Solving a Radical Equation Using Factoring and Checking Your Answers
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- Опубліковано 26 кві 2015
- 👉 Learn how to solve radical (square root) equations having one radical term. To solve a radical (square root) equation having one radical terms, we isolate the radical term by placing it in one side of the equation. Next, we get rid of the radical by taking the square of both sides of the equation and then solve and simplify the resulting equation.
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Radical Equation with a Extraneous Solution - ua-cam.com/video/JcuF7hQ3uiw/v-deo.html
You seeing that Justin
I always love when he calls people out.
lmaoaoao you didn't
He is cracked at fortnite my guy 😂
@@reneekeiana95pls me too
*_"I can still watch you"_*
@Xzavier Uriah nobody trust these last two comments, it’s a scam
I wonder if Justin still sees it?
when he writes on the board it’s so satisfying
I learned and understood what Im supposed to do in the first minute of the video compared to what my teacher taught us in a week
Gees Justin
Whose else is last minute studying watching all his yt vids
Me
brah I have a test tomorrow, I'm cramming right now
oscar9876543 exactly
Yeah... *very* last minute
Midterms tomorrow
For Christ's sake Justin! Pay attention!
Covid got me watching this, thanks teacher
I really like these short, straight-to-the-point videos
"The next thing, JUSTIN" 🤣
Awesome! Thank you for being clear and concise!
Thanks
Why do you hate Justin?
Thanks you for fast and easy explanations wish u were my teacher and didn’t have my robot talking one that I have trouble learning with
This is my friend Justin, he’s already taken.
And he’s not cracked at math my guy
Super helpful!!
man, thanks so much. i couldnt pay attention in class so this helped a ton.
He said, "you still with me" right when I was dozing off to sleep deprivation, thanks for your videos!
Its 2019 and this video has helped me wow can't thank you enough. Im from AZ btw.
Very good thanks
This man is a beast. Thank you!
This was helpful 😌
Thank you sir
You are so helpful
Pay attention Justin! come on how many times do we have to go over this!
Justin pay attention man
Justin better be a pro at this now
Thanks you teacher
love ur vids
This guy explained it way better than my teacher
How do you determine the domain of these? My teacher went over it fast but it didn't make much sense. i.e √x-2
to solve in real number, not complex, the number under square root needs to be positive. So x>=2
pay attention that the rule doesn't apply to odd roots (e.g. cubic)
On top of this, if you can determine that one side is greater than zero (e.g. constant, square root, even power, exponential), then the other side will be too and if that other size contains the variable you can continue constraining that too.
In this case, we have x+7 >= 0 and x+5 >= 0. Then x >=-5. So -6 can be excluded from domain.
What caused the extraneous solution? The square on RHS changes the sign from the intended operation.
good ass video bro 🙌 i needed this
I wish you were my math teacher.
How do I find the restrictions of the x if there is an exponent greater than 1 on the x value in the radical?
need to set the radicand greater than or equal to zero and solve
@@brianmclogan Thank you
Thanks sir
Damm it! Justin!
everytime i watch your videos i just think about how lucky your students are to have you :,( my teachers werent great in high school so now i struggle sometimes in college
good vid
Square root function only utilizes the positive square root.
less than -5, function x+5 is negative.
So -6 solution is omitted.
Sqrt(A)=B is equivalent to
B>=0 and A=B^2
Here sqrt(x+7)-5 = x sqrt(x+7)=x+5
B=x+5>=0 ==> D: x>=-5
x+7=(x+5)^2 ==> x=-6 or x=-3
-6 ejecred as not in D
-3 is solution as -3>=-5 .
What if the 5 is positive, are going to subtract
5 years later; I still feel like Justin.
justin is receiving fan behavior
My friend here Justin he’s already taken and he’s cracked at seeing that my guy
why do the signs change when you get to the end ? the 6 and 3 were positive but you changed them to negitive???
in 10x you only took away the x.. how do you get 9 out of that? I find this extremely confusing. Thank you for your help.
i was gonna answer but its already been 6 months
@@interviewer3597 dude probably failed that exam 9 months ago 😂
You just confused the shit out of me
X = -3 and -6 (Ans)
Students lucky as hell
My man Justin 😂
do NOT get sick the week before spring break and miss TONS OF CLASS and be off school for SIXTEEN DAYS.
When I’m trying to lean how to do this because I’m confused so I look on here and he’s doing the exact same question I’m confused on😫😫😫😫😫😩😩😩🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼
Boom!
When you checked your answers: -6 does work if you consider that the Square Root of 1 can be -1. -1 -5 = -6.
Yeah, he completely ignored the ± when squaring the radical! For example, √x=2, then x = ±4! Now you have 2 equations to solve, or 2 sets of solutions.
Sqrt(x) is defined as POSITIVE.
Come on Justin
Actually -6 is right considering root of 1 is -1 not +1
Say x^4=1 can have solutions x=+/-1 and +/-i. But sqrt() is always positive
My God. I’m used to the transposing method so seeing this way of handling the transference of 1 term to the other side of the equation is jarring af
pov: ur catching up on missing assignments
get it together *justin*
i ove you bro
Justin you gotta pay attention bro
I understand this thank you although that my native language is arabic
Got 1h for my test
I know I'm late. But my name is Justin 😂
So much attitude OMG
its easier in english than in Indonesian lol
*iam from Indonesia btw
Justin: 👁️👄👁️
i dont understand. what
Freaking Justin.
𝙎𝙤𝙢𝙚 𝙨𝙖𝙮 𝙝𝙚 𝙘𝙖𝙣 𝙨𝙩𝙞𝙡𝙡 𝙨𝙚𝙚 𝙅𝙪𝙨𝙩𝙞𝙣 𝙩𝙤 𝙩𝙝𝙞𝙨 𝙙𝙖𝙮
4kth view
1KTH VIEW
👊
i HATE how they call it FACTORING can we all call it what it really is. UN-FOIL