I missed a question about it in Uworld for USMLE step 1, and their explanation could not help me understand the concept, and you did. Thank you so very much!
I couldn't understand clearly in my class and was very tensed about it cause my exam is on thrusday.But your explanation gave me relief.very effective video......
radioimmunoassay can be employed for the detection of insulin in blood plasma for this 125I labelled insulin is mixed and allowed to bind with a known concentration of anti insulin antibody. A known volume of patient blood plasma is then added to the conjugate and allowed to compete with the antigen binding site of antibody. the bound antigen is then separated from the unbound ones and radioactivity of free antigen is then measured by Gama counter . following are some the statement made about this essay . 1 the ratio of radioactive count for the unbound antigen to the bound one is more at the end of reaction. 2.the ratio of radioactive count for unbound antigen to the bound one is less at the end of the reaction. 3 the diabetic patient, the radioactive count for free antigen is less than that for a normal individual 4 A diabetic patient the radioactive count for the free antigen is more than that for the normal individual which of which of the above statement are true?....... Plz sir ans this question in some short explanation plzzzzzzzz
I'm assuming you know the concentration of the radio labeled antigens? Just saying if you take a blood serum sample how will you determine comparison antigen level without knowing the tagged antigens
Great explanation. One question though, Why is unlabeled antigen able to displace labeled Ag bound to Ab.... As in why is the unlabeled antigen winning the competition?
@Sajid Shaikh is there a way to determine unlabeled antigen or ligand concentration if there were only two solutions? In other words, the first scenario is only adding a known concentration of labeled antigen to some concentration of antibodies. The radioactivity is measured of bound antibody-antigen molecules after removing free antigen. Then, the experiment is repeated with an unknown amount of unlabeled ligand that is added after adding the same known amount of labeled antigen. Ki = kd = 7.4*10^-6 M and concentration of known labeled antigen = 7.4*10^-6 M. What is concentration of unlabeled antigen added in the repeat experiment? Also, radioactivity of bound antibody in the first experiment = 63000 cpm and radioactivity of bound antibody after removing free labeled and unlabeled antigen = 49000 cpm (counts per minute). I am not sure what Ki in this instance means, i.e. Ki = [Ag][Ab]/[AgAb] ? and kd = [Ag*][Ab]/[Ag*Ab]? (where Ag* = radiolabeled antigen) in which case [Ab] would cancel leaving [Ag]/[AbAg] = [Ag*]/[Ag*Ab]. However, I am not sure that is correct. At any rate, I am not sure how to use the information given in this problem. Please anyone let me know if you "see the light" on how to use this information to find concentration of unlabeled antigen [Ag]. Thanks.
Hello. The affinity of both the atigens must be similar and conc. Is what we have to find while one is radio labelled and other is not. Why antibody is goving preference to the unlabelled ones when it is already occupied wd the similar type of antigen?
@@sakshisood7108 the monoclonal antibodies are developed against the unlabelled antigen so they have more affinities towards each other than the radio-labelled antigen
suppose there are 5 antibodies on the well ..so there will be 10 binding sites for antigens to bind to the antibody.. that means only 10 antigens will bind to the antibody.. no matter to what extent we increase the concentration..now how can increase in concentration make difference..As only 10 antigens are going to bind with that 5 antibody..can u plz explain
Dear junaid... for digramatic illustration I have show only few antibodies.. practically there are thousands of Abs... but yes.... after a certain conc of Ag, Abs are saturated.... and it should be ...
Sajid, is seriously, your explanation and visual methods was SO AMAZING, thanks a lot!!!!
I have seen many videos on this topic but no one explained like this! this is such a nice explanation!!😊
I missed a question about it in Uworld for USMLE step 1, and their explanation could not help me understand the concept, and you did. Thank you so very much!
Omg YOU EXPLAINED THIS SO WELL. I get it now.
Very clear explanation! Thank you!
Most welcome
I couldn't understand clearly in my class and was very tensed about it cause my exam is on thrusday.But your explanation gave me relief.very effective video......
Thank you so much ,saved at least an 2to 3 hours of time and energy....
I'm very happy now, all my doubts on RIA are cleared, thank u so much sir..😊
Sirjee u are genius the way u teach excellent after watching ur videos all doubts are crystal clear God bless u brother
I finally understood this technique, you made it very clear. thank you so much !!!
Way to represent is excellent, covered all the major points in short video, Thankyou so much
most welcome
Thank you, this helped a lot! Excellent work! I'm studying in german, but I could still understand everything very well (:
Most wecome brother
Thanks a lot. This has helped a lot with my physiology course
Thank you so much ! Your explanation on this topic is phenomenal.
Finally I understand actually what is this. Even in my university I didn't understand this
Best video on UA-cam that cleared all concepts waoooo... Urdu version b bnaya kren plz apni videos k 😊
Wow !.. finally got it , amazing skills to aproach the topic 👏👏
Excellent..
A thorough efforts in making us understand the core concept..
Thanku sir
Most welcome Pritpal .. would you like to help us by donating small amount to our channel? This will motivate us to make more free videos.
best explanation 😎👍👍and helpful for clearing the concept thoroughly 🤠🙏🙏
*slowly claps* Well presented. Thank you, Sir. You are a legend.
Your videos now helping in my csir net jrf preparation
Thank you ☺☺
Most welcome
this the best explanation so far..thanks alot
Got it sir... plz explain about microparticle enzyme immune assay
The part From 7:40 is where the problem has been solved and it's all clear now eventhough the accent is a little hard to understand .. thank u sir!!
Most welcome.. it hard to talk english for me
Crystal clear explanation. Tysm!!
Thanks sajid Bhai.....It really helped me during exam....
Most welcome akshay
You are the better than everyone else 😍😍😍😍😍 shomu is also not that clear but hats off to u man
Learn immunology (live, online personal/group couching ) contact : saj.99999@gmail.com
Excellent..precise and short explanation
Very informative and your way of teaching is excellent 👍
Thanx.. whr r u from ?
@@sajidmicrobiology lahore
Ok
@@sajidmicrobiology sir how can we measure the radioactivity?
With the help of scintillation counter
Wooooow super and clearly explanation 😎👍👌👏👏
Why the labeled antigen is removed ? Is it have low affinity as compared to unknown antigen??
Good job...perfect explanation...keep up the good work!! 👍
You're amazing
I'm not speak your language but I understand your explanation because you are excellent ✔
Excellent explanation n clear understanding pictures tq so much sir
Simpel clear and video wasn't too long, thank you!
Sir u r simple and awesome teacher.....thank u for helping us.....🙏🙏🙏
Most welcome dayana
You Sir are amazing.... Very wonderful explanation...
Thank you very much for your explanation 🙂🤝
Very nice explanation sir...but what is the washing agent we have to use in this process?
radioimmunoassay can be employed for the detection of insulin in blood plasma for this 125I labelled insulin is mixed and allowed to bind with a known concentration of anti insulin antibody. A known volume of patient blood plasma is then added to the conjugate and allowed to compete with the antigen binding site of antibody. the bound antigen is then separated from the unbound ones and radioactivity of free antigen is then measured by Gama counter .
following are some the statement made about this essay .
1 the ratio of radioactive count for the unbound antigen to the bound one is more at the end of reaction.
2.the ratio of radioactive count for unbound antigen to the bound one is less at the end of the reaction.
3 the diabetic patient, the radioactive count for free antigen is less than that for a normal individual
4 A diabetic patient the radioactive count for the free antigen is more than that for the normal individual
which of which of the above statement are true?....... Plz sir ans this question in some short explanation plzzzzzzzz
Option 1 and 4 seem to be correct ...
Thank u sir
you're a Lifesaver!
Very easy plus clearly explained.. thankyou so much sir
Very nicely explained.. thank u so much🙂
Amazing explanation. Thank you!
How to check the radioactivity?? How you measuring it as 40%?
what makes antibody leave labelled Ag and attach to unlabelled?
i have watched many videos on youtube but no one can teach like you. thank u sir for well detailed explanation.
Perfect explanation! Thank you!
Most welcome mena.. would you like to help us by donating small amount to our channel? This will motivate us to make more free videos.
@@sajidmicrobiology Yes!
Thanx mena.. you can paytm us on 8830061003. Your small help can make big diffrence.
You r a life saver
Contact for Personal or group immunology crash course (online)
saj.99999@gmail.com
Incredible explanation, thank u 🙏🏻 😊
Most welcome razan .. would you like to help us by donating small amount to our channel? This will motivate us to make more free videos.
I'm assuming you know the concentration of the radio labeled antigens? Just saying if you take a blood serum sample how will you determine comparison antigen level without knowing the tagged antigens
This was very helpful and easy to understand. Thank you.
Awesome explanation!
Thanx... where r u from?
Great explanation. One question though, Why is unlabeled antigen able to displace labeled Ag bound to Ab.... As in why is the unlabeled antigen winning the competition?
Yes... it's due to competition... like substrate of enzyme and inhibitor
@@sajidmicrobiology
Ohh so it's basically due to high concentration of unlabelled Ag vs labelled one... Thanks
Very clear concept. 😊
Sir it was just amazing
Please keep on making such amazing vedios
@Sajid Shaikh
is there a way to determine unlabeled antigen or ligand concentration if there were only two solutions? In other words, the first scenario is only adding a known concentration of labeled antigen to some concentration of antibodies. The radioactivity is measured of bound antibody-antigen molecules after removing free antigen. Then, the experiment is repeated with an unknown amount of unlabeled ligand that is added after adding the same known amount of labeled antigen. Ki = kd = 7.4*10^-6 M and concentration of known labeled antigen = 7.4*10^-6 M. What is concentration of unlabeled antigen added in the repeat experiment? Also, radioactivity of bound antibody in the first experiment = 63000 cpm and radioactivity of bound antibody after removing free labeled and unlabeled antigen = 49000 cpm (counts per minute).
I am not sure what Ki in this instance means, i.e. Ki = [Ag][Ab]/[AgAb] ? and kd = [Ag*][Ab]/[Ag*Ab]? (where Ag* = radiolabeled antigen) in which case [Ab] would cancel leaving [Ag]/[AbAg] = [Ag*]/[Ag*Ab]. However, I am not sure that is correct.
At any rate, I am not sure how to use the information given in this problem. Please anyone let me know if you "see the light" on how to use this information to find concentration of unlabeled antigen [Ag].
Thanks.
Amazing
Thank you so much
ASSALAMUALAIKUM দাদা , খুব ভালো বোঝালেন , খুব ভালো লাগল
may GOD bless u...pls make more videos
That's a great help, thank you.
Most welcome
wow i just loved it.
I doesn't get the plotting of graph
You’re amazing ❤️
Thanku..u made it very simple...1 question how to detect radio activity?
Thanx Somosree
Radioactivity is tested by scintillator counter
Sajid Shaikh thanku again :)
Very good explanation thank you❤
Wonderful explanation😊😘👍
Excellent video... 👏👏👏👏
Thank you so much for putting this vedio it's so understandable 🙌👏
Love you this explains
Amazing explanation
Thanx sir ... u explained it in very easy way
Most welcome Shivani Duggal
That was excellent! Thank you.
Nice explanation and make a video on fermentation cultures
Excellent explanation sir 🤩
thank you sajid . it is really amazing video .pls do more videos
Most welcome Sure...
thank you
Great explanation
Thank you so much ✨
awessssommmme explanation and verrrry nic sir God bless u
Could you clarify a doubt, why in this technique separates the free antigens (labeled and not) from those complexed to the antibody (labeled and not)?
Very nicely explained 😍
Nice explanation. Sir please make a video on RFLP (POLYMORPHISM OF RESTRICTION FRAGMENT)
Sure Raghuveer
thank you Sajid- great explanation :)
Great explanation!
Thanks!! Good work👍
Thank you! Well explained
Most welcome
Great explanation it helped me a lot.
Thanks sajith
It was just amaze👍plz upload video section of molecular biology 😓
Sure ...rashmi negi
Thank u sir!😄
discryption?
Thank yu so much for this awesome video
Hello.
The affinity of both the atigens must be similar and conc. Is what we have to find while one is radio labelled and other is not.
Why antibody is goving preference to the unlabelled ones when it is already occupied wd the similar type of antigen?
Because the unlabelled antigens have more affinity to the antibodies
Why? Both are similar
@@sakshisood7108 the monoclonal antibodies are developed against the unlabelled antigen so they have more affinities towards each other than the radio-labelled antigen
Is the amount of antibody kept constant as there is increase in unlabelled antigen concentration
Yes junaid....
suppose there are 5 antibodies on the well ..so there will be 10 binding sites for antigens to bind to the antibody.. that means only 10 antigens will bind to the antibody.. no matter to what extent we increase the concentration..now how can increase in concentration make difference..As only 10 antigens are going to bind with that 5 antibody..can u plz explain
Dear junaid... for digramatic illustration I have show only few antibodies.. practically there are thousands of Abs... but yes.... after a certain conc of Ag, Abs are saturated.... and it should be ...
THANK YOU!! Well explained!!
Thanks a lot. Really well explained
Most welcome
Fantastic! Thank you!
THANK YOU!
Whr r u from?
@@sajidmicrobiology ukraine, your video really helped me to prepare for a presentation about RIA( immunology at the university)
Glad to know
thank you! very well explained
Just awesome 💯
Thanks bro you made me understand it so easy...jazakallah
superb no wordzzzz
Thanx anisha... whr r u from ?