Nested Quantifiers (Solved Example 1)

Discrete Mathematics: Nested Quantifiers - Solved Example
Topics discussed:
1) Finding the truth values of nested quantifiers.
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[@c7hu1hu]

it helps to look at it as a game/computer program. The computer gives you either that one specific value (E) and you have to give it all others (For All) to see whether the equation is true in that particular instance/case OR not.

[@Infinitycoder01]

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[@ColorsOfLife114]

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[@caomoletimoloi6565]

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[@marlourobles8883]

Thank you! I finished my assignment because of your video!

[@ShadowSilverWolf]

oooo i'm gone finish mine now lamo

[@Infinitycoder01]

plz complete discrete mathamatics

[@izzy_pk]

THANK YOU

[@horse_keith]

I've struggled with these but not now. ^_^

[@JerichoDeGuzman-rm1kd]

Thank you. The Rosen book was a hard read

[@griffisme4833]

I'm probably missing something but why would the explanation at 6:00 hold? It wants some value y for which any value of x, P(x,y) is true. So just taking one y is ignoring all of the other y's, this seems to be a solution for something like a double universal. My guess was that you would have to find some equation for x such that P(x,y) is always false like x=1-y, then x+y=1-y+y=1 which never equals 0.

[@saidathanikhil.k6415]

No u have got it wrong.

[@rangan__]

The order matters, for every real number of x or y, there are some real numbers of y or x which hold true but the opposite, for some real number y or x, not all real numbers of x or y hold true.

[@mokhalishale7427]

great tutorial ever thank you so much🙏😻

[@Akibrot27]

Thank you very much.

[@rockiggo]

Tqu sir ur voice so good to listen

[@dishabyakod8152]

Could u pls make videos on DBMS

[@techhub_]

Great, all clear. Thanks a lot

[@nebiyudawit6125]

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[@erl2698]

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[@Natluxurious]

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[@dbuc4671]

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[@ThierryHagumubuzima]

are negative numbers real numbers?

[@apeditz456]

why option 3 is incorrect can't understand..if i took x=-1,y=1 then it satisfy..plz reply

[@buayo475]

Thanks

[@mohamedatheef6284]

crystal clear

[@nadaaui8411]

BRO YOU ARE DA BESSSSSSSSSSSSSSSSSSSST

[@Anonymous_user0512]

How r u saying that 4th statement is true

[@clarkgomez4420]

Cus it is true

[@yawoforiowusuansah6813]

For the first question say my x= 1 and my y= -1 when I add them is equal to zero . Can't that be a truth statement

[@rajeshprajapati1851]

but that will become false when i say x = 1 and y = 1. So, for all x and for all y px is not true. So, first question is false.

[@sheetaluniyal8605]

​@@rajeshprajapati1851 the answer is definitely false I get it but how's it false for all x and for all y there's atleast one exception when x=1 and y=-1 or vice versa 🤔

[@ShadowSilverWolf]

i have question plasea answer me :
(All y )(Exsit x)(x < and equil to y) ?
does it True or False
my techer say false but it seem true ?

[@roshanchaudhary6028]

mention domain as well

[@sandratawfek9576]

@@roshanchaudhary6028
If the domain is R, then it will be true, isn't it?

[@roshanchaudhary6028]

@@sandratawfek9576 its false always
did u know lattice concept ?

[@jabril3d959]

Thanks for the grea

[@jabril3d959]

great explanation!*

[@priscakayange2502]

more videos sir

[@zmalik7191]

Example dubara samjha dai koi number say ...

[@EsuYawkal-q1u]

10Q so much

[@rawanbaker4176]

need available to translate Arabic please in subtitle

[@Rahul-yu3ro]

Lol why is it always D that is the correct answer In like all of the videos

[@daniotwtinsae4277]

is (∀𝑥) (∃𝑦)(𝑥 + 𝑦 = 0) equivalent to (∀𝑦) (∃𝑥)(𝑥 + 𝑦 = 0)?

[@dresscheme2940]

Allah Hukbar

[@joyariaakter]

Thank you so much 🎉

[@mouktikchattopadhyay3506]

Thank you very much.

[@afeyaraa3490]

Thank you very much ❤️❤️