You explain SOOO much better than my school teacher. I wish I had a teacher like you who actually explains the reasoning behind something and not just tells us to memorize it :'))
So, basically, in summary. Differentiate the equation of y, find the x co-ordinates, find the 2nd differential, then plug x back into the 2nd differential to see if it's min or max?
@ExamSolutions Thanks, brilliant explanation. But which method would you most recommend, the 1st or the 2nd? My teacher at school uses the 2nd method and you seem to do in your other videos so im guessing its the 2nd.
Hi there! I don’t understand why we take the x value of the stationary point and plug it into ‘d two y / dx squared’ as isn’t the rate of change of the gradient here already zero since it is stationary at that value of x? It would be much appreciated if anyone could please explain.
Can u plzz tell me why do we double diffrentiate.....??? and why do we have to use the first method if d^2y/dx^2 = 0 ???!!! wats da diffrence..! Thanks a lot anyways..!
Instead of doing the second derivative to find the type of stationary inflection it is (maximum, minimum) can you make a sign diagram and take a number before and a number after to check sign
when the curve is greater than x^3, where you can't use a quadratic equation to work it out like 4x^4 + 3x^3 - 5x^2 + 6x - 2. how would you differentiate that?
hi! i have a question.. so if the 2nd differential is equal to zero, that means that there is no change in the gradient right ? and we know that the only graph that has no change in the gradient is a linear equation.. so if f''(x) =0 would that mean the starting equation is linear ? and if not, then why. i'd really appreciate it if someone explained it to me!
Thank you and hope you continue to make progress with them. All the best.
12 years later and this video is still purely helpful.
old is gold :)
@@ExamSolutions_Maths agree 💯
10 years later and this video is still super helpful. thanks!
Many thanks Erica. One of the early videos.
Great how you explain the theory behind it. Most teachers would just say: Less than 0 is max. Greater than 0 is min
yea
And that my friend, is so true. Some teachers don't know how important it is to understand the concept properly
good luck to everyone for their exam tomorrow
You explain SOOO much better than my school teacher. I wish I had a teacher like you who actually explains the reasoning behind something and not just tells us to memorize it :'))
@Bemz94 Yes I would generally use the 2nd method but I showed both methods for completion
@mazin2892 best to drop back to the gradient method using a table and test the gradient either side of your stationary point.
Cannot thank you enough for this! You're amazing!
Thank you very much still it is helping after 10 years
So, basically, in summary. Differentiate the equation of y, find the x co-ordinates, find the 2nd differential, then plug x back into the 2nd differential to see if it's min or max?
@ExamSolutions Thanks, brilliant explanation. But which method would you most recommend, the 1st or the 2nd? My teacher at school uses the 2nd method and you seem to do in your other videos so im guessing its the 2nd.
your videos are quality! Thankyou :D
Thanks. Great video
Thanks you so much
Funny things are same question came out in my exam.
Thanks for video
@CBullock1994 Cheers
Could you please explain why a second differential of 0 could be a minima, maxima, or point of inflection?
Hi there! I don’t understand why we take the x value of the stationary point and plug it into ‘d two y / dx squared’ as isn’t the rate of change of the gradient here already zero since it is stationary at that value of x? It would be much appreciated if anyone could please explain.
Can u plzz tell me why do we double diffrentiate.....??? and why do we have to use the first method if d^2y/dx^2 = 0 ???!!! wats da diffrence..! Thanks a lot anyways..!
Instead of doing the second derivative to find the type of stationary inflection it is (maximum, minimum) can you make a sign diagram and take a number before and a number after to check sign
Yes you can - see my website for that tutorial
for the second method how do you find out if it is point of inflection
when the curve is greater than x^3, where you can't use a quadratic equation to work it out like 4x^4 + 3x^3 - 5x^2 + 6x - 2. how would you differentiate that?
Third derivative maybe
Thanks
@aldar007 Good luck - hope it goes well for you.
hi! i have a question.. so if the 2nd differential is equal to zero, that means that there is no change in the gradient right ? and we know that the only graph that has no change in the gradient is a linear equation.. so if f''(x) =0 would that mean the starting equation is linear ? and if not, then why. i'd really appreciate it if someone explained it to me!
What if they ask you in the exam whether it is a maximum minimum or inflection. Would that mean you cant do this method?
We can use either of the 2 methods right?
@aldar007 Pleasure
Fucking soo god tutorial
Better than my school teacher