Ok I am not sure of this but I will answer since nobody did in 3 years. You basically do the same except for the mechanical advantage, but when u get the Force BB you multiply by the sin(x). Why? Because when it's at 90 degrees the torque will be the maximum(sin(pi/2)=0) and if you move upwards the force will be smaller but the angle bigger, while if u move downwards the force will be smaller and so the angle as well. This also depends on the angle the exercise gives you and if it is at equilibrium.
Hoe do I calculate the force needed by the bicep is the forearm is not at a 90 degree angle
Ok I am not sure of this but I will answer since nobody did in 3 years.
You basically do the same except for the mechanical advantage, but when u get the Force BB you multiply by the sin(x).
Why?
Because when it's at 90 degrees the torque will be the maximum(sin(pi/2)=0) and if you move upwards the force will be smaller but the angle bigger, while if u move downwards the force will be smaller and so the angle as well.
This also depends on the angle the exercise gives you and if it is at equilibrium.