Metod: if you don't remember equation for a^3-b^3=? If you know first solution for m=3 you can find quadratic equation for m in this way m^3+m^2+m-39=0 compare with (m-3)*(A*m^2+B*m+C)=0 it can be transform to A*m^3+(B-3*A)*m^2+(C-3*B)*m-3*C=0 so A=1 B=4 C=13 "(A*m^2+B*m+C)=0" W easily can find m={-B+-SQRT(B^2-4*A*C)}/(2*A)=-4+-i*3 ...😉
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Very nice @MATHS TUTORIAL ( BL SAHU)
Metod: if you don't remember equation for a^3-b^3=?
If you know first solution for m=3 you can find quadratic equation for m in this way
m^3+m^2+m-39=0 compare with (m-3)*(A*m^2+B*m+C)=0 it can be transform to
A*m^3+(B-3*A)*m^2+(C-3*B)*m-3*C=0
so
A=1
B=4
C=13
"(A*m^2+B*m+C)=0"
W easily can find m={-B+-SQRT(B^2-4*A*C)}/(2*A)=-4+-i*3 ...😉
a=1
a=1