Spontaneous Processes

Поділитися
Вставка
  • Опубліковано 3 лис 2024

КОМЕНТАРІ • 56

  • @MrNanah38
    @MrNanah38 3 роки тому +11

    Please do not stop doing the good job you are doing, its unfortunate the education system is so poor that we have to go to UA-cam for help from brilliant minds like yourself.
    Thanks again,
    Some of these college professors need training on how to teach I swear.

  • @sciencenerd7639
    @sciencenerd7639 3 роки тому +2

    Wow, I knew that spontaneous processes could be slow, but the diamond to graphite example still amazed me. Gives me a whole new appreciation for the difference between thermodynamically-favored verses kinetically favored.

  • @cupcake9202
    @cupcake9202 5 років тому +15

    thank you so much for using the simulation. it made it so easy to grasp the concept

  • @cazmaestro
    @cazmaestro 10 років тому +17

    Hi. When we're taught about this here in England, we often use the word 'feasible' instead of 'spontaneous'.

    • @q2anti
      @q2anti 3 роки тому +3

      You have no idea how helpful this clarification was. Thank you for pointing this out.

    • @MrNanah38
      @MrNanah38 3 роки тому

      Feasible? Wow

    • @sciencenerd7639
      @sciencenerd7639 3 роки тому

      thank you

  • @CroissantTart
    @CroissantTart 3 роки тому +1

    Thank you so much for the video, every time I'm stuck with chemistry concepts, I always go to your channel.

  • @sidewaysfcs0718
    @sidewaysfcs0718 6 років тому +5

    Spontaneous processes can still occur if enthalpy change is positive, as long as T*delta S is much much larger.

  • @warren1564
    @warren1564 8 років тому +3

    Has anyone else just binge watched these videos? Love watching them...they are very informative!

  • @ComandaKronikk
    @ComandaKronikk 5 років тому

    i love you bozeman!

  • @ddeb
    @ddeb 6 років тому +1

    At 3:45 of the video you mentioned that after the gas expands the temperature of the gas wouldn't change. However, I believe the temperature of the gas would indeed decrease rather than remaining same.

  • @Emme12495
    @Emme12495 3 роки тому

    Thank you for doing this video. It helps a lot!

  • @nebrejaalejandrojohnm.1605
    @nebrejaalejandrojohnm.1605 3 роки тому +1

    a. Liquid water freezing at a temperature below its freezing point
    b. Liquid water freezing at a temperature above its freezing point
    c. The combustion of gasoline
    d. A ball thrown into the air
    e. A raindrop falling to the ground
    f. Iron rusting in a moist atmosphere
    spontaneous or non spontaneous

  • @namehere630
    @namehere630 3 роки тому

    This has been very helpful. Thank you.

  • @ashianagi
    @ashianagi 7 років тому +3

    thank you that was so helpful

  • @ALIMUNTH
    @ALIMUNTH 10 років тому +2

    THANX , a lot of information , gtta watch it again .

  • @RooseveltPadilha
    @RooseveltPadilha 10 років тому +1

    Excellent! I hope you post a new videos!!!

  • @kasukibakugo7423
    @kasukibakugo7423 3 роки тому

    Thank you so much

  • @tayyibkhan8355
    @tayyibkhan8355 4 роки тому

    thank you sir nice method your teaching

  • @ahmadjarrad2635
    @ahmadjarrad2635 4 роки тому

    So basically, spontaneity only has to do with whether the products or reactants are favored? Just having some trouble wrapping my head around this concept.

  • @hygri
    @hygri 5 років тому

    Spot. On.

  • @OBM21
    @OBM21 3 роки тому

    Very digestible, thank you for the video!

  • @Zahra-zy4ze
    @Zahra-zy4ze 5 років тому +1

    Great video, quick question when you say spontaneous required no external energy source, dont all reactions need activation energy to start them off? Little confused with the two concepts?
    Thanks again for the informative content.

    • @xOxAdnanxOx
      @xOxAdnanxOx 5 років тому +2

      Zahra think about activation energy as an energy to initiate a reaction. for example, “ combustion “ if there is a gas ( flammable ) spread out into vacuum, no reaction will occur with the oxygen until you initiate it with a spark or a match so it can break the bonds and reaction occurs. once you initiate it you do nothing to can make it continue ( spontaneous ) it is self-sustaining .so all of this is after energy supplied from an external source “ the spark “

  • @sciencenature787
    @sciencenature787 7 років тому

    When we make both chambers in contact and gas move to right why there is no change in temp and what happens to internal energy.Please explain

  • @Robo311Star
    @Robo311Star 9 місяців тому

    Hello, Mr Anderson. 😎

  • @renzoandre5286
    @renzoandre5286 10 років тому

    How are products favored in a spontaneous reaction? I thought if delta H was negative, it would be exothermic and so move in the backwards direction, reactants favored.

    • @Cobenis_Kar
      @Cobenis_Kar 8 років тому +5

      +Renzo Andre What you're referring to is an equilibrium reaction. When the enthalpy change of the reaction is exothermic, then the backward reaction is favored. That's not what he is talking about.
      He is talking about the spontaneity of a reaction. For example matchstick head burning will cause heat energy to be given out and therefore be exothermic in nature. The burning head also turns to gas and this increases disorder of the system and therefore, entropy. The matchstick burning is not an equilibrium reaction.
      Energy tends to move towards a lower state so, when you burn the match the products will have lesser energy right? So, the reaction favors product formation. This shows that enthalpy decreases.
      Hope that helped!

  • @Departedreflections
    @Departedreflections 10 років тому +1

    nice video

  • @shiroshakirah8668
    @shiroshakirah8668 9 років тому

    nice explaination

  • @Cheo97
    @Cheo97 10 років тому

    Thanks, & nice presentation

  • @ethanbongiovanni2657
    @ethanbongiovanni2657 Рік тому

    When he says occur I hear okurr

  • @tonybron1225
    @tonybron1225 5 років тому

    Thx

  • @mileswaugh
    @mileswaugh 3 роки тому

    Earned my subscription :)

  • @abhishekdhakad9826
    @abhishekdhakad9826 6 років тому

    Nice one

  • @randall.chamberlain
    @randall.chamberlain 3 роки тому +1

    But, but, but, but ... diamonds are forever :(

    • @muhammed5667
      @muhammed5667 3 роки тому +1

      "tending to infinity relative to an average human life span", so if your lover happens to say something like that, now you know what to say

  • @heartstudio9130
    @heartstudio9130 3 роки тому

    book mark 01:14

  • @SaloniMore
    @SaloniMore 8 років тому +1

    What do you mean when you say the products are favoured?

    • @XZagatoX
      @XZagatoX 8 років тому +4

      It means the reaction makes more products than reactants

    • @SaloniMore
      @SaloniMore 7 років тому +1

      Okay, thank you!

  • @shrutishete6456
    @shrutishete6456 6 років тому +1

    great explaination. please reduce the pace a lil bit. thanx

  • @leoknuusiku3104
    @leoknuusiku3104 7 років тому

    useful...

  • @biochemist1661
    @biochemist1661 10 років тому

    My old college chemistry text says that when delta G is equal to "0", then the reaction is at equilibrium just as you do, however, when delta G is "0" and K=1, the products and reactants are equal in concentration but the reaction is not necessarily at equilibrium. My old text goes on to define equilibrium to be when the forward and reverse "reaction rates" are equal. When this condition is met, the reaction can be shifted to the right or to the left depending on the reaction and the value of K. In other words K defines if the reaction lies to the right or to the left or in the middle when the reaction is at equilibrium. So I am confused as to why you and my text say that when delta G is equal to "0", the reaction is at equilibrium?

  • @sidewaysfcs0718
    @sidewaysfcs0718 6 років тому

    By the way, as an example.
    Graphite DOES transform into Diamond spontaneously, but only at very specific conditions ( 1500 K, aprox 60.000 atm pressure)
    Spontaneity is defined with thermodynamic conditions imposed, such as Temperature and Pressure.
    Graphite DOES NOT transform into Diamond at 298 K and 1 atm pressure, under these condition the opposite process is spontaneous.
    As an added note, Enthalpy and Entropy of reaction have nothing to do with reaction rate, the reason at 298K and 1 atm diamonds don't just burst into graphite (exothermic process by the way) , is because this process is kinetically limited by a huge activation energy, which does NOT depend on thermodynamics.

  • @mikepenn8273
    @mikepenn8273 Рік тому

    I knew id return from HS

  • @riptornadoofsouls
    @riptornadoofsouls 10 років тому

    how can a reaction be reversible if it is favorable one way and unfavorable the other?

    • @siabf96
      @siabf96 10 років тому +1

      Both reactions occur at the same time but, one goes more to completion than the other

  • @albertwang2477
    @albertwang2477 5 років тому

    can you talk any faster?