Practice Problem: Limiting Reagent and Percent Yield

Once we get the hang of stoichiometric calculations, we get a curve ball. Limiting reagents? Not all of the reactants will react? We might not get as much product as we expect? Let's practice identifying the limiting reagent, calculating theoretical yield, and percent yield.
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[@gB-gm7vy]

I can't express how pertinent your lessons are to my COVID college learning. For Chem and Calc...Thank you

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This is a good channel

[@ShxkeGFX]

agreed

[@circlefont]

I cannot begin to explain how big of a help this was. THANK YOU SO MUCH 🙏🙏🙏

[@farhanalam7642]

You are a brilliant teacher of basic concepts. Some other videos I have seen is just focusing on the units and did not go over what these ratios mean. Thanks!

[@Kammerliteratur]

Hey Professor Dave, can you make a playlist with all tutorials and all practice problems combined?

[@krishnaswamy6684]

Thank you for this lesson

[@assadaaadinawa5225]

understood better than my chemistry master. you are my life savoir.

[@dalianycamacho]

great way to explain it. finally understand thank you

[@davinderarora3938]

Best practice video ever!!!,thanks a lot!

[@milanibohlen2283]

best one i’ve found! thank you!

[@veldanasabra3452]

Thank you!

[@johncrosby5964]

Beautiful video!

[@RachealHeather]

Thank you this has really helped me

[@devlama4725]

Hi sir.can u do a lecture on ionic equilibrium

[@nicholasvrentzos7290]

What if there are two products? How would the second method work?

[@tenzindikila2365]

Thank your for your help

[@Estherawe444]

You explained it perfectly omg

[@cameronholloway5222]

i had passed my exam with really high marks thanks keep up the great work =D

[@arvhiebravo9346]

Thank you so much

[@steadmanjerold1492]

Thank you Sir

[@maryjosettebadano7752]

oh my gosh thank you so so much, you saved my day!! 😭

[@cristianmirasol1538]

Thank you

[@hex7378]

Where did you get the 2.89g at the end?? 8:37

[@robertstanley9633]

Thank you! 2 hours later, I solved how the answer was received. Many thanks! Just subscribed!

[@Barry88487]

Thanks sif

[@desireehaiflich6836]

big question: why did you multiply the 0.0712 by 2/3? O just need some help with that.

[@desireehaiflich6836]

wait nvm, i saw the other part of the video LOL

[@hamzakedir9914]

Finally understand 😌

[@krishnaswamy6684]

I think you really explained this concept really well. Thanks a lot! But I am confident on how you got 2.89g?

[@fahad_sul9]

Its given

[@farahaslan09090]

+1

[@jothamwainmut8462]

Thank you very much😁
I'm certain that I will pass my test tomorrow 😌

[@xdsagecat3920]

did u?

[@judy9680]

the dave grohl of chemistry

[@coss0420]

7:30 where did the 140.28 came from Im so confused please help.

[@BuffaloBuffaloQuasar]

sorry might be too late but that's the molar mass of si3n4, thats how you convert moles to grams

[@mwelase]

you're the best

[@farahaslan09090]

How are you find the Actual Yield????

[@ProfessorDaveExplains]

By doing the experiment and weighing the product.

[@shovandeb9905]

Awesome sir !!

[@jeev6034]

I dont udnerstand how you got 0.0804 mol Si.

[@galiciaangelnicolechristia9585]

how did you get the actual yield

[@mustafakamal-jt1db]

It is given in the question

[@sasrutha7304]

Bro in this how did you divide N2 with a molar mass of 28 that’s the sulfur mr rite??im talking about the first question.

[@ProfessorDaveExplains]

N is 14, so N2 is 28

[@wooshyk6583]

@@ProfessorDaveExplains why dont we multiply silicon by 3 when theres 3 of it

[@skookiz]

Literally studying for my final the morning before 💀💀

[@sniperammow4865]

well since i did not get the mark i wanted in chem i have to redo grade 12 U chem :( this will be useful again i guess.

[@bhavneetkaur6668]

👍👍👍 very nice

[@Nour-Abou-Noweir]

How is the silicon the limiting reagent ?! It has a larger no.of moles than Nitrogen in both cases!!!!!
5:10

[@ProfessorDaveExplains]

You have to consult the stoichiometric ratio.

[@Nour-Abou-Noweir]

Oh oh.. Very nice I got it. All thanks

[@xiaoyu1691]

dam 2019 is 2 years ago
]

[@almamctaggart5787]

Where does the 2.89 g come from when finding the actual yield?

[@ProfessorDaveExplains]

That's the actual yield given at the start of the problem.

[@almamctaggart5787]

Professor Dave Explains ohhh thank you so much! Great video

[@russianemaeegay9096]

Where does the 1mol?

[@fabianmartinez5896]

@@ProfessorDaveExplains P.S next time mention how YOU GOT IT!!!!!!! but thanks

[@ProfessorDaveExplains]

@@fabianmartinez5896 it’s a made up number. This is a practice problem.

[@KeejeMass]

I’m never gonna get this 😐

[@jaspervillanueva6985]

Trust me you can. It just takes time

[@jaspervillanueva6985]

I recommend that you check out Tyler Dewitt's video tutorials first before diving into this kind of videos

[@gabriellaluescher6476]

He looks kinda like lin Miranda

[@akrammohmed6775]

علاوي حبيب كلبي ابو حسين

[@ayanda_m4240]

My actual yeild is often bigger 😭😭😤

[@desireehaiflich6836]

you probably divided the 0.0238 by 3 again. I did that too

[@xXoommaarrXx]

This isnt your voice mate.

[@ProfessorDaveExplains]

Um, yes it is.

[@nothingnew4287]

papi chulo

[@vinoriawareba9438]

Thank you so much sir 🫂,you really helped me..