Nested Quantifiers (Solved Example 1)

[@c7hu1hu]

it helps to look at it as a game/computer program. The computer gives you either that one specific value (E) and you have to give it all others (For All) to see whether the equation is true in that particular instance/case OR not.

[@Infinitycoder01]

Thanks neso acadamy for helping me in improving my skill and knowledge,so thankful to you..

[@김수연-i4f]

You're totally save my life, Thank you sooo much! love you

[@marlourobles8883]

Thank you! I finished my assignment because of your video!

[@ShadowSilverWolf]

oooo i'm gone finish mine now lamo

[@griffisme4833]

I'm probably missing something but why would the explanation at 6:00 hold? It wants some value y for which any value of x, P(x,y) is true. So just taking one y is ignoring all of the other y's, this seems to be a solution for something like a double universal. My guess was that you would have to find some equation for x such that P(x,y) is always false like x=1-y, then x+y=1-y+y=1 which never equals 0.

[@saidathanikhil.k6415]

No u have got it wrong.

[@rangan__]

The order matters, for every real number of x or y, there are some real numbers of y or x which hold true but the opposite, for some real number y or x, not all real numbers of x or y hold true.

[@caomoletimoloi6565]

Bruh! I m'fing love you. You such a legend my g. Big up

[@horse_keith]

I've struggled with these but not now. ^_^

[@ColorsOfLife114]

Thank you so much for sharing your knowledge with us in this amazing way.

[@JerichoDeGuzman-rm1kd]

Thank you. The Rosen book was a hard read

[@mokhalishale7427]

great tutorial ever thank you so much🙏😻

[@Infinitycoder01]

plz complete discrete mathamatics

[@rockiggo]

Tqu sir ur voice so good to listen

[@dbuc4671]

my god u are a goddamn lifesaver thank you so damn much 🙏🙏🙏 not all heroes wear capes

[@izzy_pk]

THANK YOU

[@EliasMikola]

The best lecture

[@techhub_]

Great, all clear. Thanks a lot

[@nadaaui8411]

BRO YOU ARE DA BESSSSSSSSSSSSSSSSSSSST

[@Natluxurious]

You are amazing for this! Thank you soooooooo much!!!!!

[@dishabyakod8152]

Could u pls make videos on DBMS

[@afeyaraa3490]

Thank you very much ❤️❤️

[@mohamedatheef6284]

crystal clear

[@mouktikchattopadhyay3506]

Thank you very much.

[@erl2698]

Thank you very much God bless you

[@ThierryHagumubuzima]

are negative numbers real numbers?

[@buayo475]

Thanks

[@Shalini1-j7m]

why option 3 is incorrect can't understand..if i took x=-1,y=1 then it satisfy..plz reply

[@Anonymous_user0512]

How r u saying that 4th statement is true

[@clarkgomez4420]

Cus it is true

[@jabril3d959]

Thanks for the grea

[@jabril3d959]

great explanation!*

[@ShadowSilverWolf]

i have question plasea answer me :
(All y )(Exsit x)(x < and equil to y) ?
does it True or False
my techer say false but it seem true ?

[@roshanchaudhary6028]

mention domain as well

[@sandratawfek9576]

@@roshanchaudhary6028
If the domain is R, then it will be true, isn't it?

[@roshanchaudhary6028]

@@sandratawfek9576 its false always
did u know lattice concept ?

[@yawoforiowusuansah6813]

For the first question say my x= 1 and my y= -1 when I add them is equal to zero . Can't that be a truth statement

[@rajeshprajapati1851]

but that will become false when i say x = 1 and y = 1. So, for all x and for all y px is not true. So, first question is false.

[@sheetaluniyal8605]

​@@rajeshprajapati1851 the answer is definitely false I get it but how's it false for all x and for all y there's atleast one exception when x=1 and y=-1 or vice versa 🤔

[@priscakayange2502]

more videos sir

[@EsuYawkal-q1u]

10Q so much

[@zmalik7191]

Example dubara samjha dai koi number say ...

[@rawanbaker4176]

need available to translate Arabic please in subtitle

[@Rahul-yu3ro]

Lol why is it always D that is the correct answer In like all of the videos

[@daniotwtinsae4277]

is (∀𝑥) (∃𝑦)(𝑥 + 𝑦 = 0) equivalent to (∀𝑦) (∃𝑥)(𝑥 + 𝑦 = 0)?

[@dresscheme2940]

Allah Hukbar

[@Akibrot27]

Thank you very much.

[@joyariaakter]

Thank you so much 🎉

[@nebiyudawit6125]

Thank you so much😊