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Tributary Area and load calcuations
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- Опубліковано 16 сер 2024
- Example problem of determining distributed load on a beam and column reactions for a simple beam-and-plank system with unsymmetrical bay sizes
(Reference: Onouye & Kane, 2012, problem 4.2)
Excellent. As an electrical engineer I have been struggling with how to approach a beam loading problem for 3,500 Lb transformers and this give a great intuitive overview as well as a nice step-by-step approach.
This is by far the most impressive analysis I’ve come across yet. Thank you!
This is just a phenomenal explanation and walkthru. I started with your video and had to double back a couple of times to some texts on line to figure out the reasoning behind why certain calculations were coming out the way they were, but once I did it just all fell into place intuitively and your video was smooth.
Well done.
Studying for my Architect license Exam and this video is helpful!
So informative! Definitely the best I've come across so far. Thank you💯
Best instructional videos I've ever seen.
Good stuff! I recently built a deck with 3 beams (distributed over 12 posts), so it was neat to see the calculations of something similar.
Very helpful video. Very simply explained, any one can understand the complex calculation. Many thanks for the video.
The way you explain this is superb.
Extremely interesting and helpful as well ,as explained with practical example.
worth watching guyzzz. thanku
Thank you so much for explaining a complicated problem for me, in such as easy way to understand.
how to choose what type( size of beam) to use ?
Depends on what you are trying to do. To get the load on a column, you can use tributary width of beams and girders X their lengths to get the point loads to apply to the column, or you can get the same number directly by using the tributary area.
Why do we have to multiply live load with tributary width of the beam not the tributary area when determining the load acting on the beam
And why don't you multiply the plf with the length of the beam when determining the load on the beam
Sir, Many thanks for this video which is easy to comprehend.
Nice explanation and I especially like the what that you are able to sketch on the image of the structure.
Thank you so much for your great and simple explanations.
Thanks for making this. Extremely helpful.
I am a structural engineer, and every time when I have some problems relate to trib area, I look at this video and problems will just be straighten out.
This was a life savior. Thank you for the video!
Thanks John! I found this really helpful
wow, its been amazing, thank you so much. Can you also analyze for the wind loads on a storey structure? Thank
Excellent video
There are very good information.-
I wish to calculate the moment of a rectangle who is supported in only one side.- This side is supported by a shaft.- The shaft will rotate 90 degree in order to move the rectangle who has a distributed load of 100 pounds.- Which is the torque on the shaft?.- This is which could be the max torque in the shaft from zero to 120 degree?
What is the difference between using the trib width for the beams and the trib area for the column?
WELL DONE!
For the beams, the answers you give are for linear feet. So if I want to know the total load on the whole beam, would I multiply your answer by the length of the beam?
yes
thank you so much
great explanation sir
Great thanks!
very well explained!
Pounds per sf = x area
Pounds per linear f = x length
Pounds =
can you reply to this: if you have a continuous beam setup,do you analyze the beam first as continuous beam and get the shear forces at various supports and add up the shear forces to give the total support reaction at every point or do you assume the beam is simply supported between the supports and just divide the beam loads into two to every supports?
Well explained and understood - what book do this example comes from.
Im confused as to how tributary area for a beam doesn't take the whole length of the beam into acct
I have to calculate my column placement is at A3, and I'm calculating the ground beam column, my house is a double storey house. How to calculate it? Do I have to consider the loads from roof to beam then to column? But I don't know where to find the exact video on how to calculate it. I'm lost.
Good work
thank you for great explanation!
Why are the loads not separated into triangles and trapezoids?
Sir, you are awesome!
please make a tutorial on distribution of story forces due to earthquake to the frames of a building and then to individual columns.
If they gave us the concrete beam dimensions( hight and width ) how do we get its load ??
this is great! thank you
Good video, but what about the continuity factor? Or are beams taken to be pinned at each column connection?
Professor explained tributory area example in higly organised way and easy to understand.Thanks
If we remove the column B2 then the slab will retain or not? Please somebody tell me
SOOOO HELPFUL
For example in a double storey building, Does the beam in first floor sustain whatever load (max shear force) carried by roof beam other than the weight of slab and wall?
You Xian Hang No. The first floor beams and girders only take load from the first floor (unless there is a column from 2nd floor that does not continue to the ground. 2nd floor load travels down the columns directly to the foundation.
Thanks for the explaination (=
Good video my guy
The dimension of your beams and columns? How u compute it? Anyway. Great vid!
How would you find the max shear for one of the beams?
You could use the empirical equation in your design code
Good job!
thank you for this! :)
What I do to design column and beans for building ? Please make an video in detail please please please sir ☺
Thank you sir
Hello John,
which software you are using in this presentation?
Microsoft Onenote captured using Camtasia
Great, thank you
if we go multi-storey, does the tributary area adds up for the determination of column size or does it remains same?
kalpana gupta yes, for the columns. Each lower column collects additional load from each floor. Visualize load like water and the columns as pipes. By the time you get to the bottom, the pipes (columns) have to collect all the water (load). Each floor, however is independent.
So, while designing the dimensions of the column, the tributary area of the column would be ( in basic terms) the area supported on one floor multiplied by(times) the number of floor. Am i right?
This is based on the assumption that the beams are simply supported.
very helpful
How would you calculate the loads on a 2x6 stud wall just right under a roof?
Load on top of the wall would be a line load, same as on one of the beams. The load in each 2x6 depends on the spacing. For instance, if the line load at the top of the wall is 300 plf and the studs are spaced at 16" o.c., then each stud takes 300 plf * 16"/(12"/ft) = 400 lbs.
May i ask why do we need add the beam load when we are calculated FORCE ACTED ON BEAM ?
I'm no engineer , but IMHO is that the beam itself contributes to the load placed on it ... i.e. ... its weight is being supported by what? Itself.
He’s is trying to calculate load on column not beam. In order to calculate total load on column, you must include the beam weight itself and anything bearing on it
why is it an error? no video! can I report it?
thankyou sir
No, I don't have such a sample.
more english please otherwise the content is great
How to transfer load from beam to column.. Plz help
Use reaction method.... Concentrated load to the supporting columns
@@markgarcia2448 ooof
You do a mistake. When you calculate the surface load multiply by tributary width for beam 1-2-3 you should take 4' instead of 3'.
+Redemption_Project
I am calculating the load on the beam along line A, which has a tributary of 6'/2 = 3'. The beam on line 'C' would have a tributary of 8'/2 = 4'
Hi, can you please upload video for two way slab.
Are you ignoring the moments?!
Where did the deck loads come from? Those must be known values.
how are they known bro? from code?
The International Residential Code (Table 301.5) specifies a minimum deck live load of 40 psf. If you add in appx. 10 psf dead load, that equals 50 psf. Where did 68 psf come from? You've heard of residential deck failures because of young adults swarming the deck for parties, and then they collapse. So, it would be wise to design a deck with a load of something greater than 50 psf, in case guests attempt to treat the deck like a commercial building instead of a residence.
monicapttrsn x
I dread videos explaining through the imperial system of measurement 😩. Otherwise this is a beautiful engineering concept of load distribution and support whose final stability ultimately depends on the bearing capacity of the compacted soil beneath
Great example but you might want to check your spelling.