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For a time YT was the shit for free education and now everything is more and more becoming priced again. This is really tragic imo, please don't go that road and find another way. I think some patrons will happily support the channels they love without needing vital content to be exclusive.
I cannot count the amount of times you have made concepts so much easier to understand. I was getting lost on drawing the angle x,y component for N force. Thank you!
What he says actually wasn't correct. The regular incline is the same thing. The difference is that a car traveling on curved bank experiences a centripetal acceleration. There is still the force of gravity exactly as shown in the incline.
You are so good at explaining these concepts. I get lost when my PhD professor tries showing me this stuff, and then I watch your UA-cam video and it all makes sense. Thanks
This video is so helpful, this concept was very confusing from my text explanation but when relating the FBD's of banked curve with incline made so much more sense. Thankyou!
I love this problem. It's so simple, once we know what we are doing. It's good to check if the students actually knows how friction and centripetal force works, :)
I really like your videos. It's more comprehensive than my professors.. If its possible to make a request video/image. Can you recommend me a beginner books for physics? I really appreciate it if you could 😊
I am not sure if you found a book, but take a look at some Pearson textbooks, the year 11 physics pearson textbooks has helped me a lot, and the year 12 physics pearson textbook has some great motion stuff that relates to this topic.
yeah as another commenter mentioned thanks a lot for making the distinction between inclines and curves. My textbook didn't mention it at all for some reason.
Can you please solve the following question for me: A racetrack has a bend at an angle of 10° and has a radius of 200m. A racing car has mass of 750kg and the tyres and the road surface has cofficent of friction 0.6 between them. Find the speed of the car.
I disagree with some points in this video. It's not necessarily the inclined mass is different from the banked curve. The geometry is the same. The difference is that the object is MOVING and experiencing a centripetal acceleration. The difference is that the banked curve involves another force in addition to the gravitational force. You make it sound like it's different...it's not different, it's the same scenario but with an additional force (centripetal) You can equally solve this problem by invoking a centrifugal force (Fc) which acts outward of the circle against the force of gravity along the incline (Fg). Fc = Fg. Where Fc=m*Ax*cos(theta) (the centrifugal force) balancing Fg= mg*sin(theta) (the force of gravity along incline). The centrifugal force component along the incline will be cos(theta) and the normal will be sin(theta). Drawing this out may help to see the geometry m*Ac*cos(theta) = mgsin(theta) v²/r = gsin(theta)/cos(theta) v² = gtan(theta)r The result is the same as the video. But this approach shows more directly why the mass won't slide up or down the incline
Does the friction force where the rubber meets the road acts radially inward to counter the tangential velocity on the car moving in a circular motion?
In this case there is no friction just centripetal acceleration pushing the car into the road so that the weight of the car on the banked curve is just mg. So it's as if the car is on a flat surface , therefore canceling the lateral forces thus making the car not slide up or down.
I don't know if you care anymore, but since this is not on a normal sloped surface Fn is actually the force holding the car in from flying off, serving as centripetal force, not just counteracting a component of Fg. Remember, in circular motion the velocity is tangential to the circular path, so as it resists changes in its velocity and tries to fly off the path (newton's first law), Fn holds it in and keeps accelerating it towards the centre.
Normal force is greater because of the centripetal acceleration in the x direction, so the force in the y direction then becomes great enough to equal mg.
@@singh2702 yeah thx for replying. I had got how this thru gen phys 1. But the thing is that ur answer must be opposite centripetal happens because normal force is greater. By N2L, force causes motion.
@nirow8199 Normal force becomes greater through centripetal acceleration, if there were no acceleration then Normal force would be smaller than mg and object would slide. If that makes sense.
At 14:00, I am not able to get the same answer. I am not getting a number because tan(15) equals a negative number and you cant take the square root of a negative number. Can someone please help me?
tan(15) is not a negative as it is in degrees, your calculator must be in radians. Press Shift + Mode/set up and 3 and it will change it back to degrees, hope this helps!
6.4 A cart at the top of a 0.3km hill has a mass of 420g. What is the cart’s gravitational potential energy? Assuming that energy is conserved and there is no friction, calculate the cart’s speed at the bottom of the hill. Please help me out with this question I have an assignment due tonight😭😭😭I tried doing it but I just can’t get it
Firstly, we use the law of conservation to link that the potential energy of the cart at the top will be equal to the kinetic energy at the bottom. E(Potential) = E(Kinetic) We then calculate potential energy E(Potential) = 0.5 * m * h = 0.5 * 9.8 * 0.42 E = 2.058 N With this value of potential energy, we know that is the kinetic energy at the bottom as described before. We can now plug this value into the kinetic energy formula where we can then solve for velocity. E(kinetic) = mv^2 2.058 = 0.42 * v^2 2.058 / 0.42 = v^2 v = 2.2ms-1 (2 s.f)
On banked road there is centripetal acceleration in the x direction which increases the Normal force. On a regular inclined plane there is no countering acceleration to keep an object from sliding.
Circular Motion - Formula Sheet: bit.ly/4gIUL3r
Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html
Full-Length Videos & Exams: www.patreon.com/MathScienceTutor/collections
Full 1 Hour Video on Patreon: www.patreon.com/MathScienceTutor
Direct Link to The Full Video: bit.ly/3IpbPfW
For a time YT was the shit for free education and now everything is more and more becoming priced again. This is really tragic imo, please don't go that road and find another way. I think some patrons will happily support the channels they love without needing vital content to be exclusive.
Plsss can you tell me why a car travels at a higher speed when the curve track is banked
I cannot count the amount of times you have made concepts so much easier to understand. I was getting lost on drawing the angle x,y component for N force. Thank you!
The distinction between a regular incline and a curve helped a lot. I was getting confused when I looked at my notes.
for real man i was wondering the same thing
hi there can we bank a road without forming an angle whith frictional force????😢
What he says actually wasn't correct. The regular incline is the same thing. The difference is that a car traveling on curved bank experiences a centripetal acceleration. There is still the force of gravity exactly as shown in the incline.
thanks daddy hopefully im ready for my physics test
lmaooo same 🙏
I really hate math but i never hate the man who's behind this voice 🔥🥰
You are so good at explaining these concepts. I get lost when my PhD professor tries showing me this stuff, and then I watch your UA-cam video and it all makes sense. Thanks
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I'm trying to self study AP Physics 1 and this video really helped me!
way. WAY better than my prof's 'explanation'. istg. thank you so much.
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Do you guys have any account that has subscribed to his channel on Patreon? I need it but i Cant afford it :( I really need for my final exam!😭😭
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This video is so helpful, this concept was very confusing from my text explanation but when relating the FBD's of banked curve with incline made so much more sense. Thankyou!
I love this problem. It's so simple, once we know what we are doing. It's good to check if the students actually knows how friction and centripetal force works, :)
It's fucking not
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LMAO
NGL From Activities to Exams thank you for assisting us.
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I really like your videos. It's more comprehensive than my professors.. If its possible to make a request video/image. Can you recommend me a beginner books for physics? I really appreciate it if you could 😊
I am not sure if you found a book, but take a look at some Pearson textbooks, the year 11 physics pearson textbooks has helped me a lot, and the year 12 physics pearson textbook has some great motion stuff that relates to this topic.
Do you guys have any account that has subscribed to his channel on Patreon? I need it but i Cant afford it :(
@@alexkent9599 yeah for a time youtube was the shit for free education and now more and more everything is becoming priced again. Really tragic :(
If anyone have account subscribed to the channel, can you please lend me your account for my exam 🙏🏻
@@alexkent9599 Nobody do that! DON'T give your password to ANYONE on the internet! Very dangerous!
yeah as another commenter mentioned thanks a lot for making the distinction between inclines and curves. My textbook didn't mention it at all for some reason.
my guy you're a genius
Thank you so much!!!
Brilliant. Thankyou
Watching this 40min before final!!
sir , can i request :The Frame of Reference .
i like your teaching the way you explain the concept
I like this position, do you?
In an exam do we need to derive the formula for design speed?
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Can you please solve the following question for me:
A racetrack has a bend at an angle of 10° and has a radius of 200m. A racing car has mass of 750kg and the tyres and the road surface has cofficent of friction 0.6 between them. Find the speed of the car.
41.66 meters per second
I disagree with some points in this video. It's not necessarily the inclined mass is different from the banked curve. The geometry is the same. The difference is that the object is MOVING and experiencing a centripetal acceleration. The difference is that the banked curve involves another force in addition to the gravitational force. You make it sound like it's different...it's not different, it's the same scenario but with an additional force (centripetal)
You can equally solve this problem by invoking a centrifugal force (Fc) which acts outward of the circle against the force of gravity along the incline (Fg).
Fc = Fg. Where Fc=m*Ax*cos(theta) (the centrifugal force) balancing Fg= mg*sin(theta) (the force of gravity along incline). The centrifugal force component along the incline will be cos(theta) and the normal will be sin(theta). Drawing this out may help to see the geometry
m*Ac*cos(theta) = mgsin(theta)
v²/r = gsin(theta)/cos(theta)
v² = gtan(theta)r
The result is the same as the video. But this approach shows more directly why the mass won't slide up or down the incline
thanks alot😊
watched this whole video only to realise my big mistake was forgetting to change the units
you the goatttt
Thank you for this
Does the friction force where the rubber meets the road acts radially inward to counter the tangential velocity on the car moving in a circular motion?
In this case there is no friction just centripetal acceleration pushing the car into the road so that the weight of the car on the banked curve is just mg. So it's as if the car is on a flat surface , therefore canceling the lateral forces thus making the car not slide up or down.
what about when there's friction involved? I'm stuck
5:00
If Fn is mg cos@ and Fny is Fncos@, how is Fny=mg?
Shouldn't it be Fny=mg×cos²@?
I don't know if you care anymore, but since this is not on a normal sloped surface Fn is actually the force holding the car in from flying off, serving as centripetal force, not just counteracting a component of Fg. Remember, in circular motion the velocity is tangential to the circular path, so as it resists changes in its velocity and tries to fly off the path (newton's first law), Fn holds it in and keeps accelerating it towards the centre.
Thank you very much🙂
@JG tutorial why does a car travel at a higher speed when the road is banked
thanks alot
Can you please do a motion in accelerated frames video🙏
God bless you
I cannot understand. How can Fn have higher value than applied one (gravity). If the gravity equals Fny, then it means Fn > Fg.
Normal force is greater because of the centripetal acceleration in the x direction, so the force in the y direction then becomes great enough to equal mg.
@@singh2702 yeah thx for replying. I had got how this thru gen phys 1. But the thing is that ur answer must be opposite centripetal happens because normal force is greater. By N2L, force causes motion.
@nirow8199 Normal force becomes greater through centripetal acceleration, if there were no acceleration then Normal force would be smaller than mg and object would slide. If that makes sense.
@@singh2702 Yeah but the acceleration is result, forces are always cause
@@singh2702 In atomic size, it makes more sense
At 14:00, I am not able to get the same answer. I am not getting a number because tan(15) equals a negative number and you cant take the square root of a negative number. Can someone please help me?
tan(15) is not a negative as it is in degrees, your calculator must be in radians. Press Shift + Mode/set up and 3 and it will change it back to degrees, hope this helps!
Do you guys have any account that has subscribed to his channel on Patreon? I need it but i Cant afford it :( I really need for my final exam!😭😭
6.4 A cart at the top of a 0.3km hill has a mass of 420g. What is the cart’s gravitational potential energy? Assuming that energy is conserved and there is no friction, calculate the cart’s speed at the bottom of the hill.
Please help me out with this question I have an assignment due tonight😭😭😭I tried doing it but I just can’t get it
Firstly, we use the law of conservation to link that the potential energy of the cart at the top will be equal to the kinetic energy at the bottom.
E(Potential) = E(Kinetic)
We then calculate potential energy
E(Potential) = 0.5 * m * h
= 0.5 * 9.8 * 0.42
E = 2.058 N
With this value of potential energy, we know that is the kinetic energy at the bottom as described before. We can now plug this value into the kinetic energy formula where we can then solve for velocity.
E(kinetic) = mv^2
2.058 = 0.42 * v^2
2.058 / 0.42 = v^2
v = 2.2ms-1 (2 s.f)
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@@rxpe thank you so much 😊
Jeff L wrong, PE=mgh
Thought it said bonked tracks lmao
Dropping booms 💣🚬💥💥💥🤧
Why there is difference between regular inclined plane and bank road ???
On banked road there is centripetal acceleration in the x direction which increases the Normal force. On a regular inclined plane there is no countering acceleration to keep an object from sliding.
Why is the angle used 45 degrees instead of 15 as stated in the problem?
He just used that to explain some concepts
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Where are the comments??
Im finding the 'Do you like this position😩' comments lol. But it got deleted (?)
he reposted the vid i think
4:05
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First
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