Calculate the magnitude of the mechanical advantage that the (Achilles tendon)foot as a lever provides a human body with in the walking. D = 16 cm; d = 4 cm.
Excellent video, you're not only saving my physics 1 course, you're also presenting biomechanics in a fantastic manner. Thank you for your work. Commenting to prop up your content :D
I believe you said the effort arm (from the achilles tendon) to the axis of rotation is perpendicular, but you did not draw it perpendicular to the effort force (line of pull of the muscle). You drew it on the horizontal. Other than that, I genuinely like your video.
It starts out nearly perpendicular, but as you push yourself up on your toes, the angle will no longer be perpendicular. Therefore the "efficiency" of pushing yourself up on your toes diminishes as the angle changes.
Thank you for an idea of calculating force on Achilles Tendon. I probably should figure the same thing for Japanese martial arts. Since we use earth's gravity, the calculation of your way would not be valid. I have been too lazy to figure it out. Thanks for motivating me.
@@MichelvanBiezen Thank you for your reply. You would think so but we use gravity and wave from core of our body. So almost no stress on Achilles tendon. It is relying on bone structure not on muscle. Japanese ancient martial arts were so sophisticated that they can fight so long hours without fatigue. For instance, we just use opponent power by using crankshaft in our body. There are so many things I need to consider. As I write down this, I realized that Achilles tendon is not pulled. It would be actually stretched when we jump forward. Anyway you gave me a good hint to think furthermore. Thanks again!
Hi Mr. Michel van Biezen . I calculated that d2 is 7.42cm, i used the seno law to got it. I do not understand why you got that d2 = 7*cos(5°) . Could you explain with details?, Thanks you veru much.
Excuse me Sir, how about the weight of the foot? If we take that in to account (since it would provide a counterclockwise torque), Force A should be smaller than what we have estimated, right?
Once you have calculated Fa, then you can use the "sum of the torques" technique to solve for any other unknown. (in this case you would move the pivot point to the toe).
where is the gravity of body? I see the similar comment down below. But, isn't 800N of force you get from the ground a normal force? Hope it could be explained
@@MichelvanBiezen Than how is normal force 800N produced? Toe must be pushing the ground with 800N and that must be the reason why ground is pushing the toe with 800N? Toe must be pushing the ground with 800N becasue if we go on a scale no matter if we are on our toes or not the weight is the same. Hope this could be answered. I am looking into doing a project with this.
i am a student in biomedical engineering .first stage .could you solving more questions about the medical physics our refereance ( physics of human body )has no solution just a result so could you so could u explian questions of it and solving them 😢
Could you please show me the force required to push a cylindrical switch that has 6kg of pressure and requires the human foot to push the switch 500 times over an 8 hours of work? How would this be calculated?
@@MichelvanBiezen yah i was watching this sceptical too.. but then when i saw end equation it was clear.. but i suggest for everyone to stick to oldschool SI system when we don't know end formula..
aren't you supposed to do it like: 800N x 18cm x cos15° = Fa x 25cm x cos20° ? or sth like that... Fa is supposed to be less than 800N bc the distance of Fa from the pivot point is greater
Such a shame how the people helping society the most are the most underappreciated. Thank you sir for all your content👍
Calculate the magnitude of the mechanical advantage that the (Achilles tendon)foot as a lever provides a human body with in the walking. D = 16 cm; d = 4 cm.
Excellent video, you're not only saving my physics 1 course, you're also presenting biomechanics in a fantastic manner. Thank you for your work. Commenting to prop up your content :D
Thank you. Glad you found our videos. 🙂
i was really wondering about this, thank you so much for explanation
Glad it was helpful!
I believe you said the effort arm (from the achilles tendon) to the axis of rotation is perpendicular, but you did not draw it perpendicular to the effort force (line of pull of the muscle). You drew it on the horizontal. Other than that, I genuinely like your video.
It starts out nearly perpendicular, but as you push yourself up on your toes, the angle will no longer be perpendicular. Therefore the "efficiency" of pushing yourself up on your toes diminishes as the angle changes.
i'm a little confused how d2 is not just 7 cm. isn't the distance suppose to be perpendicular to the line of action from the pivot?
Fa is not perpendicular, but makes an angle of 5 degrees with the perpendicular.
Thank you for an idea of calculating force on Achilles Tendon. I probably should figure the same thing for Japanese martial arts. Since we use earth's gravity, the calculation of your way would not be valid. I have been too lazy to figure it out. Thanks for motivating me.
It should work for any situtation. You just have to find the moment arms and the forces involved.
@@MichelvanBiezen Thank you for your reply. You would think so but we use gravity and wave from core of our body. So almost no stress on Achilles tendon. It is relying on bone structure not on muscle. Japanese ancient martial arts were so sophisticated that they can fight so long hours without fatigue. For instance, we just use opponent power by using crankshaft in our body. There are so many things I need to consider. As I write down this, I realized that Achilles tendon is not pulled. It would be actually stretched when we jump forward.
Anyway you gave me a good hint to think furthermore. Thanks again!
googled it and it says the tensile strength of tendons is between 50 and 150 MPa, super strong
That is VERY strong indeed! 🙂
thanks mr l
You are welcome.
You are amazing Sir, Salute!
Glad you like the videos
must implement this to game engines✔
sir can we find the weight of the object from this.
Hi Mr. Michel van Biezen
. I calculated that d2 is 7.42cm, i used the seno law to got it.
I do not understand why you got that d2 = 7*cos(5°) .
Could you explain with details?, Thanks you veru much.
This video may help clarify it: Physics - Mechanics: Ch 15 Torque Fundamentals (4 of 13) How to Calculate a Torque (Method 1)
i dont understant how we found the angle 5 degree😟
20 degrees - 15 degrees = 5 degrees
Are you iraqi?
ELHAMDULILLAH, MAŞA ALLAH... MANY THANKS..
We appreciate the comment.
how do you call Fa in forces
What is the boundary condition of simulating prosthetic foot walking on the ground in FEA?
pls anyone have an answer .?
Excuse me Sir, how about the weight of the foot? If we take that in to account (since it would provide a counterclockwise torque), Force A should be smaller than what we have estimated, right?
You could include the weight of the foot. (That wasn't the purpose of the video).
isn't the weight just force over gravity?
Can I set the equation as ; 800x18 = FA x7 x cos20 ?
Do I have to change all force direction to parallel the tibia? we dont count the pivot anyway.
what if the angle was 15 instead of 20????
the process of solving it would be the same
how would i solve for reaction force on the tibia???
Once you have calculated Fa, then you can use the "sum of the torques" technique to solve for any other unknown. (in this case you would move the pivot point to the toe).
@@MichelvanBiezen thank you!
where is the gravity of body?
I see the similar comment down below. But, isn't 800N of force you get from the ground a normal force?
Hope it could be explained
Since we picked the pivot point A, we don't need to worry about the weight of the body since that force acts through pivot point A.
@@MichelvanBiezen Than how is normal force 800N produced? Toe must be pushing the ground with 800N and that must be the reason why ground is pushing the toe with 800N?
Toe must be pushing the ground with 800N becasue if we go on a scale no matter if we are on our toes or not the weight is the same.
Hope this could be answered. I am looking into doing a project with this.
If it's not too much of a hassle could you explain to me through email?
Thank you in advance?
shawnoh8@naver.com
Correct, the weight of the body would logically be 800 N if he/she stands on one foot.
@@MichelvanBiezen Yes so if thats the case shouldn't there be an additional 800N force on the toe towards the ground? going counterclockwise?
i am a student in biomedical engineering .first stage .could you solving more questions about the medical physics our refereance ( physics of human body )has no solution
just a result so could you so could u explian questions of it and solving them 😢
Could you please show me the force required to push a cylindrical switch that has 6kg of pressure and requires the human foot to push the switch 500 times over an 8 hours of work? How would this be calculated?
john reis what is the name of this subject ?
Dear sir are there any books on body Mechanics
I am sure there are, but I am not aware of any.
“Physics in biology and medicine”
why are you using centimeters if newtons are in meters???
Since the units (cm) cancel out, it doesn't matter.
@@MichelvanBiezen yah i was watching this sceptical too.. but then when i saw end equation it was clear.. but i suggest for everyone to stick to oldschool SI system when we don't know end formula..
You found f how Ican found T please answer me
Force and tension are the same in the case of ropes, cables, tendon, etc.
@@MichelvanBiezen professor I have question I couldn't find answer for it can you help me please
aren't you supposed to do it like: 800N x 18cm x cos15° = Fa x 25cm x cos20° ? or sth like that... Fa is supposed to be less than 800N bc the distance of Fa from the pivot point is greater
The video is correct. Thanks for checking.
this incorret
This video isn't incorrect, but your spelling is.
@@BlocknerdProductions nice one lol