Only one question in and it is miles better than how my IT professor does it. I am grateful because you've shown why a certain step is made instead of just showing the step and skipping the explanation behind it, unlike how my professor does it. It really helps to understand the procedure instead of hunting in the dark.
This helps sooo much than the online lectures that we are having right now during the Pandemic Staff having mic problems, connection issues on my part or inaudibility, so your little video really helped me out Thanks a lot :)
Thanks a lot for this. I was completely lost before, and watching the first one I was like "HUH?!" but by the 3rd example I was able to simplify all on my own! I still need more practice, but again this REALLY helped me.
I slightly didn't understand on the first example, I only understood the chart, but when you began the 2nd example it clicked. Thank you so much, it's hard to understand this on a sheet.
(2:37) A small cause of confusion there! For most people, the boolean Absorption Law is the theorems: A ∙ (A + B) = A and A + (A ∙ B) = A The theorem he is referring to is one of the two that make the the Law of Common Identities: A ∙ (ㄱA + B) = A ∙ B and A + (ㄱA ∙ B) = A + B Anyways, for anyone interested, here is a different and somewhat more detailed solution to the second exercise (I use Distribution): ㄱA ∙ ㄱB ∙ ㄱC + ㄱA ∙ ㄱB ∙ C + ㄱA ∙ ㄱC Given ㄱA ∙ (ㄱB ∙ ㄱC) + ㄱA ∙ (ㄱB ∙ C) + ㄱA ∙ ㄱC by Association ㄱA ∙ (ㄱB ∙ ㄱC + ㄱB ∙ C + ㄱC) by Distribution ㄱA ∙ ([ㄱB ∙ ㄱC + ㄱB ∙ C] + ㄱC) by Association ㄱA ∙ ([ㄱB ∙ {ㄱC + C}] + ㄱC) by Distribution ㄱA ∙ ([ㄱB ∙ {C + ㄱC}] + ㄱC) by Commutation ㄱA ∙ ([ㄱB ∙ 1] + ㄱC) by Complement Law ㄱA ∙ (ㄱB + ㄱC) by Identity Law (aka Intersection Law)
bro, im terrible at maths beyond imagination, but after watching you, i solved my very first Boolean algebra which was this question 5:52 bro, you might not understand, this is way too big cannon event for me in my life. It's a miracle
thanks so much for this, very clear explanation also, i personally the expression below to my "cheat sheet". while its technically already in the cheat sheet, having this version made things easier for me AB+AB'=A
In the first example. What if we decided to use the A+1=1 rule and apply it to A.C.(1)+Ā and we get A.C.(1) Then we will have AC as an answer Will that be correct???
3:43 So in this answer *Not A AND C*, where does the B go when you write a logic circuit? You just don't include it into the circuit diagram because it isn't important? Same thing for 9:00, would I leave D out of the circuit diagram?
(A+A')(A+B) -> Distributive Law (1)(A+B) -> Complement Rule A+B -> (Distributive) A+B is the final answer That's the OR Redundancy Law. I learned it here: ua-cam.com/video/kcekwNJRAHM/v-deo.html
The video said it's Absorption Rule but it's actually Redundancy Rule: -So basically, you use Absorption for 3 terms(but 2 terms are same). ---->Like A+(B*A) = A -Redundancy for 3 terms(but 1 term is a complement of another). --->Like A+(B*A') = A+B
It is factored out as a common variable along with A from the terms: A.B.C and A.notB.C. Since you bring the A and C out of those terms the result is AC(B+notB)
@@bruh-lt7hb I think it's because of the Idemponent Rule. A+A = A A*A = A In the example: C+C = C A+A = A I also wonder if the concept of Multiplication taking precedence over Addition even works with Boolean Algebra.
Thank you so much firstly, also just wondering: what level of education is this aimed at? Is it at GCSE (High school) or A-level(college) or university/degree? It was a bit challenging for me so that's why. I'm in GCSE (High school right now).
You're so much better at explaining this than my teacher. Thank you from this video I understood what I couldnt understand in class for like 3 weeks.
InstaBlaster...
youtube be like that
@@DarkArcticTV cri
Same
True
If you are reading this, and have a test coming up, please please please, just remember that chart he has, I made an A due to that
So kind of you. Thank you so much
@Mercury Si we have this in our syllabus.... I am in high school
I got A bar :(
yep! budy
@Mercury Si we have this in our syllabus .... and I am in high school
Man, I have Digital Electronics exam tomorrow but this guy's chart is a gem here. Thank you, man.
You just crushed my teacher on teaching this material. Thank you SOOO much!!
Fuck!
@@billionairediarie are you the teacher 😂
@@bishnugogoi9729 Hahaha
Ujefwwyw
Bishnu Gogoi the student has become the teacher
Only one question in and it is miles better than how my IT professor does it. I am grateful because you've shown why a certain step is made instead of just showing the step and skipping the explanation behind it, unlike how my professor does it. It really helps to understand the procedure instead of hunting in the dark.
❤
Hyy how are you ❤
thanks man! it was really confusing topic but you explained it very nicely.
This helps sooo much than the online lectures that we are having right now during the Pandemic
Staff having mic problems, connection issues on my part or inaudibility, so your little video really helped me out
Thanks a lot :)
Thanks a lot for this. I was completely lost before, and watching the first one I was like "HUH?!" but by the 3rd example I was able to simplify all on my own! I still need more practice, but again this REALLY helped me.
Well explained
ive just joined a computing class halfway through the semester and I really struggled on learning this. thanks so much
The transformation of the same solution into various forms in Problem 2 would be really helpful for Multiple Choice Questions..... Great work!!
Very clear and detailed explanation about simplifying the logical functions. Thanks a million.
I slightly didn't understand on the first example, I only understood the chart, but when you began the 2nd example it clicked. Thank you so much, it's hard to understand this on a sheet.
not alot of videos help but let me say this helped another lost soul thank you brother
didn't really understand at class, thanks to this video I got more insight about this and learned new tidbits.
To remember demorgans remember the saying: Break the line change the sign
Thankyou so much man !!
Thanks alot.
legendddd
whhha... thanqqqqqqq
It's great man, thanks bro❤😂
(2:37) A small cause of confusion there! For most people, the boolean Absorption Law is the theorems:
A ∙ (A + B) = A and A + (A ∙ B) = A
The theorem he is referring to is one of the two that make the the Law of Common Identities:
A ∙ (ㄱA + B) = A ∙ B and A + (ㄱA ∙ B) = A
+ B
Anyways, for anyone interested, here is a different and somewhat more detailed solution to the second exercise (I use Distribution):
ㄱA ∙ ㄱB ∙ ㄱC + ㄱA ∙ ㄱB ∙ C + ㄱA ∙ ㄱC Given
ㄱA ∙ (ㄱB ∙ ㄱC) + ㄱA ∙ (ㄱB ∙ C) + ㄱA ∙ ㄱC by Association
ㄱA ∙ (ㄱB ∙ ㄱC + ㄱB ∙ C + ㄱC) by Distribution
ㄱA ∙ ([ㄱB ∙ ㄱC + ㄱB ∙ C] + ㄱC) by Association
ㄱA ∙ ([ㄱB ∙ {ㄱC + C}] + ㄱC) by Distribution
ㄱA ∙ ([ㄱB ∙ {C + ㄱC}] + ㄱC) by Commutation
ㄱA ∙ ([ㄱB ∙ 1] + ㄱC) by Complement Law
ㄱA ∙ (ㄱB + ㄱC) by Identity Law (aka Intersection Law)
Thank you !!
thank you because i was looking at it and i was like what this was not it. But thanks for clarifying
Your way of teaching is the best. It is easy to follow and understand. You just made my work easier.
Thank you very much . This video helps me a lot , for my studies. so again Thanks a lot .I'm from Sri Lanka
bro, im terrible at maths beyond imagination, but after watching you, i solved my very first Boolean algebra which was this question 5:52
bro, you might not understand, this is way too big cannon event for me in my life. It's a miracle
Very good explanation, and nice English too. You deserve more subscribers
man THANK YOU i've been trying to understand this for the last hour and watching your video just helped it click.
thanks so much for this, very clear explanation
also, i personally the expression below to my "cheat sheet". while its technically already in the cheat sheet, having this version made things easier for me
AB+AB'=A
what an absolute mad lad,really helps me a lot
you're still saving lives after 5 years even !!!!!
MUCH LOVE MAN
Kind of wish my online course explained it this way. Thanks :)
Thank you!!! I was so confused before this!!
Happy to help!
Dary is a comedian hle🙌🙌🙌😂😂😂I've been laughing through the whole video
من العراق
Excellent explanation 🎉❤
Wow.. this guy is amazing for real💯
Thanks man! I appreciate this walkthrough. My CS Final exam in uni is just 2 days away and I was potatoes in this topic
Thanks man really helpful straight to the point.
Didnt get what my professor was saying AT ALL, then you simply said "and" "or" and it all just magically clicked. W
you are great you solved my doubt
of my first class
Amazing Video thank you sm, this really helped me with my Electrical Engineering Class
I was the 4k person to like the video ;) thank you very much
Meu mano você me ajudou muito a entender como funciona e eu agradeço muito por isso, abraços do Brasil!
me salvou tambem!!
First question: the class
Second: the homework
Third: the test
In all seriousness thank you it helped alot
this will really go a long way in me understanding it
Thanks for making this logic so simple for uss❤️❤️
3:47 don't get the last 2 lines and how did he use the absorption rule
A'B' is common in both variables....So he took A'B' and left (C'+C)...
Thankyou sir😊😊😊
It helped me a lot !!
Well explained ! ❤️❤️
thank you for this video, it really helped me a lot.
very interesting, helped me a lot to clear my concepts, thank you, sir.
Thank you for making something that was difficult for me to understand, understand fully well now thanks to your lesson.
thank you
Thanks so much , this actually helped alot
Glad it helped
This is the 1st time I saw your video..... And I admit that your explanation is just awesome..... Enjoyed during your explanation.....
thank u so much
it will really help me in tommorrow's exam
i love how my lecturer just expected people to be able to do this
Here for the same reason brotha lol
Excellent demonstratation of Boolean, was a nice & quick refresher!
AMAZING MAN SO HELPFUL .......GOOD
I'm grateful to you sir, my utmost veneration to you. I've perceived well
Thank you 😊❤️ i understand it very easily 😊
Thank you 😊
Loved your explanation.
Thank you very much for this video.. really helpful
Imagine watching this video after your exam and then see that one of your exam questions was actually in this video 🙃
In the first example. What if we decided to use the A+1=1 rule and apply it to A.C.(1)+Ā and we get A.C.(1)
Then we will have AC as an answer
Will that be correct???
Thank you very much great work😀😀
Nice concept sir
Thanks dude, your video helped me a lot!
This was an excellent exercise, thank you!
Amazing Explanation... Thank you
Wow, you made me understand this so easily
3:43 So in this answer *Not A AND C*, where does the B go when you write a logic circuit? You just don't include it into the circuit diagram because it isn't important?
Same thing for 9:00, would I leave D out of the circuit diagram?
B doesnt connect to anything if the simplifed expression doesnt include that anymore. Same for D @9:00 mark.
Thanks a lot, this is very helpful for nut brainer like me
thank you it benefits me a lot while studying
Thanks brother 😊 i from India
You are very nice teacher 👏😊
Thanks a lot sir after 3 hours my preboard exam will held 🤓
I follow you from Egypt
So helpful ❤❤❤😍😍😍tq sooooooooo much
Very helpful, thank you sir!
Great example of Discrete Math course that i had, well explained
Nice explanation dude...keep it up..👍👍
excellent exercises thanks
Exam on this in CMPEN 270 at PSU thanks mate
Thank you sooo much sir. I hope I can solve all problems from now, just practice...
Nice explanation
absolute legend thank you soooooooooo much
thank you so much sir i really learned it well but can you tell me what does that dot mean between letters for example "A.B" ?
if the given is (A+C+D) (A+C+D') (A+C'+D)
can I distribute (A+C+D) to (A+C+D') (A+C'+D) directly?
Question, how is A + A̅B = A + B?
Need elaboration, thanks.
Redundancy Law
(A+A')(A+B) -> Distributive Law
(1)(A+B) -> Complement Rule
A+B -> (Distributive)
A+B is the final answer
That's the OR Redundancy Law. I learned it here: ua-cam.com/video/kcekwNJRAHM/v-deo.html
The video said it's Absorption Rule but
it's actually Redundancy Rule:
-So basically, you use Absorption for 3 terms(but 2 terms are same).
---->Like A+(B*A) = A
-Redundancy for 3 terms(but 1 term is a complement of another).
--->Like A+(B*A') = A+B
at 1:43 where does the c at the right go?
It is factored out as a common variable along with A from the terms: A.B.C and A.notB.C. Since you bring the A and C out of those terms the result is AC(B+notB)
@@bruh-lt7hb
I think it's because of the Idemponent Rule.
A+A = A
A*A = A
In the example:
C+C = C
A+A = A
I also wonder if the concept of Multiplication taking precedence over Addition even works with Boolean Algebra.
so nice thanks
Excellent teaching sir
Tnq so much sir
Thanks for this. Lesson boy. Expert
If you have D’(AB + B’) how does this get reduced
Thank you so much firstly, also just wondering: what level of education is this aimed at? Is it at GCSE (High school) or A-level(college) or university/degree? It was a bit challenging for me so that's why. I'm in GCSE (High school right now).
how can we reach you for tutoring?
Thanks for sharing it with us
ma teacher sent me here, he sent me to the right place!
haha. ikr
So, can you start with any term, and use it a manipulate any other term?
from example number 3 what happened to the A.D
Great job 👏👏👏
How to simplify Not A * C + Not C * A? Thanks
can someone explain to me why on the first problem letter B disappeared on the simplified expression? thanks
Very helpful. Thanks
It so helpful .Thank you!
Bro u are awsmmm
thanks very much I understand it easly
Sir reply please.......
In boolean expression(1+xy)=.........?
1 (TRUE OR ANYTHING = TRUE)