you have taken output from wrong point , output is directly connected to input voltage it will always give +vcc output , take the output across CE (put v0 below rc), this is what happen when we do ratta based study , nobody here is even pointing it
Why D1 and D2 are open when A = B = 0? I means our VBB < 0 right? so if the positive side of diode is 0, there is still a chance that diode can be in forward bias.
Even if they are opened base side of transistor will be zero this means it is connected to ground an this situation still our transistor off you are right diodes can be on but you need to focus on transistor because our aim is to switch the transistor
mam in that circuit D1&D2 both diodes are using and both diodes are operating similarly so can we use only one diode instead of both in that place......?
Actually the output is taken just above the transistor collector terminal , and that would solve ur problem. The thing shown in the circuit is wrong in 4th case
ok, so when A and B are given high, then DA and DB are going to be off (open circuited) and no current will be flowing through that part...so D1 will be directly connected to +Vcc through resistance RD and both D1 and D2 will be forward biased and a HIGH logic will be passing through the transistor and the transistor will become ON or short circuited...thats ok upto this,,..my question is, will not be there any effect of -Vbb connected to the base part of the transistor for that particular logic when A and B both are given HIGH at that instant of time? please reply as soon as possible...help me out with this friend please...
madam your schematic base is very good but you lot of confuse how to explain.... i request first you perfect then explain cause " cathod to anode no pwr
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you have taken output from wrong point , output is directly connected to input voltage it will always give +vcc output , take the output across CE (put v0 below rc), this is what happen when we do ratta based study , nobody here is even pointing it
Right
its her choise ;)
Yes you're right... Many have pointed this mistake out.. Not everyone is doing ratta based study...
@@_sadaf_ lol
Out put is not taken correctly.
Your way of explaining is Awesome mam. Thanks for helping us ❤️🙏🙏
Very good teacher for hindi medium students
u are just awesome...........one day before exam teacher!
Excellent way of teaching. 👏
Additional diode D2 increases noise margin and output need to taken from below Rc i.e. directly from the collector
Waah kya likha h
Yeah exactly
Exactly
No bro
Exactly. She has short Vo with Vcc without a resistor in between, which means Vo will always be 1 no matter what the rest of circuit does.
Mam I like u r teaching
Great explanation. Thank you very much! (from Sri lanka)
WOW, now easy for me.❤❤❤❤❤❤
You are connected output directly to the input voltage. So every time it provide only one volt
i love you teaching
Nice explanation
Why D1 and D2 are open when A = B = 0? I means our VBB < 0 right? so if the positive side of diode is 0, there is still a chance that diode can be in forward bias.
Exactly same doubt bro
Even if they are opened base side of transistor will be zero this means it is connected to ground an this situation still our transistor off you are right diodes can be on but you need to focus on transistor because our aim is to switch the transistor
The output must be taken between Rc and the transistor
Yes ,, she had taken the output from wrong point
Excellent teaching 👏 😊
You always save my semeter. Best lec.
Thanks a lot mam🙌🙏
content is good but the way they explains is very confusing. neso academy does a good job in explaining clearly.
Well explained😊Thank you
So nice
Thanku so much madam
thank you so much ma'm .You helped us in our worse times
What is the use of two diode at transistor base. I think One is enough
Tijin Dayi two diode is used to provide proper noisemargin to the circuit
Tijin Dayi k
Is it necessary to connect the output of RTL , above Rc. Normally its connected below Rc
thanks maaah
V out -> between Rc and transistor
The way Vo is shown, it will always be equal to Vcc. Should it be on the other side of Rc?
Thanks
Carry on good
To whoever it may concer, the output y must be taken after the resistancr Rc.
Aritra Roy gosthipaty.... Thank you very much.... I have been worrying about this issue a lot!!.... 😔 U jst cleared my doubt!! Thanks 😊
yeah.. thats what i was debating on..thanks for placing this comment
Agree!
Yes output is after resister
mam in that circuit D1&D2 both diodes are using and both diodes are operating similarly so can we use only one diode instead of both in that place......?
Why base need two diodes??
mam there would be the negative voltage at the base of transistor due to -Vbb in the case of A=1, B=1.
1 NUMBER
Output can take at collector terminal
Mam halki fulki theory bhe de deya kroo ese kese smjh aajyga
why two diodes D1 and D2 are connected, is one diode enough? because two of them work the same. please clear my doubt if possible.
Thanks mam
output voltage seems to be directly connected to the input voltage!!!
yep! the output voltage should be connected below vc voltage....
Actually the output is taken just above the transistor collector terminal , and that would solve ur problem. The thing shown in the circuit is wrong in 4th case
Exactly😂😂😂
How can D1 get off?? The voltage at the anode is not 0. Its 0.7 if a silicone diode is used
ok, so when A and B are given high, then DA and DB are going to be off (open circuited) and no current will be flowing through that part...so D1 will be directly connected to +Vcc through resistance RD and both D1 and D2 will be forward biased and a HIGH logic will be passing through the transistor and the transistor will become ON or short circuited...thats ok upto this,,..my question is, will not be there any effect of -Vbb connected to the base part of the transistor for that particular logic when A and B both are given HIGH at that instant of time? please reply as soon as possible...help me out with this friend please...
if you got to know this, please reply. I have same doubt too
I hav same doubt too!
That's good
Vaalo khub vaalo .....ami samji
For both high input, the output won't be low because the connection of output is near by Vcc
why two diodes D1 & D2 are added? only one diode can also do the same work isnt't it?
Vo is connected at the wrong point in the first diagram. It should be connected to the Collector of the npn-BJT, not Vcc!
Thank
Output always vcc?
yes.
Plz provide Notes plz.....of this topic
which playlist is it from.....
why two diodes are necessary D1 and D2?
at @7:00, when A = 0, B = 0, why do Rd and Rc disappear?
you have explaned wrong concept
madam your schematic base is very good but you lot of confuse how to explain.... i request first you perfect then explain cause " cathod to anode no pwr
Can u explain dtl nor gate
Sir cute🙏
V out should taken at collector
Resistor ka kya kam h?
I need another example please
Why D2 ???
Mam ecl nhi pdaya kya
Why d1 and d2 are there when d1 is enough?
to protect from false triggering
where is note?
Vo nae vcc to ground as short-circuited
× 1.75 👍
your output is wrong position
Mam D3 D4 off kaise hoga
Provide a notes
This is the ALWAYS "1" logic gate if you tie Vo to Vcc. I am not going to subscribe.
Pardeep Kusheterpal ka koi ni muqabla
dont mislead students. Vout point is wrong. And why there are two diodes? what is the purpose?
Mam concept clear karo apne
can you translate into Vietnamese
task failed suscesfuly
Kam.se kam.defination to bta deya kroo
Baneswar Dawo
Brainless
Am not this one
Wrong … got confused after watching your video ..nonsense
Hindi bolne main saram lgti hy
I wish I could understand her but the accent is too thick.
Hindi me padhana tha na Ma'am...☹️😒
ghanta smjhaiya
Thanks
Thanks