To obtain gravitational acceleration 'g' with simple pendulum apparatus | Physics Practical

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#Physicsdemonstrations

[@marthakulujili9744]

"A very tiny bob...a cute one" I agree😭

[@sheldoncooper204]

thankyou for saving our lives before our board practicals sir...i have my practicals in 10 days

[@MakeMeScientific]

Good luck

[@chandraprakash9777]

My today🤣🤣🤣

[@thisuserfeelssolostt]

​@@chandraprakash9777 mine tooooo 😭😭😭😭

[@qamroshkamalansari6648]

I have tomorrow 😂

[@rehanijayasundara_1928]

Thank you for your handwork! It helped me a lot 💜

[@kittinb5603]

At abt 3:00 it will be potential energy not kinetic as kinetic is 0 due to velocity being 0

[@MakeMeScientific]

Noted thanks

[@rehanijayasundara_1928]

Yes 👍

[@chaos-c]

If I get the same stopwatch
I would open your video and perform experiment

[@MakeMeScientific]

Try kar sakte he

[@1K_soon]

Extra ordinary, fantastic, mind blowing sir

[@anshukumari7942]

Thank u sir, tomorrow is my practical

[@plakshagulati3035]

mera bhi bro

[@rehanijayasundara_1928]

Mine too 💜

[@slavoisheir4129]

Mine too

[@pex9134]

mine's in 4 hours

[@sscreation2548]

Tq Sir.... My physics practical exam at today.... 🙏🏻❤

[@MakeMeScientific]

All the best

[@ashmitghosh6717]

Thank you Sir it helped me a lot for my practical exam

[@anushab1077]

It was very useful 👍🏻 thanku you

[@balaramgoswami6783]

Best one. Too useful👌.

[@marshgodgaming4915]

It was very useful 👍👍👍🤘🤘🤘😊

[@suryanshsingh874]

It's awesome 👏👏👏👏👏

[@ce-a2-35siddhikale7]

Thank u👍

[@TanmayDKS]

THANK YOU

[@devbratpaliwal1040]

Thank you sir

[@rekhaabhaykushagra2982]

Nice. Very helpful

[@rishisoni3553]

Its great sir, Thank you so much

[@allinone-wm9ve]

Best video for beginners ❤

[@MakeMeScientific]

Glad you think so!

[@saeedanwar1328]

g00d

[@anamikachaudhary1191]

Thank u so much sir🎉🎉

[@maanyagupta262]

Its great

[@voiceofpresenttruth3119]

Why is it that when i substituted the values in the formula, the answer i got from my calculator is different from your answer.

[@MakeMeScientific]

SMALL VARIATIONS IN ANSWERS ARE ALLOWED, THAT IS DUE TO pi.

[@voiceofpresenttruth3119]

@@MakeMeScientific got it, thanks!

[@user-tw9sh3xe1g]

I substituted the values you stated out but the answer I got is 9.735 why is it different from your own final answer sir

[@MakeMeScientific]

The small error will always come in finding the square root so don't worry

[@vansh_sings]

sir is it necessary to take the length 27.5 cm

[@MakeMeScientific]

You may take any length and conduct the practical

[@vansh_sings]

@@MakeMeScientific thank you sir

[@NDB.]

Thanks

[@MakeMeScientific]

Welcome

[@anushikajain9b884]

Sir we are told to take three to four readings in a single experiment so what should I change to take different readings length or no. of oscillations?

[@voiceofpresenttruth3119]

the length

[@Anzal.__]

I am getting that asnwer by putting the values ,,, Kindly help

[@kusummaurya6090]

Sir I should put T=10.56 or T=1.056

[@kusummaurya6090]

I am getting 966.6 and with T=1.056

[@MakeMeScientific]

1.056

[@a-kgamer2272]

Kis kis ka kal hai

[@TerrenciaVlogs]

Do I have to set my calculator to a specific mode? When I punch in the values for 'acceleration due to gravity' 4π^2 x 27.5 ÷ 1.056^2 ... I got 973.564196761 . What did I do wrong?

[@MakeMeScientific]

Did you place all the units like length in SI or meter? If you have used cm then you will get 973.223 etc in CGS system