Holy crap this video might have just saved my life. I have an organic chemistry exam in less than 4 hours, and this dude just explained a concept I've failed to grasp all quarter. Very grateful
Came to you because professors have proven to be useless, once again. You are incredible and have saved me in numerous classes throughout college. I love you. Thank you.
My chem prof made a mnemonic to remember the Z isomer. It's Z because the two groups with the highest priorities are on the "Zame Zide" (Same side). Obviously, for the E isomer it would be different sides then.
THESE ARE THE PEOPLE ON UA-cam WHO DESERVE TO MAKE BIG MONEY! I AM TRYING TO GET INTO MEDICAL SCHOOL AND YOU'RE AMAZING AT TEACHING ORGANIC CHEM! Yes the capital letters were me yelling this XD.
I learnt a lot and understand what i have been finding so hard to get. I really like watching organic chemistry videos from this channel because it's always understandable
thank you for this video my teacher sucks at teaching. she would just write the name straight away while you labeled the branches and parent chain first and then combined it. made it very clear
In the last question the correct name of the compound is - (Z) 3-methyl-2-propyl hex-2-ene (by giving the double bond lowest numbering). The parent chain will contain 6-carbon not 8.
but for the last example tho I thought we have to prioritise and make double bonds the lowest position possible? so isn't it suppose to be (Z) 1,2-dimethyl-1-propyl-1-pentene
No, it can't bro. For carbon 1 to take the double bond it has to be between C1 and C2. Putting it between C6 and C1 will be giving the double bond to C6 even though C1 is the lower number.
For anyone else who has the same question. It´s easier to see whether the molecule is trans or cis when you draw the hydrogen to the second and third carbon. If the hydrogens are both upwards it´s cis-2-butene, if one hydrogen is up and the other hydrogen is downwards, it's trans-2-butene.
For cis it's Z (zusammen -together ) both z and t are consonant, and for trans it's E (entgegen-opposite) both e and o are sonant/vowel you can remember from here. thank me later :)
Is this according to the newest IUPAC rules released? In class, we learned if there are no rings: the longest chain has priority regardless of the presence of multiple bonds, which is different from the older IUPAC rules. Do you think you can clarify? Overall-helpful with distinguishing E and Z isomer. Thank you!
Can someone explain why he does not use the E Z system on cycloalkenes? (like why doesn't he indicate whether it has an E or Z configuration on its nomenclature)
No, because the alkene is tetrasubstituted...there’s no way to tell what groups are cis or trans to the others. The two methyl groups are cis to each other, for example, but each of them is trans to the propyl groups, so which do you pick? So it has to be (Z)-4,5-dimethyl-4-octene. For trisubstituted and tetrasubstituted alkenes, the EZ system is required for unambiguity.
@@paysonkeown2960 oh I see, and for propane it can only be 1 or 2 but it would be implied to be 1. but for butene, it can be in the middle (2-) instead of the terminal ends, so that is why it's necessary to state 1-
@@lieviotangellos7343 yeah exactly. Some labs and scientists would be fine if you said butene, but if you were in a class, writing to someone who likes 1-, or writing something important down, 1- is needed.
At 7:56 why isn't it 1-ethyl-5-methyl-cycloheptene? I started counting the same direction as he did in the beginning, but when on to count the ethyl with a 5,6, and 7. @TheOrganicChemistryTutor or anyone else. Thank you.
First, u need to consider where is the double bond. Then, u put the number on that ring. So we can see we have methyl and ethyl right? The reason why u write ethyl first then methyl because "e" come out first before"m"
Yes, that’s also considered correct, but saying it that way has always grated on my nerves a bit. I generally tend to say names likes that with the number entirely before the parent chain.
The E/Z system is an absolute form of naming, which can always be applied for clarity. Cis/Trans only works in simple cases, and only tells the relative configuration.
In this structure 2,5-dimethyl-3-propyl-hexene I have been struggling to find out what the longest chain is. I wonder if there is any scenario where the parent chain is not like longest chain in the alkene above. Any one to help
You have chosen it right because according to the IUPAC rules - 1) The longest C-chain must contain double bond. 2) Longest C-chain must get maximum number of branches(try to get multiple number of branches rather than getting one complex branch or substituent). So, 2,5-dimethyl-3-propyl-hexene is the correct IUPAC name and 2-methyl-3-(2-methyl propyl)hexene is the incorrect one.
I mean this video was made 6 years ago, but I don't understand WHAT IF we had a simple ethene with 2 different functional groups on the left side and 2 hydrogen atoms on the right - would it be E isomer, or is this the case of "this molecule has no isomers". Its hard for me to put my question in words - if I could post a drawing it would be easier.
With alkenes, the rule is that the chain *must* contain the dubble bond. Looking at the possibilities including the dubble bond, we can see it was indeed the longest chain.
Organic Chemistry - Video Lessons: www.video-tutor.net/organic-chemistry.html
This dudes a legend. Here I am at 1am and this guy has taught me more than my month and a half in my org chem class.
I think he is the best so far🤗🤗
Feltttt
The way I’m using to remember E and Z is that in E, the priority groups go “Eww” and stay away from each other.
@@nb6955 THIS IS GENIUS THANK YOU SO MUCH
@@nb6955LMAOOO STOPP I LOVE THAT
I love how fast this guy goes through examples. Explains well, hits all kinds of problems, and is overall super helpful. Thanks for saving my grade
Holy crap this video might have just saved my life. I have an organic chemistry exam in less than 4 hours, and this dude just explained a concept I've failed to grasp all quarter. Very grateful
Came to you because professors have proven to be useless, once again.
You are incredible and have saved me in numerous classes throughout college.
I love you. Thank you.
Aah😂😂😂
8:00 - If ur in a rush
Thank you!
You are awesome
THANK YOU from somebody who's orgo final is in 15 minutes lmao
@@emmajohnson964 how did it go
@@emmajohnson964 ????
My chem prof made a mnemonic to remember the Z isomer.
It's Z because the two groups with the highest priorities are on the "Zame Zide" (Same side).
Obviously, for the E isomer it would be different sides then.
i think of it as acrosZ and oppositE.
My teacher said think of E like “ears” which are on “opposite” sides of your head.
This helps, thanks
this was super helpful, thanks
i always try to think it as "like Zis"
If you want to jump right into E-Z system, then it starts at 8:10
Thanks bro niliwatch❤
I am a UNIBEN undergraduate and this your lecture video on isomers is simply top notch far better than textbooks
THESE ARE THE PEOPLE ON UA-cam WHO DESERVE TO MAKE BIG MONEY! I AM TRYING TO GET INTO MEDICAL SCHOOL AND YOU'RE AMAZING AT TEACHING ORGANIC CHEM! Yes the capital letters were me yelling this XD.
😂😂😂😂 perfectly said 😊
This guy is the best, Loads better than any lecture professor
You deserve a 5star.
I really like your tuitions because it has helped me from Jhs, and SHS as well.
Thank you and God bless you too.
I learnt a lot and understand what i have been finding so hard to get. I really like watching organic chemistry videos from this channel because it's always understandable
ive been trying to figure this out for months. i needed only 11 minutes of time... incredible.
i guess we all agree this man is the king of chemistry
thank you for this video my teacher sucks at teaching. she would just write the name straight away while you labeled the branches and parent chain first and then combined it. made it very clear
E and Z come from the german words "Entgegengesetz" (Opposite) and "Zusammen" (Together)
I listen to your explanation bc of your voice its very calming
Wow chem is more easier. This dude is a genius. We need such chem teachers
In the last question the correct name of the compound is - (Z) 3-methyl-2-propyl hex-2-ene (by giving the double bond lowest numbering). The parent chain will contain 6-carbon not 8.
you literally saved my life 😭 thank youu soo much !!!! 🥺😭
Man, you are just a pure legend!
the fact that his voice is also soothing
I am Iraqi stady in HUST in china. You the best lecturer 👌🙏
Tomorrow I have test in organic chemistry about this topic.
Thank you for everything...
I get that everyone is saying "this saved me" I get that its a good explanation. I am still confused though oh my goddddd
Zame and Eppisites.
You’re a genius
you're a genius bro ily
Thanks sir.... Huge respect from Pakistan 😍
9:41 I got (Z)-2-bromo-1-chloro-1-propene for the left and (E)-2-methyl-1-buten-1-ol for the right.
At 10:42 isn’t wrong to count from the ethyl group because if you start from the methyl group the double bond would be number 2 ??
dude that's what I am thinking! Sucks my final is tomorrow morning and nobody is gonna read this.
Isn't it because it will be the longer chain. If you go by the methyl group the chain will be shorter.
great video as usual. how do you know which group have priority though ?
GRACIAS. YOU ARE TRUE KING
but for the last example tho I thought we have to prioritise and make double bonds the lowest position possible? so isn't it suppose to be (Z) 1,2-dimethyl-1-propyl-1-pentene
@theorganicchemistrytutor help!!
From 8:10 nomenclature of E/Z Isomers
Thanks for making this lesson SO EZ
Hehehehe
Very helpful discussion 🙏🙏🙏
You're the only reason I'm passing my guy
God bless my friend, well explained as always
Thank you, this was helpful
Thank you very much🙏🙏🙏...we appreciate
Explanation is good.... thank you so much........
Thank you so much sir ur just d best
6:14 Could it also be 2-ethylcyclohexene? You could start counting at the carbon above and achieve a smaller number for the ethyl group.
No, it can't bro. For carbon 1 to take the double bond it has to be between C1 and C2. Putting it between C6 and C1 will be giving the double bond to C6 even though C1 is the lower number.
@@timisanniofficial Thank you. :)
How do you tell the difference between cis and trans-2-butene in the skeletal structures (at 1:20 into the video) ?
For anyone else who has the same question. It´s easier to see whether the molecule is trans or cis when you draw the hydrogen to the second and third carbon. If the hydrogens are both upwards it´s cis-2-butene, if one hydrogen is up and the other hydrogen is downwards, it's trans-2-butene.
@@mariekegraf9087Thanks, but how do we know if the hydrogen is upwards or downwards?
U made my day😊
Skip to 8 minutes for the actually video
I love the video it has helped
For cis it's Z (zusammen -together ) both z and t are consonant, and for trans it's E (entgegen-opposite) both e and o are sonant/vowel you can remember from here. thank me later :)
it is even difficult than the actual E Z isomers concept lol
He's the best✨
a genteel men i can't till end of my life
Living legend 🙌
God bless you Sir
11:50 Can we call it Sis - 4,5 - dimethyle - 4 - octene ??
Thanks so much ,
Thank You So much !
Took me 2 hours to decipher a 12 minute video
I need to see the face of this man!!!
Wow that's amazing
Is this according to the newest IUPAC rules released? In class, we learned if there are no rings: the longest chain has priority regardless of the presence of multiple bonds, which is different from the older IUPAC rules. Do you think you can clarify? Overall-helpful with distinguishing E and Z isomer. Thank you!
These aren't the newest iupac rules. U can tell because he names 2-butene instead of but-2-ene
The bonds are counted before the substituents
What if the two highest priority groups are both on the left side of the compound?
does the orientation of the pi bond change when switching between e and z configuration?
Can someone explain why he does not use the E Z system on cycloalkenes? (like why doesn't he indicate whether it has an E or Z configuration on its nomenclature)
At 11:50 could it be cis-4,5-dimethyl-4-octene instead of Z
For the very last question, do you need to use the E,Z system? They aren't different groups so cant you just use cis-trans?
No, because the alkene is tetrasubstituted...there’s no way to tell what groups are cis or trans to the others. The two methyl groups are cis to each other, for example, but each of them is trans to the propyl groups, so which do you pick? So it has to be (Z)-4,5-dimethyl-4-octene. For trisubstituted and tetrasubstituted alkenes, the EZ system is required for unambiguity.
Very good
why did you start counting from the left instead the right at time 2:01 ?
Its the same from either way.
0:31 Why is it required you say "1-" for butene but not "1-" for propene, is 1 not already implied for both?
We can have 2-butene, so from a formal perspective, 1-butene does not have an implied 1-.
@@paysonkeown2960 oh I see, and for propane it can only be 1 or 2 but it would be implied to be 1. but for butene, it can be in the middle (2-) instead of the terminal ends, so that is why it's necessary to state 1-
@@lieviotangellos7343 yeah exactly. Some labs and scientists would be fine if you said butene, but if you were in a class, writing to someone who likes 1-, or writing something important down, 1- is needed.
At 7:56 why isn't it 1-ethyl-5-methyl-cycloheptene? I started counting the same direction as he did in the beginning, but when on to count the ethyl with a 5,6, and 7. @TheOrganicChemistryTutor or anyone else. Thank you.
First, u need to consider where is the double bond. Then, u put the number on that ring. So we can see we have methyl and ethyl right? The reason why u write ethyl first then methyl because "e" come out first before"m"
Thank you
Thank you
Thank you dai
i think my brain just comit suicide
Can someone assist me with the structure of (E)-1-Bromo-2-isopropyl-1,3- butadiene. Check if it must be E and not Z
I have a question about dienes? How do we do e and z when there are multiple double bonds
@ 10:46, where does the second 3 come from? I understand the (E) - methyl and heptene part but why is there a 3 in front of heptene?
the double bond is on carbon 3, sorry if this is late
@@user-lk1cl6ev7g no worries it refreshed my memory as I thought I figured it out but looking at it again I got confused but now I get it. Thank you!
11:48 can it be "(Z)-4,5-dimethyloct-4-ene?
Yes!
yes!
Yes, that’s also considered correct, but saying it that way has always grated on my nerves a bit. I generally tend to say names likes that with the number entirely before the parent chain.
You saved me man
doesnt the 4-methyl-1-hexene have a chiral center?
7:00 isn’t there not a 1-cyclohexene at the end for double bond
Adding the 1- isn’t necessary as it is known the alkene occurs at position 1
are the En'Z and CISn'TRANS both similar?
cause in you know the other channels or video are using CIS and TRANS just trying to ask if they're the same
The E/Z system is an absolute form of naming, which can always be applied for clarity. Cis/Trans only works in simple cases, and only tells the relative configuration.
i love loving you.
Nice
In this structure
2,5-dimethyl-3-propyl-hexene
I have been struggling to find out what the longest chain is. I wonder if there is any scenario where the parent chain is not like longest chain in the alkene above. Any one to help
You have chosen it right because according to the IUPAC rules - 1) The longest C-chain must contain double bond. 2) Longest C-chain must get maximum number of branches(try to get multiple number of branches rather than getting one complex branch or substituent). So, 2,5-dimethyl-3-propyl-hexene is the correct IUPAC name and 2-methyl-3-(2-methyl propyl)hexene is the incorrect one.
ty
can we use E-Z for cycloalkenes?
I don't think it applies for cycloalkenes. R and S do though
@@aeropostale101nw thank you !
I mean this video was made 6 years ago, but I don't understand WHAT IF we had a simple ethene with 2 different functional groups on the left side and 2 hydrogen atoms on the right - would it be E isomer, or is this the case of "this molecule has no isomers". Its hard for me to put my question in words - if I could post a drawing it would be easier.
So like maybe 1,1-dichloroethene? With molecules like that, there won’t be an E/Z designation since E/Z applies to groups on opposite sides.
What is the second 3 and second 4 in the 2nd to last and last problem? Why is it z 4,5 dimethyl FOUR octene???? I don't understand the 2nd 4
The 4 in 4-octene indicates which carbon of the main chain that the double bond starts on.
come to my school and be my professor please
It so easy yet u freeze up during test...
In 6:16, why ethyl and not methyl?
There is an invisible bond between CH2 and CH3
after tm my unite 1 chem exam wish me luck please
👌👌👌👌
How do you know where to start counting?
You prioritize the alkene (double bond) so u start with it
Very useful to him after 6 months
@@levikaneki5778 lol
THannkkk youuuuuuu
"Zee Zeme Zide" and "Epposite"
It sure is E Z to learn!
I love you
At 5:10 u made a mistake for finding the longest chai
With alkenes, the rule is that the chain *must* contain the dubble bond. Looking at the possibilities including the dubble bond, we can see it was indeed the longest chain.
Actually I am not able to understand tht last one 😢
❤️