Theoretical, Actual, Percent Yield & Error - Limiting Reagent and Excess Reactant That Remains
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- Опубліковано 4 жов 2024
- This chemistry video tutorial focuses on actual, theoretical and percent yield calculations. It shows you how to determine the percent error using a formula and how it is related to the percent yield. This video also shows you how to identify the limiting reactant by calculating which reagent has the lowest mole per coefficient ratio. It also shows you how to calculate the amount of excess reactant that actually reacts and how much is left over or remains after the reaction is complete.
Introduction to Moles:
• Introduction to Moles
How To Calculate The Molar Mass:
• How To Calculate The M...
How To Convert Grams to Moles:
• How To Convert Grams T...
How To Convert Moles to Grams:
• How To Convert Moles t...
Moles to Atoms Conversion:
• Moles To Atoms Convers...
Grams to Molecules Conversion:
• Grams to Molecules and...
_________________________________
Grams to Atoms:
• How To Convert Grams t...
Moles, Atoms, & Grams Conversions:
• How To Convert Between...
How To Balance Chemical Equations:
• How To Balance Chemica...
Stoichiometry - Basic Introduction:
• Stoichiometry Basic In...
Avogadro's Number:
• Avogadro's Number, The...
_________________________________
Limiting Reactant Problems:
• Limiting Reactant Prac...
Excess Reactant Problems:
• How To Find The Amount...
Theoretical & Percent Yield:
• How To Calculate Theor...
Percent Yield - More Examples:
• How To Calculate The P...
Percent Error:
• Percent Error Made Easy!
_________________________________
Percent Composition By Mass:
• Percent Composition By...
Empirical Formula Problems:
• Empirical Formula & Mo...
Empirical Formula - Hydrated Compounds:
• How To Find The Empiri...
Combustion Analysis:
• Introduction to Combus...
Stoichiometry Practice Test:
• How To Solve Stoichiom...
_______________________________________
Final Exams and Video Playlists:
www.video-tuto...
Full-Length Videos and Worksheets:
/ collections
Stoichiometry Formula Sheet:
bit.ly/3Z7uMw8
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Stoichiometry Formula Sheet: bit.ly/3Z7uMw8
Final Exams and Video Playlists: www.video-tutor.net/
Honestly I am that person who never comments on youtube videos, but I have a big college chem exam tomorrow and have watched like 4 of your videos. You by far explain all of these topics better than an other youtube video and even better than my professor. Thank you very much!!!!
Brandon Sipiorski you’re learning this for college I’m learning this in high school 😭
I'm that one weeb you basically relearn everything in college unless you place into a higher level class. if you’re in a intro class it’ll just be high school stuff over again
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my professor had given us such a poor explanation, I can't even 💀
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Shouldn't it be 39g o2?
Edit: Ahh... yes I see. He just fixed it later on :>
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Y’all are college students while i’m a poor 10th grader studying this kind of shit? Hmph💀💀
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who is watching from 2020
Legit good instruction. Thank you.
YOUR EXISTENCE IS A BLESSING
i love the last way of finding limited reactant ,at 18:48.ty so much !
THIS VIDEO ACTUALLY HELPED ME!! IM READY TO ACE THIS HON CHEM TEST TMR
to find theoretical yield a way less confusing way to do it is to break it up:
first find the n(CO2) by comparing with n(O2) and its mole ratio
second now that you have n(CO2) just find m(CO2)
hope this is helpful!
whats N
@@owaisn6095 The co-efficient, typically.
@@Dr.Peppermintz got my head around it thanks
aaahhh our teacher taught us a different equation and this is quite understandable than what i know
Thank you so much for helping me understand stiochiometry and these lessons clearly! You deserve endless amount of recognition.
Do I have to do the percent error thing ? In my book they are only asking for the theoretical yield
even if you did just remember it's 100% - your % yield.
this guy is the best! broken down perfectly! thank you!
Your teaching is amazing. God bless you! - Kasi
Thank you, getting to understand this topic.
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Thank you. I like that you always do exam-like questions.
im confused, the question says you have 39g of oxygen, but you used 32 g of oxygen? 14:08
nvm, I have seen further that you corrected the amount of oxygen used. thank you for your education
32 is the molar mass of oxygen
@@bertybongben7088 they were talking about the given amount of oxygen. the given was 39, not 32. He wrote 32g twice
THANK YOU SO MUCH I HAVE A TEST TOMORROW AND NOW I FEEL LIKE I CAN GET A FUCKING 100 CUZ OF U
You're welcome
I like your explanation please let me know more about period table and concentration which is molarity
God bless you sir. I perfectly understand
Thank you
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Too good explanation......wanna you to be my chemistry teacher....
Could you please explain what are/is difference(s) of percentage yield and percentage error and what each indicates?
Percentage yield is the percent of product made, while percent error is percent of product lost or error I in making.
*REMEMBER*
Percentage yield + Percentage error = 100%
You are doing a great work out there man ,keep it up 🙌
Thank you for the exercises
I solved both the questions before seeing the solution
Though I got first wrong, I am pretty sure I would get second correct>
My answers are 31.79 grams, 19.78 grams, 3.22 grams
I appreciate your efforts! 🙏 I have a quick question: 🤷♂️ I only have these words 🤔. (behave today finger ski upon boy assault summer exhaust beauty stereo over). Not sure how to use them, would appreciate help. 🙏
Should you round off the atomic mass or not? In the periodic table some elements have 2 atomic mass which do I pick?
Why don’t u take into account sig figs?
cause fuck sig figs
You are my hero😊
What if only one mass is given to two reactants???
I need answer
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thank you so much. this video helps me a lot.
2:36 why the heck has no one ever told me this!!?
Thank you!
Me too. I have been doing it the long way for so long.
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On the first part, can we also find the masses and see which one is the limiting reactant?
If we get the loyalty badge can we request videos? I need oxy cope reactions
for second problem , when you were balancing the equation why for Oxygen on right that you had 7 you said ethanol from left side has 1 so 7-1=6 I have no idea why you did that
I have no idea as well?
what would we all do without him
thanks very much.....much needed help
thank u so much for this!
Thank you. Respect.
8:03 shouldn't it just be 15.99 g? Since oxygen is diatomic?
5:33 Is it necessary to use significant digits?
The balanced equation is actually c2h6 + 5 O2 yields 2co2 + 3 h2o
Kimmra Crawford no it's not.
Why don’t you use n=m/M .... number of moles = mass/Molar mass?
I don’t understand why the moles in the product are the moles you have but the coefficients in the reactants aren’t the amount of moles you have.
Why did we convert at the very end from 39 O2 g to C2H6 grams, I'm a little confused.
To find the left over , u subtract the amount of oxygen u need from the amount u have which is 39g
what if there is no actual value given?
what if you're not given what was collected?
i love ths man.
Thanksss much dude
I just wanna undersand concept behind thoses two
hello sir how did you have H2O on the problem wherein it is not stated on the given?
This problem is a combustion reaction and its products are always CO2 and H2O, so it doesn't need to be stated in the problem
great video
Why did you take the difference from 7 from 1?
Never mind I see now lol!
God bless you
شكرا
I LOVE YOU
Wow thanks
Thank u huhu
Im confused as hell. The way you balanced your chemical reaction isnt the same way my teacher nor another youtuber who teaches this.
Someone pls explain what to do if not given the actual yeild
U can't solve
yoooo this is so complicated.....
At 4:00 why do you not go straight to finding the grams?
To grams of co2?
Will you still get the same answer?
You have to do molar conversions to go from one element to another in chemical reactions.
It’s abit confusing due to the large amount of sums, you should real it up into smaller parts for us to understand better
Split*
Danke
they ask whos the grade saver, now hows the grade saver smh
i love you.
16:30
Ellwood....
6:00
My test is in 30 minutes
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lost sound
13:14
cool
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IF YOU DONT UNDERSTAND HOW TO DO THIS FIRST LOOK AT THE VIDEO TITLED "STOICHIOMETRY - Solving PERCENT YIELD Stoichiometry Problems by sciencepost " then come back here.