Ok I am not sure of this but I will answer since nobody did in 3 years. You basically do the same except for the mechanical advantage, but when u get the Force BB you multiply by the sin(x). Why? Because when it's at 90 degrees the torque will be the maximum(sin(pi/2)=0) and if you move upwards the force will be smaller but the angle bigger, while if u move downwards the force will be smaller and so the angle as well. This also depends on the angle the exercise gives you and if it is at equilibrium.
![Biomechanics | Torque Problem #1b (Elbow Joint) [Calculate Joint Reaction Force]](http://i.ytimg.com/vi/7xHAKqf8v5o/mqdefault.jpg)
![Biomechanics | Torque Problem #1b (Elbow Joint) [Calculate Joint Reaction Force]](/img/tr.png)
![Biomechanics | Torque Problem #1 (Elbow Joint) [Biceps Force, Mech. Adv., Joint Reaction Force]](http://i.ytimg.com/vi/wjB0l33W100/mqdefault.jpg)
Hoe do I calculate the force needed by the bicep is the forearm is not at a 90 degree angle
Ok I am not sure of this but I will answer since nobody did in 3 years.
You basically do the same except for the mechanical advantage, but when u get the Force BB you multiply by the sin(x).
Why?
Because when it's at 90 degrees the torque will be the maximum(sin(pi/2)=0) and if you move upwards the force will be smaller but the angle bigger, while if u move downwards the force will be smaller and so the angle as well.
This also depends on the angle the exercise gives you and if it is at equilibrium.