Nope. Because the angle “AEB” has a vertex of E and isn’t inscribed from the same arc as “ADB” You can do the inscribed angle ACB since that starts at A and finishes at B (so arc AB like ADB has) and C is ON the circle. Or you can do vertical angle with AEB, so the angle across from AEB still with E as the vertex -> so angle CEB (or BEC) Hope that helps!
hey, for problem 5 could this work for congruent angles? ADB~AEB? 11:28
Nope. Because the angle “AEB” has a vertex of E and isn’t inscribed from the same arc as “ADB”
You can do the inscribed angle ACB since that starts at A and finishes at B (so arc AB like ADB has) and C is ON the circle.
Or you can do vertical angle with AEB, so the angle across from AEB still with E as the vertex -> so angle CEB (or BEC)
Hope that helps!
what do you mean by they dont cross the same arc
What problem are you asking about?
@@BrittaDwyer I figured it out keep up the good work
Oh good! Glad to hear it 🙌🏼🙌🏼🙌🏼