Studying for GAMSAT medical school admissions exam in the UK. You two are the best teachers I have come across on the internet in 6 months. Thank you so much.
Hi your vedios are alot of help. but i have a question. the velocity wont be 0 at the top but the potential energy of the spring will turn in to eithier gravitational potential energy or the kinetic energy. what if the question was, what is the velocity the marble will leave with. Am i right?
this is quite excellent for my MCAT studying, I was wondering do you guys teach electrostatics, magnetism etc for your 12th graders? I went to a highschool where we did not even have a decent physics teacher...
At 4:50 you said at the top the velocity would be 0. my question is how would the velocity be 0 since the mass would have some velocity going up in its flight?
@physicshelpcanada Thank you for your videos they are extremely helpful but I do not understand why 5cm were subtracted at the end, is h=delta h, as in h final - h initial?
NVM I guess h = maximum height of marble - height of spring unstretched therefore if the question was what is the maximum height of the marble above the compressed spring the answer would h = maximum height of marble - height of spring compressed, 6.25cm - 0cm = 6.25cm
Two other things. Sorry. At the bottom, wouldn't the marble have some potential energy vis-a-vis the ground? and On the free body diagram, should we show a normal force?
Hi your vedios are alot of help. but i have a question. the velocity wont be 0 at the top but the potential energy of the spring will turn in to eithier gravitational potential energy or the kinetic energy. what if the question was, what is the velocity the marble will leave with. Am i right?
Excellent videos as usual. The only thing I am confused about is the answer in realtion to the UNSTRETCHED spring. Is the answer of 6.25cm correct in relation to the unstretched spring. At the bottom the spring is not stretched at all, it's compressed. At the top, the spring is completely stretched in relation to the bottom. So, the marble is 1.25 cm above the stretched spring, and 6.25cm above the compressed spring. Am i wrong????
Studying for GAMSAT medical school admissions exam in the UK. You two are the best teachers I have come across on the internet in 6 months. Thank you so much.
great sfx at 4:12 You guys don't know how much you have helped me. Thanks a lot!
@dinosawrawrr Thanks for letting us know. We're glad to help.
Finally a decent physics channel!
@hrm1785 Hi. Thanks for the compliment. We're glad we could help.
Hi your vedios are alot of help. but i have a question. the velocity wont be 0 at the top but the potential energy of the spring will turn in to eithier gravitational potential energy or the kinetic energy. what if the question was, what is the velocity the marble will leave with. Am i right?
this is quite excellent for my MCAT studying, I was wondering do you guys teach electrostatics, magnetism etc for your 12th graders? I went to a highschool where we did not even have a decent physics teacher...
You are great! all the best !
@harisrg92 since all objects thrown up slow down due to gravity, then the highest point of the object's flight would be when it reaches 0 velocity.
These videos help out so much!! :) Thank you
At 4:50
you said at the top the velocity would be 0.
my question is how would the velocity be 0 since the mass would have some velocity going up in its flight?
@physicshelpcanada Thank you for your videos they are extremely helpful but I do not understand why 5cm were subtracted at the end, is h=delta h, as in h final - h initial?
NVM I guess h = maximum height of marble - height of spring unstretched therefore if the question was what is the maximum height of the marble above the compressed spring the answer would h = maximum height of marble - height of spring compressed, 6.25cm - 0cm = 6.25cm
@MrKicks2010 We have not covered that topic yet but hope to someday. Good luck with your MCAT studies.
Two other things. Sorry.
At the bottom, wouldn't the marble have some potential energy vis-a-vis the ground?
and
On the free body diagram, should we show a normal force?
How come you used kx at 1:40 but not 1/2 kx^2 ?
Hi your vedios are alot of help. but i have a question. the velocity wont be 0 at the top but the potential energy of the spring will turn in to eithier gravitational potential energy or the kinetic energy. what if the question was, what is the velocity the marble will leave with. Am i right?
No u r wrong
then please clairify your point cause i wanna know where i am wrong
i do not got , why the velocity will be zero at top?
Excellent videos as usual. The only thing I am confused about is the answer in realtion to the UNSTRETCHED spring. Is the answer of 6.25cm correct in relation to the unstretched spring. At the bottom the spring is not stretched at all, it's compressed. At the top, the spring is completely stretched in relation to the bottom. So, the marble is 1.25 cm above the stretched spring, and 6.25cm above the compressed spring.
Am i wrong????
No, I don't think you are.
What I meant was I don't think you are wrong.
Ignore the last two replies, watch the full video.
Your beard is amazing