Hi Jesse! I am so thankful for your videos! I have a physics midterm on Tuesday and need to go over all kinematics and forces. So thanks for helping me study! Please keep up the awesome videos! I am sure many many appreciate it as much as I do!
Actually...this was a good explanation. My take away from this was the point about choosing the correct coordinate axis. I never really thought about it that way. I wish I knew that from the first day I took physics.
Hi Andrej! So glad you found them useful. I'm trying to ramp up production this summer and hope to have more out soon. Great to hear from Slovakia! You're the first Slovakian I've heard from!!
Hey Nick! Thanks, man. I've been working on my next video for almost a year now. Hopefully it will be worth the wait! (I work a full-time job, teach a night class and have started freelancing as an accident investigator. Oh yeah, and I have four kids. Weeee!!) Cheers from Detroit!
Excellent !!!... thanks Jesse ..... very clear and thorough from beginning to end!!. nice artwork too.. :D I've enjoyed all your videos that I've seen.... You're a true talent!!
Oh I was so excited when I saw your video in my sub box :D I find those really useful, and maybe im little bit strange, but entertaining too! Make more pls :) Regards from Slovakia
Seriously! you're like a light at the end of a tunnel, which is inside of a , not super, or mega, but ULTRA Massive black hole, at which even light is non existent, you are there JM...I FEEL I BEAT A BLACK HOLE! thanks.
Thanks!, This was a great video and really helped me cram for my AP physics 1 exam. Maybe next time you could do a video for maximum speed to not slide out on a banked curve with friction its a concept that threw me a twirl. and also, Tension or mass of objects where there are multiple pulleys, and multiple masses would be helpful also!
Hey thanks for the video, do you think you can help me find the maximum speed with which you can negotiate the curve so that there is no skidding outward?
Hello Jesse - excellent video here, one of the best I have seen on banked curves with zero friction. --> Could you also do one *with friction*; for example, maximum speed with a given friction coefficient so that there is no sliding upward along the ramp. That will be great. - cheers
Is v the tangential velocity? & The maximum v should be less than the square root of mu x r x g as u have derived. Thanks Does the friction force where the rubber meets the road acts radially inward to counter the tangential velocity on the car moving in a circular motion?
Hello, Long! We didn't rotate our coordinate system to align with the plane like we normally do with inclined planes. This is because the acceleration is toward the center of the turn. Hope that helps!
Theres a "normal" component of acceleration to the banked surface. If instead you do dot product on the radial force, you'll get the same result. If instead the bank was zero, then the radial force component in the normal to surface direction would be zero leading to the result youre used to seeing.
could you please do a video of a banked curve with friction please?
Hi Jesse!
I am so thankful for your videos! I have a physics midterm on Tuesday and need to go over all kinematics and forces. So thanks for helping me study! Please keep up the awesome videos! I am sure many many appreciate it as much as I do!
Glad to be of assistance, Chantal. Best of luck on your midterm!
Such a great job on these... Just stumbled across these somehow. Your preparation and clarity are second to none.
And my production time! LOL Been working on this next one for two years... =)
Actually...this was a good explanation. My take away from this was the point about choosing the correct coordinate axis. I never really thought about it that way. I wish I knew that from the first day I took physics.
Hi Andrej! So glad you found them useful. I'm trying to ramp up production this summer and hope to have more out soon. Great to hear from Slovakia! You're the first Slovakian I've heard from!!
whyd you stop making videos this is really good and not boring to watch, like a lot of educational videos
Hey Nick! Thanks, man. I've been working on my next video for almost a year now. Hopefully it will be worth the wait! (I work a full-time job, teach a night class and have started freelancing as an accident investigator. Oh yeah, and I have four kids. Weeee!!) Cheers from Detroit!
I am glad you are still active and thanks for the help. Keep up the good work and go lions
@@JesseMason I know what it's like to want to do something you love but can't due to responsibilities.
Excellent !!!... thanks Jesse ..... very clear and thorough from beginning to end!!. nice artwork too.. :D I've enjoyed all your videos that I've seen.... You're a true talent!!
AWESOME! you don't get physics tutorials this quality anywhere else, because even I, a 6th grader understood this!
That's quite a compliment - thanks, Aatmodhee! Best of luck with your studies!!
Lover your videos, wish i found them earlier in the semester.
Yeah, I hope teachers will someday put the QR code for my How to Solve Any Physics Problem video on their syllabi. (You could suggest this...) :)
Oh I was so excited when I saw your video in my sub box :D I find those really useful, and maybe im little bit strange, but entertaining too! Make more pls :)
Regards from Slovakia
Best teacher ever
Cheers, Alhammam!
you should do more videos!!!!
you are fantastic mate
Thanks, Habib! I'm working on it...
you are AWESOME!
thank you for the explanation, very clear and helpful
:)
Seriously! you're like a light at the end of a tunnel, which is inside of a , not super, or mega, but ULTRA Massive black hole, at which even light is non existent, you are there JM...I FEEL I BEAT A BLACK HOLE! thanks.
you're awesome, thank you! could you do problems with friction next? also, problems that are very calculus heavy would be helpful.
Fascinating how the solution is derived for such a complex (to me, anyway!) problem.
Very nicely done.
Thanks!, This was a great video and really helped me cram for my AP physics 1 exam. Maybe next time you could do a video for maximum speed to not slide out on a banked curve with friction its a concept that threw me a twirl. and also, Tension or mass of objects where there are multiple pulleys, and multiple masses would be helpful also!
+Jay Marie Thanks for the suggestions, Jay!
Sounds like an interesting problem. Is 0.29 the coefficient of static friction?
Hey thanks for the video, do you think you can help me find the maximum speed with which you can negotiate the curve so that there is no skidding outward?
Hello Jesse - excellent video here, one of the best I have seen on banked curves with zero friction. --> Could you also do one *with friction*; for example, maximum speed with a given friction coefficient so that there is no sliding upward along the ramp. That will be great. - cheers
That's a great idea - will push that up my list toward the front, Bill!
Is v the tangential velocity?
&
The maximum v should be less than the square root of mu x r x g as u have derived.
Thanks
Does the friction force where the rubber meets the road acts radially inward to counter the tangential velocity on the car moving in a circular motion?
Great video!
+Lismaury Galiano Thanks, Lismaury!
could you do a question where it only has friction as it's known value.
Just a doubt; since Nx is in line with the x's array, shouldn't the formula for calculating it from N go as : N cos 15 , and not N sin 15 ?
Thank you very much
You're very welcome, Katie. Cheers from Detroit!
Just saying hello from my part of the world ✊🏾
Cheers from Detroit, cowgate!
Could someone simplify the last calculation? How do you get 16.2 m/s in simple steps?
nice
Thank you, Prince!
I'm accustomed to n = mgcos(theta) on inclined planes. Why is n not mgcos(theta) here? I don't understand why n = mg/cos(theta).
Hello, Long! We didn't rotate our coordinate system to align with the plane like we normally do with inclined planes. This is because the acceleration is toward the center of the turn. Hope that helps!
Theres a "normal" component of acceleration to the banked surface. If instead you do dot product on the radial force, you'll get the same result. If instead the bank was zero, then the radial force component in the normal to surface direction would be zero leading to the result youre used to seeing.
why did you make it so complicated???
TYTYTYTYTYTYTYTYTYTYTYTYTYTYTY!!!!!!!!!!!!!!!!!!