This the answer and explanation I've been looking for, I wonder what will happen to the diagram if the temperature double in isothermic process. Now I can sleep, thank you sir ❤
I don't understand how after expansion the pressure decreases? Shouldn't the pressure always equalize with the atmosphere because other wise the piston will either go up or down?
I don't understand how p*V stays constant in the example if the Volume increases. Wouldn't the pressure have to sink? and isn't in reality the opposite the case? As I understand the example by increasing the temp we increase the inner pressure which pushes the piston up, thus increasing the Volume, with the pressure either staying same or increasing too.
Thank you sir for this wonderful lecture. I really enjoyed watching it. I've a small doubt. How can heat source does work on piston without increasing kinetic energy of gas molecules ? Work can only be done by the gas molecules when they collide with each other and with container walls then kinetic energy will be transferred from one molecule to other but this can happen only if we heat the container. When we heat the container it is thus obvious that kinetic energy of the molecules will increase and then they do work on the piston? In isothermal process when there is no temperature difference how can there be heat transfer ?
Just like when you learned calculus for the first time, you need to imagine the system and surroundings as differing in temperature by a very small (differential) amount. and also the piston is displaced by a differential amount. in real life, there is no such thing as an isothermal process. that is why this class is so confusing.
Hi, thank you for your video. I can not understand basic thing - why when you apply heat, temperature remains the same? How it is possible? This basic thing does not clear for me. Thank you.
When heat is supplied, a lot of it is used to make and break bonds (break if heat is absorbed and make if heat is removed). Thus temperature does not change immediately and it remains constant for a while.
Hopefully you worked this out by now (5 months late) but in case you haven't/ if anyone else thinks this. It's just a simple re-arrange of the E=Q+W formula for if E = 0 Q + W = 0 (subtract W from both sides to get Q on it's own) Q + W - W= 0 - W (then just simplify W-W = 0) to end with Q=-W
Man , I really thank you from my heart , u r the best one who teach really the best
Thank you. Clear and Precise. Sending love from the Philippines.
thank you so much , I come from Taiwan , after your explanation I totally understand how this works
you simply the difficulty to ease .
you explain it so well !
Great lecture and awesome lecturer :)
superb lectures... awesome way of teaching
Beautifully explained
Great teacher osm lecture.all my doubts are clear ❤️
This the answer and explanation I've been looking for, I wonder what will happen to the diagram if the temperature double in isothermic process. Now I can sleep, thank you sir ❤
AK-47 on point, cheers brother
thank you very much, it was supper clear
This Guy's Great!!!!!!
Good service
you are amazing! thank you!
Thanks!! Glad you enjoyed the lecture!
Great lecture
nice and clear
sir if ke. isnt gonna increase then how pressure will increase
I don't understand how after expansion the pressure decreases? Shouldn't the pressure always equalize with the atmosphere because other wise the piston will either go up or down?
thanks for the amazing explination , watching this before my exam with 8 hours and i understand nothing
did u pass?
I don't understand how p*V stays constant in the example if the Volume increases. Wouldn't the pressure have to sink? and isn't in reality the opposite the case?
As I understand the example by increasing the temp we increase the inner pressure which pushes the piston up, thus increasing the Volume, with the pressure either staying same or increasing too.
and with both volume and pressure increasing the product can't stay a constant. The pressure would have to sink while the volume is rising
Thank you sir for this wonderful lecture. I really enjoyed watching it. I've a small doubt. How can heat source does work on piston without increasing kinetic energy of gas molecules ? Work can only be done by the gas molecules when they collide with each other and with container walls then kinetic energy will be transferred from one molecule to other but this can happen only if we heat the container. When we heat the container it is thus obvious that kinetic energy of the molecules will increase and then they do work on the piston? In isothermal process when there is no temperature difference how can there be heat transfer ?
Just like when you learned calculus for the first time, you need to imagine the system and surroundings as differing in temperature by a very small (differential) amount. and also the piston is displaced by a differential amount. in real life, there is no such thing as an isothermal process. that is why this class is so confusing.
great explanation thanks
Hi, thank you for your video. I can not understand basic thing - why when you apply heat, temperature remains the same? How it is possible? This basic thing does not clear for me. Thank you.
When heat is supplied, a lot of it is used to make and break bonds (break if heat is absorbed and make if heat is removed). Thus temperature does not change immediately and it remains constant for a while.
Sir physics isothermal process work equation please explain
all i hear is system, But nice work sir :)
Don't know why but AK reminds me of The Wolf of Wall St (Jordan Belfort)
thanks
anikoustos2 welcome
shouldn't it be Q=W?? not -W
no, its fine the way it is.
I am Indian
shouldn't it be Q=W?? AND Y IS it Q=-W;
Hopefully you worked this out by now (5 months late) but in case you haven't/ if anyone else thinks this. It's just a simple re-arrange of the E=Q+W formula for if E = 0
Q + W = 0 (subtract W from both sides to get Q on it's own)
Q + W - W= 0 - W (then just simplify W-W = 0)
to end with Q=-W
some people consider change in internal energy as Q - W, where W as positive is work done by system, not work done onto system
KHAAAAAAÀAAAAAAAAAAAAAAAAANSTANT😁😁😁😁😁😁😁😂😂😂😂😂
IT'S KHAAAAAAAANSTENT YOU KNOW !!!
Bokkaa
the video could have completed in half the time if it was just constant instead of "KHAAAAAAANSTENT!!!!!!!
or if you have used 2x speed.
not impressed nicetry
not impressed nicetry