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this is also a mental sum.move the the X^2 to the right hand side The equation becomes X^3 = 100 + X^2 the value of 5 satisfies the equation
X=5
Please.solve this ecuacion exponencial:4×^3-4×-4=o.venezuela.
Funny how during solving then the answer itself is apparent5^3-5^2= 100X is 5 Minute 2 of the explanation. So from there everything is just circular back to 5😉
5 x 5 x 5 = 125 minus 5 x 5 = 100. X is 5
(5-x).(x^2+4x+20)=0[(5-x).(x^2+4x+20)] / (x^2+4x+20 ) = 0 / (x^2+4x+20) (5-x)=0X=5🙃 👉 0/a = 0 ( a simple mathematical rule)
Х=5
x^3-x^2=100x^3-x^2-100=0x^3-x^2-125+25=0(x^3-5^3)-(x^2-5^2)=0(x-5)(x^2+5x+25)-(x-5)(x+5)=0x-5=0 x=5x^2+5x+25-x-5=0x^2+4x+20=0x=[-4+-rq(16-80]/2 =[-4+-8i/2x=-2+-4i x=5
How did you get the 1st part of line 5?
this is also a mental sum.move the the X^2 to the right hand side The equation becomes X^3 = 100 + X^2 the value of 5 satisfies the equation
X=5
Please.solve this ecuacion exponencial:4×^3-4×-4=o.venezuela.
Funny how during solving then the answer itself is apparent
5^3-5^2= 100
X is 5
Minute 2 of the explanation. So from there everything is just circular back to 5
😉
5 x 5 x 5 = 125 minus 5 x 5 = 100. X is 5
(5-x).(x^2+4x+20)=0
[(5-x).(x^2+4x+20)] / (x^2+4x+20 ) = 0 / (x^2+4x+20)
(5-x)=0
X=5🙃
👉 0/a = 0 ( a simple mathematical rule)
Х=5
x^3-x^2=100
x^3-x^2-100=0
x^3-x^2-125+25=0
(x^3-5^3)-(x^2-5^2)=0
(x-5)(x^2+5x+25)-(x-5)(x+5)=0
x-5=0 x=5
x^2+5x+25-x-5=0
x^2+4x+20=0
x=[-4+-rq(16-80]/2 =
[-4+-8i/2
x=-2+-4i x=5
How did you get the 1st part of line 5?