accuplacer test tomorrow, wish me luck!
May the force be with you fam!
When you realize you've done all this in high school and never used it in the real world. 😩
ThaRestlessOne I promise! None of this stuff was ever used by me.
This is why I need to be taught again by UA-cam almost 15 years later lol
Great review series to prepare for the Accuplacer elementary algebra
thank you for not only showing us how to do it but u have us do questions over the videos we watch, of course i have subscribed and this has been super helpful so thank u now i have confidence i will pass.
Awesome, thank you!
I dont recall ever learning the AC method. I'm having a hard time with number six. Do you have any videos better explaining the AC method by chance. Otherwise your videos are amazing and really helping me with this. i should of maybe given myself a bit more time before i scheduled my test but I think I'll manage
Thanks for your encouraging remarks. Here is a tutorial on the AC method ua-cam.com/video/UjTe7dvdUKw/v-deo.html
The the videos keep getting better and better! Very helpful!
Thank you so much for your encouraging words
i haven't even taken my test yet but im already feeling ready and confident thank u so much keep it up
You are very welcome. We hope you super ace that test.
how it go
Truly math got served.Thankyou so much.
you are welcome
Thank you for doing this! I was really struggling to find videos that would explain these problems.
Thanks for this. Using this so I know how to do the practice questions online
I feel like an idiot... I spent over an hour trying to get question 6! I'll get it if it takes a year! Thanks for the video and the help!
Questions like number 9 confuses me.
I would have chosen answer choice A.
How do you know when to get rid of the parenthesis?
for number 9, I used the distributive method in order to get the same answer. that a viable method?
Can anybody tell me where he got the 2 and the 3 from because he lost me when he made that X thing
It is called the ac method. If you have a quadratic in standard form ax^2+bx+c you place the product of a and c on the top and b on the bottom. Then come up with two integers that multiply to give you a*c (top number) and add to give you b (bottom number) Does that make sense?
maths gotserved is there a simpler method to solving it without having to do all of that? Because I've never learned anything about that method. Or can you do a separate video explaining the ac method?
maths gotserved Can you use the ac method for the denominator though? Since it isn’t a trinomial??
am going for my test nextweek and i hope u guys will help me pls
Also, the accuplacer test doesn't provide a good enough calculator to take the math part and we're not allowed to use our own so can you teach a simpler way to solving for long divisions?
We will investigate to see if we can find simpler methods to divide. If any discoveries are made, you will be the first to be notified. Thx
The links to the Interactive Practice Test and Part 3 are missing. Just thought I should let you know. Amazing review series! :)
julian vazquez Thanks for the heads up, we will fix that right now.
you are the legend
For #8, when you got -x=7 why did you divide -x and 7 with a -1? I thought you had to flip the signs, meaning if -x is a negative, then I would have divide both -x and 7 by +1?
Math Gothard He did that to get X as a positive. - ÷ - is +.
Very helpful, thank you!
You are very welcome.
In question 6 solution, using the ac(?) method, does it matter which side (left & right) that the factors are placed? I'm also still unclear how the factored version of the numerator replaces the original numerator formula. Is it just a substitution method used to simplify the equation?
Excellent question. It does not matter which one goes to the left or right. After factoring the numerator you substitute the factored form into the expanded form then reduce common factors.
I have mine tmmr, and I’m scared. kinda my fault I’ve been trying to avoid it so I’ve only been reviewing today. wish me luck 🤧😖
what is the name for the problem for #7?
I am still not understanding #6 could you please help me to get this?
Sure! do you understand the factorization piece?
+maths gotserved. thank you for getting back with me. I think so.
I did the interactive test but after question 14 I can't proceed and get redirected to the home page.
Your answer for number 9 is incorrect it's actually D . Instead of dividing at the end you cancel out the x on the left side of the equal sign and then add it on to the right and it becomes positive that way .
your awesome.
Matthew Menges Oh thank you so much for your kind and encouraging words.
maths gotserved No thank you, you helped me a lot. And one more thing where is the part two of this one i could not find it ?
Why did you divide by -1 in question #8?
Oh you divide by -1 to get x isolated. When you divide -x by -1 the sign of -x flips to positive x and that is the goal of the problem.
just took your interactive test can you please check question 13
pookie hawkins Ok sure thanks for the heads up
pookie hawkins We have resolved the issue thanks again. We hope you do great on your exams woo hoo
need help solving 3x-2(4x+3)=-2
3x-8x-6=-2 Distribute the -2 to the parenthesis
-5x-6=-2 Combine like terms
-5x=4 added 6 to both sides canceling the -6 on the right side
x= -5/4 or 1.25
how come its negative 6 all of a sudden when he writes it out?
I still don't understand number 6. Can you help me please!
Me too
Helen Hanson it's very easy. there is a shorter way to solve that problem
I just wanted to say thank you for making this very beneficial series. My accuplacer test is tomorrow and I feel more confident having watched and learned these problems. Please continue to make these so others may benefit from your vast knowledge. Thanks!
just took your interactive test can you please check question 8
pookie hawkins Ok sure