Another method: Sum=8 Product=48 ---> u^2 - 8u+48=0 u=4(-/+)√(16-48)= 4(-/+)√(-32)= =4 (-/+) i 4√2 Solution: ( n ; m )= (4+i√2 ; 4-i√2) or ( m ; n )= (4-i√2 ; 4+i√2)
Another method: Sum=8 Product=48 ---> u^2 - 8u+48=0 u=4(-/+)√(16-48)= 4(-/+)√(-32)= =4 (-/+) i 4√2 Solution: ( n ; m )= (4+i√2 ; 4-i√2) or ( m ; n )= (4-i√2 ; 4+i√2)
Another method:
Sum=8
Product=48
---> u^2 - 8u+48=0
u=4(-/+)√(16-48)= 4(-/+)√(-32)=
=4 (-/+) i 4√2
Solution:
( n ; m )= (4+i√2 ; 4-i√2)
or
( m ; n )= (4-i√2 ; 4+i√2)
Too good Boss😊
Thanks for sharing your brilliant solution😊
@@ExploredMaths you are too kind 😁😁😁, your video is clear and precise
@giorgiogiorgi8931 Thankyou so much🥰
Greatness is all yours☺️
One that is a little bit easier, great :)
Yes.
Of course 😊
m = 8 - n
( 8 - n )n = 48
n^2 - 8n + 48 = 0
D = - 128 < 0 no soluzioni reali
n = 4 +/- 4 i sqrx( 2 )
(m,n) = { ( (4+4i sqrx(2) ) , (4-4i sqrx(2) ) ) ,
( (4-4i sqrx(2) ) , (4+4i sqrx(2) ) ) }
👍😁🤪👋
Great solution Boss.
Thanks for sharing ☺️
This is not an elegant method.
Use m.n =( (m+n)/2)^2 - ( (m-n)/2)^2
Okay Boss🙂
Another method:
Sum=8
Product=48
---> u^2 - 8u+48=0
u=4(-/+)√(16-48)= 4(-/+)√(-32)=
=4 (-/+) i 4√2
Solution:
( n ; m )= (4+i√2 ; 4-i√2)
or
( m ; n )= (4-i√2 ; 4+i√2)
nis +4 or -12. So the other also the other way.
Vai dar banho ao cão .
Okay 😐
Why would olympiad give such easy equation that not even worth 2 marks?
I think its not easy at first glimpse for everyone...the solution is infact easy.