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was it really neccessary to go all that long procedure instead of just using the de morgans theorem ...i was confused on the way yet it was jst short
Thanks !
Thank you
Please if one is asked to complement or implement a logic function, is it just to double complement the function(please help anyone).
Tq..
According to de-morgons theorem A compliment or B compliment =A. B whole compliment. To kya hum direct put nhi kr skte
At the end u totally confused us and done nothing, in ur previous video ur explanation was good but in this u done nothing accept confusing ..
X=(A'+B)C'Solve it plz
X =(A'+B)C'(X')'={[(A'+B)C']'}' =[(A'+B)'+C']' =[(A'+B)']'.(C')' =[(A')'.B']'.C =(A.B')'.C
I'm uncertain that you know how to use de-Morgans theorem your calculation didn't make any sense nor was it explain efficiently enough to the point that you left me confused
Exactly, quite inconsistent with the first video
At the end u haven't explained well... But thanks anyway
Thanks for the feedback.
was it really neccessary to go all that long procedure instead of just using the de morgans theorem ...i was confused on the way yet it was jst short
Thanks !
Thank you
Please if one is asked to complement or implement a logic function, is it just to double complement the function(please help anyone).
Tq..
According to de-morgons theorem A compliment or B compliment =A. B whole compliment. To kya hum direct put nhi kr skte
At the end u totally confused us and done nothing, in ur previous video ur explanation was good but in this u done nothing accept confusing ..
X=(A'+B)C'
Solve it plz
X =(A'+B)C'
(X')'={[(A'+B)C']'}'
=[(A'+B)'+C']'
=[(A'+B)']'.(C')'
=[(A')'.B']'.C
=(A.B')'.C
I'm uncertain that you know how to use de-Morgans theorem your calculation didn't make any sense nor was it explain efficiently enough to the point that you left me confused
Exactly, quite inconsistent with the first video
At the end u haven't explained well... But thanks anyway
Thanks for the feedback.