Domain : All Students in the world. P(x) : x student has taken more than 21 credit hours in a semester and received all A's. Therefore, ∃x P(x) What about this ?
Domain: All people P(x): x is a student s(x): x has taken more than 21 credits q(x): x has received all "A"' Ex(p(x)^s(x)^q(x)) is it correct? plz reply I've an exam tomorrow
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i have a doubt a11:03 .if s(x) is =>x is richly coloured ,i think we can't say that not of x means x is dull in color .because not of x will mean not richly cololoured .it can also mean that the bird is "okay" coloured.
Domain: all people on the planet earth. P(x): x is a student. Q(x): x has taken more than 21 credit hours in a semester. R(x): x has received all A's. Ans: ∃ x [P(x) ∧ Q(x) ∧ R(x)] "There exists x such that x is a student and x has taken more than 21 credit hours in a semester exam and x has received all A's."
Domain: Set of all the people on the planet S(x) : x is a student C(x): x has taken more than 21 credit hours in a semester A(x): x has received all A's ∃x[S(x)^C(x)^A(x)] Is this correct? If not, please point out the error.
Domain: All people. S(x): x is a student. P(x): x has taken more than 21 credit hrs in a sem. Q(x): x has received all A's. then ∃x (S(x) ^ P(x) ^ Q(x))
Sir, can we write it as this way too? Hope you reply sir :) Domain: All students P(x) : "x has taken more than 21 credit hours in a semester." S(x, y) : "x received y" ∃x[ P(x) ^ ∀y( S(x, y)) ]
H/W prob. ans:
Domain : All students
P(x) : x students has taken more than 21 credit hours in a semester.
Q(x) : x received all A's
So,
∃x[P(x)^Q(x)]
I also got this...
Thoda doubt tha.about selecting the domain
Domain : All Students in the world.
P(x) : x student has taken more than 21 credit hours in a semester and received all A's.
Therefore, ∃x P(x)
What about this ?
so for exactly one student ( a student) it holds ? i thought it would need negation
Domain: All people
P(x): x is a student
s(x): x has taken more than 21 credits
q(x): x has received all "A"'
Ex(p(x)^s(x)^q(x))
is it correct?
plz reply I've an exam tomorrow
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Domain-all student
P(x):x >21 credits in semester
Q(x):x has recieved 'A' in all subjects
-】(p(x)^q(x))
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i have a doubt a11:03 .if s(x) is =>x is richly coloured ,i think we can't say that not of x means x is dull in color .because not of x will mean not richly cololoured .it can also mean that the bird is "okay" coloured.
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birds that do not live on honey are dullin color
can also be written as there exist some bird that does not live on honey and are dullin color
Domain : All students
Let P(x) = x has taken 21 credits
Q(x) = x has received all A's
Answer to 5:45 = ∃x [ P(x) ^ Q(x) ]
Domain: all people on the planet earth.
P(x): x is a student.
Q(x): x has taken more than 21 credit hours in a semester.
R(x): x has received all A's.
Ans: ∃ x [P(x) ∧ Q(x) ∧ R(x)]
"There exists x such that x is a student and x has taken more than 21 credit hours in a semester exam and x has received all A's."
"no large bird live on honey"... is it wrong to negate the Q(x) instead of negating the R(x)?
Thank you so much
Domain: Set of all the people on the planet
S(x) : x is a student
C(x): x has taken more than 21 credit hours in a semester
A(x): x has received all A's
∃x[S(x)^C(x)^A(x)]
Is this correct?
If not, please point out the error.
do dont have to take s(x) because x is already a student as you mentioned for C(x)..only take C(x) and A(x)...
@@codewithsankyy5738 Okay, thanks.
Thanks
Domain: All people.
S(x): x is a student.
P(x): x has taken more than 21 credit hrs in a sem.
Q(x): x has received all A's.
then
∃x (S(x) ^ P(x) ^ Q(x))
My answer is same. Is it correct? plz reply I've midterm exam tomorrow
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Sir please complete discreet mathematics
Sir you said that Operating system and computer networks video are coming in app on 1st week of September. But you didn't upload it?why?
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Sir, can we write it as this way too? Hope you reply sir :)
Domain: All students
P(x) : "x has taken more than 21 credit hours in a semester."
S(x, y) : "x received y"
∃x[ P(x) ^ ∀y( S(x, y)) ]
You must define y,
Keep y as all A's not simple y
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Can we write like this : £ x p(x)
Where p(x): x has taken more than 21 credit hours in a semester and received all A's
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Did bracket matters
yes ofcos
S(x) : is a student
M(x) : taken more than 21 credit hours
A(x) : received all As
∃x(S(x) ∧ M(x) ∧ A(x))
Thanks a lot