Complex Numbers : Modulus and Argument | ExamSolutions
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- Опубліковано 6 лют 2012
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Complex numbers - modulus and argument. In this video, I'll show you how to find the modulus and argument for complex numbers on the Argand diagram.
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Thank you so much! I was unsure how the awnser of a problem where I have to find argument of a problem simply indicated as being -3i (so the real axis (Re) is 0), but you explained it perfectly in how the angle is measured from different segments. Because the point is in the 3pi over 2 line, the angle is pi over 2 (I know it's shown as a minus, but my teacher always siad an angle can never be negative so that's what had me confused and I THINK I understand it now, thanks to you). I would never have even known how to ask about this, but you awnsered it so perfectly, thank you sooo much!
Make sure your calculator is in radians mode. I suspect it is in degrees mode.
How do I take the calculator to radians mode in casio fx-991
@@imranalif4792 Shift > Menu > 2:Angle input > 2: Radian
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Chloe Millar
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Thank you for your support
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it was very helpful thank you
Great vid! Another care should be taken when talking about Arg(z) and arg(z).
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Glad it's useful to you!
how do you know where to label the acute angle (alpha) on the line of Z
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Cheers
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How was the exam
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question? do you require to keep your calculator in radians mode all the time for complex numbers?
Thanks a lot, i was reading on my textbook and didnt understand much but you got me in 17min thanks!!
No problems - Thanks for using the website.
Thank you for thid interesting video
thank u very much for your help :)
Sir i need immediate help i want to know where this method has been taught it is not in books i did it in my schl but teachers disagreed..
Big help
Thanks
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And you
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thank you very much...
Thanks Alot! but i have a question if u dnt mind sir!
In this time 3:53-3:56 u said a word i heard it "quargens" what is it?
Yes
in the third quadrant , why did you put negative pie? thx
Thank you sir
this is still helpful even after 8 years
Maths is timeless.
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Good to hear. Best wishes.
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Thanks
Thanks, this was helpful.
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You're welcome
What program was used to create this and what was used to “record” the program?!
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nice tutorial
THANKS A LOT. one more doubt. how we get the value 1.17 rad for tan inverse 12/5. please elaborate. i cant able to get that. please and thanks a lot
It's much easier to just consider this rule:
argz=tan^-1(y/x) (+/ - pi for fourth and third quadrant respectively)
i.e. Add pi if z on the argand diagram falls in the top left quadrant.
Subtract pi if z on the argand diagram falls in the bottom left quadrant.
yes
Bruh...u explained this within 16 mins and 49 seconds and made me understand while my teacher explained it over an hour and i still couldn't understand.
Please replace my teacher, she goes on about how slow your videos are while rushing through and messing everything up.
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Thank you so much!!! This was explained really poorly in my lectures
Hi
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And you
Yes I will but not till later this year now.