This was really helpful, thanks!!! I'd seen other videos but they had less complicated equations so it was good to see a more complex one done. I might just pass my exam now so thanks!! Also, you're a great teacher, really clear explanation.
Teaching myself A level maths and your videos are so useful! Could you recommend a site or page for example questions or questions to practice your lessons?
Thank you for the video! Just a quick question, can you prove that a stationary point is the point of inflection when a small decrease/ increase in x means that dy/dx is positive on both sides? Thank you!
@thezohan2112 You could look at the gradient either side. I show this in other tutorials on stationary points. Have you seen them? Look on my index on the homepage of my website if not.
Thank you so much for this! It's really helpful and better than the way my teacher had explained it before. I have liked your video and shared your channel with a lot of my friends, hope that it helps! You're awesome, thanks again!
If the second derivative = 0, then it is a point of inflection (meaning it changes from concave up to down or vice versa). The result is not inconclusive 4:56
Sorry to say but it is until you do the table. If you were to have say y=x^4, dy/dx=4x^3 and when dy/dx=0, x=0, y=0, d2y/dx^2 = 12x^2 and when x=0, d2y/dx^2=0 but it is a min in this case not a point of inflexion.
can't you say that when d2y/dx2=0, the nature of the sationary point is that it's an inflexion, or is it always inconclusive and do you have to resort to the table
Thanks so much for this. Your like my second tutor but free one. Thanks so much will be watching your other videos as well. You answered all of my questions in this video Thanks again
Hi peter, you are an amazing teacher. I wanted to ask that why do you put the value of the x cordinate in the second differential i.e dy2 divided by dx2.
That is the point we are testing and d^2y / dx^2 gives the rate of change of gradient and from this (see previous tutorial) we can tell the nature of the stationary point.
losblancos99 You probably did something wrong when using the first differential. I used the first differential method and I got (-2,-63) as a minimum point.
hi i got a question to do but ive never done it with only two numbers...i hope you can help....here goes....what are the stationary points of this function x3 (cube)- 6x2(square)
As you said instead of zero we can try to -2 but if we take the -3 on left side and -1 in right wont the value -3 out number the -2 which is out of range ?
Hi , I also divided by 30 and was left with 2x^4 + x^5... how do you factorise from this ? Thanks for the vids If I pass my degree exam will deff be leaving a nice donation :)
Jasmine liketheflower either 2+x is 0 or 30x^4 is 0 because the whole expression is 0 so anything times 0 is 0 so at least one of them has to be 0 for the expression to be equal to 0 so x^4 has to be 0 because 30 times 0 is 0 and that times 2+x is 0
Thanks you very much for saving my mathematics grade
Thank you once again for saving my maths grade!!!
I dont understand the nature table part. Why does the 30x turn to negative but the 60x not?
Ahad because x=-2 so
60 x (-2 x -2 x -2 x -2) = positive
BUT for
30 x (-2 x -2 x -2 x -2 x -2) = negative
Zat make sense?
hey I donated £100 to you, you're the best tutor ever and You saved my alevel maths
Ajjaa Ajajjaj how did you do that?
Liar
Don’t lie
This was really helpful, thanks!!! I'd seen other videos but they had less complicated equations so it was good to see a more complex one done. I might just pass my exam now so thanks!! Also, you're a great teacher, really clear explanation.
Fhck your fly in your pic
Crazy that it's been 11 years since he made this AMAZING video and he's still liking our comments. Legend.
Really needed this, I've got my A-level mocks in a couple of days and was struggling to get my head around stationary points, cheers
Your an amazing teacher
Thanks.
You should have corrected him and said you're* :'(
savage
This has helped me alot. I didn't know anything and I had finals in 3 days
your english teacher wasn't
Teaching myself A level maths and your videos are so useful! Could you recommend a site or page for example questions or questions to practice your lessons?
I haven't watched more helpful videos than these ones!! You have a very loyal fan indeed!
Lize van Dyk Welcome.
thank youuuu i have an exam tomorrow and u just helped me thanks!!!
Thank you for the video! Just a quick question, can you prove that a stationary point is the point of inflection when a small decrease/ increase in x means that dy/dx is positive on both sides? Thank you!
Thank you so much for this tutorial, you've explained this so well and I've really understood this now! Thank you once more!!!
@thezohan2112 You could look at the gradient either side. I show this in other tutorials on stationary points. Have you seen them? Look on my index on the homepage of my website if not.
Such an awesome explanation and the visuals really help. Thanks!
Hi,
Do I need to know both the differential methods or can I get away with just knowing one?
Thanks
thank you!! such a clear, straightforward no nonsense way to explain this :)
You cannot say with certainty that when d2y/dx2=0 that the point is a point of inflexion so yes refer to the table.
one question. How did you determine the shape of the graph at last part ?
Thank you so much for this! It's really helpful and better than the way my teacher had explained it before. I have liked your video and shared your channel with a lot of my friends, hope that it helps! You're awesome, thanks again!
+Farris Thank you
at 6:29, with 60x^4 when x=-1, how does that equal 60? I got that it equals -60 because -1^4 is -1, and 60*-1 is -60. Please can you explain?
-1 x -1 x -1 x -1 = 1 not -1. I suggest you think of it as (-1)(-1)(-1)(-1) especially if using a calculator
what would you do instead of the double differentiation??
If the second derivative = 0, then it is a point of inflection (meaning it changes from concave up to down or vice versa). The result is not inconclusive 4:56
Sorry to say but it is until you do the table. If you were to have say y=x^4, dy/dx=4x^3 and when dy/dx=0, x=0, y=0, d2y/dx^2 = 12x^2 and when x=0, d2y/dx^2=0 but it is a min in this case not a point of inflexion.
Just a random query, what is the most effective way to make notes for maths?
cleared my doubts, thank you very very much!!
can't you say that when d2y/dx2=0, the nature of the sationary point is that it's an inflexion, or is it always inconclusive and do you have to resort to the table
what is the apps for editing this video
you can use the fact that when d2y/dx2=0 and d3y/dx3 doesn't = 0 the stationary point is a point of inflexion?
Thanks so much for this. Your like my second tutor but free one. Thanks so much will be watching your other videos as well. You answered all of my questions in this video Thanks again
+Rohit Pai (rodude123) Thank you for your comments. Any support you can give is always appreciated is you find these of benefit.
You welcome
Hi peter, you are an amazing teacher. I wanted to ask that why do you put the value of the x cordinate in the second differential i.e dy2 divided by dx2.
That is the point we are testing and d^2y / dx^2 gives the rate of change of gradient and from this (see previous tutorial) we can tell the nature of the stationary point.
@@ExamSolutions_Maths Thank you.
Cool, that's what I like to hear.
Explained it better than our A-Level teacher in just a few minutes - and this is from 2010
At 8:30 I tried the 1 differienational method and got the point (-2,-63) as a maximum point. Help please!
losblancos99 You probably did something wrong when using the first differential. I used the first differential method and I got (-2,-63) as a minimum point.
Wise Fool Your comment is a bit late as I already did my exam two days ago but I'm fine now
losblancos99 Haha well I have mine coming up on Wednesday!
Yeah I got another Maths exam on that day too. I am doing C2 OCR
losblancos99 I see. I'm retaking exams from my edexcel module.
This helped so much! Thank you!
+Alys McCarthy That's good. I am pleased you found it helpful
hi i got a question to do but ive never done it with only two numbers...i hope you can help....here goes....what are the stationary points of this function x3 (cube)- 6x2(square)
Thank you very much, that really helped!
As you said instead of zero we can try to -2 but if we take the -3 on left side and -1 in right wont the value -3 out number the -2 which is out of range ?
THANKS YOU ARE THE GOAT 🙌🙌
Awesome explanation 🙌
I really love this...Thanks
So much respect for you, sir.
@daniel bonello you factorize the x^4 out
My concepts were under attack; this video saved them.
10 years later and the video is better than 2020 ones
Thank you so much this helps a lot
@wearemce2010 differentiate, equal it to zero, factorise and solve.
When you add x= -2 into d^2y/dx^2 it comes to -4320, did i do something wrong because this doesn't make sense!
Thank you so much
@allstarjai1010 You can do that.
Thanks a lot bro, u helped heaps with my methods revision
That's good, thanks for watching, I hope it went well for you.
THANK YOU SO MUCH!!
What if one of the (x) is zero. What do you do then..
I learnt you got to work with (0.5) and (-0.5)?? Though I am abit unclear with this.
Pardon?
Monica J still waiting
Hi ,
I also divided by 30 and was left with 2x^4 + x^5... how do you factorise from this ?
Thanks for the vids If I pass my degree exam will deff be leaving a nice donation :)
Great explanation
THANK YOU SO MUCH SIR YOU ARE THE BEST!!!!
Thanks for your support.
why does x = 0 when finding the second differential?
+Ryan Goburdhone It was the point we found at 1:57.
How did you get x as 0
Sorry.. can i know why we need to to make that table??
so good!!!
How did he get the 2 + x in the brackets?
He factorised it. You can just use a calculator for that.
thank you!!!
hi you are such a great teacher but for the first question I got -703, what did I do wrong
Not at all. For example take y=x^4. when x=0 it is a min
THANK UUUU
Legend
how does x^4 = 0 .sorry I don't understand
Jasmine liketheflower either 2+x is 0 or 30x^4 is 0 because the whole expression is 0 so anything times 0 is 0 so at least one of them has to be 0 for the expression to be equal to 0 so x^4 has to be 0 because 30 times 0 is 0 and that times 2+x is 0
Awesome
hey ive got a math test tomorrow wish me luck cya
A bit late but I hope it went well.
While plotting the graph 'This is not to scale but I just want to illustrate a few points' Slipping sneaky calculus joke in there?
I have my math methods test tomorrow wish me luck
Best wishes Lino
Can't u just say that when x=0 d2y/dx2 =0 and therefore it is a horizontal point of inflection?
how to find Stationary point
F(x) = x^4 - 1/2x^2 +1
Callux? 🤔
i am very sry but this made everything more complicated. Is there an easier way?
Please why do you differentiate twice
This is fucking brilliant wow thank you
can you*
thanks lmaoooooooooo ez 100
i dont fucking understand anything you dont even explain you just do examples
because this is a example video. he has videos where he actually explains the concepts. you can watch them instead.
Thank You SO much