My teacher suggests to draw a rectangle between the two vertices using a and b so that the asymtotes of the hyperbola go through the corners of the rectangle
@@Haza-rp1cb It was some time, but I was taking Trig/Pre-Calc and received an A. Currently, I just finished Differential Equations, Linear Algebra, Calc 3 multi-variables and Physics Optics all in one semester! It was brutal lol. I still come back to these videos time to time when I forget how to factor and other tricks. With that out of the way, I’m going to attend UCLA for Electrical Engineering this Fall to finish all these EE courses. Hope all is well for you and you achieve the goals you pursue. Thank you for checking in with me. :)
You are a great teacher, i get to know the equations when you were the one who explains how, my teacher, I really didn't get every single thing from her, thanks Sir Brian!!!! High School Student here!!!
Uhm sir, its a very good video you have :). It can easily be understood compared to the actual lessons I take at school lol I give you a thumbs up but the center is represented as (h, k). Why is the 'k' on getting the asymptote is '3'? Then on 'h' is '-2'? Wasn't the center (3,-2)? Edit: Whoops I should've watched the whole video 😂😆 sorry about that sir hahaha thanks for the vid! it truly helps.
Umm no a^2 being the bigger term only applies to ellipsis, a^2 and b^2 here in hyperbolas are always fixed, and he already said it was going to be horizontal
In the case of hyperbolas, it doesn't matter whether a^2 or b^2 is greater, but which term is negative. So in this case, the y side, or (y+2)^2/16 was negative so it is horizontal. If the (x-3)^2/4 was negative then is would be vertical. This is because the formula for hyperbolas, the terms have different signs, unlike ellipses which have the same sign for both terms. Sorry if my terminology isn't completely accurate, but I hope it still makes some sense.
unlike ellipses, hyperbolas have equations containing a minus sign. the variable of the term in front is what determines whether the graph is vertical or horizontal. because the x term comes before the y term in the equation (it is the x term minus the y term), the graph is horizontal. i hope that helped lol
Hey, just wanted to start with great video! I really do enjoy your content. I was wondering if I subscribed would i get notified when you upload a new video? I would really love that instead of always coming back to your channel. Thanks!
While I appreciate your teaching and your accepting of corrections (something many teachers get childishly mad over), it's unnecessary to use gendered words (especially when only 2 are mentioned and exclude all others) when addressing the students/audience. You can still get your point across perfectly well without excluding nonbinary people, agender people, gender fluid people, etc, by just addressing your students with gender neutral words :) it's polite, inclusive, and the correct way to address others when one doesn't know their audiences' gender. Thank you
You should have skipped to the part where you fixed your mistake. I just wasted a whole piece of paper and ten minutes of my time on something you didn’t even get right. Thanks for the waste. Not watching again.
Brian, you're a great teacher (and a life saver)
6:38 for those who dont get why k was equal to 3, you’re welcome :))
Thanx man
Your videos may be the only reason I pass college level algebra. Thank you!
Watching you teach makes me realize how much my teacher sucks
Lee Lorenz. She may have feelings, but not for her students 😔 I can’t blame her tho, she has 2 kids
Same bro i can feel u
@@leelorenz.3889 No one cares
@@esther9210 I do care, now stfu
@@Mama03514 no one cares that you care
Since the formula for asymptotes goes h,k wouldn't k be -2 because it is horizontal? Formula for vertical is k,h right?
Agreed
Totally agree with u
Pls enlighten me about this huehue
Yes I think he reversed them-totally agree. But thank god for Brian I totally understand anyways!
My teacher suggests to draw a rectangle between the two vertices using a and b so that the asymtotes of the hyperbola go through the corners of the rectangle
agreed. That is actually a little simpler
Best math teacher. Have to come for you for my finals since I completely forgot about this. Thank you very much for such great content.
you are very welcome! Best of luck on your final!
howd it go bro
@@Haza-rp1cb It was some time, but I was taking Trig/Pre-Calc and received an A. Currently, I just finished Differential Equations, Linear Algebra, Calc 3 multi-variables and Physics Optics all in one semester! It was brutal lol. I still come back to these videos time to time when I forget how to factor and other tricks. With that out of the way, I’m going to attend UCLA for Electrical Engineering this Fall to finish all these EE courses. Hope all is well for you and you achieve the goals you pursue. Thank you for checking in with me. :)
@@kingvirginiaverg7528 thank you king didn’t expect a 5 year old comment to reply an hour later looollll hope Your doing fine bro
Very helpful video! Thanks so much for uploading such great content. I can actually understand
You are a great teacher, i get to know the equations when you were the one who explains how, my teacher, I really didn't get every single thing from her, thanks Sir Brian!!!!
High School Student here!!!
who give that much hw? 1-108 wtf
sandy simon haha I like to mess with my students from time to time
What I've learned from you're videos is that even teachers and great mathematicians make mistakes.
Sir your another y should be -2x +3 since we minus positive 5 to - 2, but the rest is brilliant, I easily get it. Thanks to you
Thankyou! My professor is putting this on the test even though he never got to this section....
@ 8:23, how do i know the values of the pattern, "up two, over one" where did that pattern come from? Thanks!
i cant find any videos explaining what to do if the equation doesn't equal to 1
do you have the answers now?
I know I’m a little late but if it doesn’t equal 1, then I believe you divide every side by that number so that is equals one.
@@Jesus_freak0 dude you’re like 4 years late 😭
It's good to have you as our life savwry
Uhm sir, its a very good video you have :). It can easily be understood compared to the actual lessons I take at school lol I give you a thumbs up but the center is represented as (h, k). Why is the 'k' on getting the asymptote is '3'? Then on 'h' is '-2'? Wasn't the center (3,-2)?
Edit: Whoops I should've watched the whole video 😂😆 sorry about that sir hahaha thanks for the vid! it truly helps.
Hello where did the 2 vertex get from?
I thought a^2 is always the bigger term, so in this case since 16>4, it would be a vertically opening hyperbola?
Umm no a^2 being the bigger term only applies to ellipsis, a^2 and b^2 here in hyperbolas are always fixed, and he already said it was going to be horizontal
In the case of hyperbolas, it doesn't matter whether a^2 or b^2 is greater, but which term is negative. So in this case, the y side, or (y+2)^2/16 was negative so it is horizontal. If the (x-3)^2/4 was negative then is would be vertical. This is because the formula for hyperbolas, the terms have different signs, unlike ellipses which have the same sign for both terms. Sorry if my terminology isn't completely accurate, but I hope it still makes some sense.
Isn't the a² is dominant so 16 should be a² because it is much bigger than 4?
That’s for ellipses. With hyperbolas it’s a-b.
Wait I’m kinda confused cause isn’t ur b^2 bigger than ur a^2 cause it’s 16? so wouldn’t it be vertical instead of horizontal?
unlike ellipses, hyperbolas have equations containing a minus sign. the variable of the term in front is what determines whether the graph is vertical or horizontal. because the x term comes before the y term in the equation (it is the x term minus the y term), the graph is horizontal. i hope that helped lol
@@jaycee8624 omg i saw this just now but thank you so much, it helped!!
thank u needed the test reviwe
i love this man so much
In the asymptotes k=-2, why did you plug in the 3 sir?
Yeah thats what I saw
is it always y=k+ - b/a(x-h)??
Big fan from Pakistan
who else realized he made several mistake and tried to tell him and couldnt
is it necessary to graph the auxiliary rectangle?
no I just like to for the visual path of the asymptotes
Hey, just wanted to start with great video! I really do enjoy your content. I was wondering if I subscribed would i get notified when you upload a new video? I would really love that instead of always coming back to your channel. Thanks!
yes, that is the idea of subscribing but to get all of the notifications you will also want to click the bell
Is it actually c^2=a^2+b^2 or c^2=a^2-b^2?
THANK YOU because my teacher doesn't teach at all!!
Relate much
is a^2 and b^2 can be 0?
You should make merches like a mathematical shirt and put it to sell
Shouldn’t the vertices always be on the outside?
The vertices should be on the hyperbola itself
Very helpful :)
+Mashuzuu thank you, happy to help!
what down 2 negative 1 how do u know?
-2 can be written as -2/1 and we want the fraction for using slope to graph, -2 came from the asymptote formula
Oh my gosh i was watching the video normally, and then i noticed the marker caps that were switched, and now i cant stop looking at it..
haha yes a bad habit of mine
sir i notice that x-h is x-3 so in the asymptote would it be x-3 not x-2?
same also in the value of k?
sorry Sir. i jump into conclusion, i didn't finish your video at all, sorry! peaceyow
no worries! happy to be able to help
He normally writes a 2 without za loop, but when he has to rewrite a 2 as a correction he adds the loop... how interesting
Pay attention to the math goddamnit.
Thanks!
Legend
Can someone please explain to me the meaning of "Asymptote" in simple words?
it is an imaginary line that the graphed line will never reach.
It's vertical, because a is always the bigger value than b
Great video.... I didn't know how to draw assymptots before..... But what was up 2 over 1😕😕😕😕😟
the slope
I thought positive will be the a?
i think k=-2
yes it is
it not useful to follow along if the teacher makes a mistake
While I appreciate your teaching and your accepting of corrections (something many teachers get childishly mad over), it's unnecessary to use gendered words (especially when only 2 are mentioned and exclude all others) when addressing the students/audience. You can still get your point across perfectly well without excluding nonbinary people, agender people, gender fluid people, etc, by just addressing your students with gender neutral words :) it's polite, inclusive, and the correct way to address others when one doesn't know their audiences' gender. Thank you
root under 20 is 5 root under 2,its not 2 root under 5
In hyperbola a>b. I can't understand Plz clear my concept..
The fuck am I brain dead or something, why is k 3 in the asymptotic equation, doesn’t it equal 2?
you’re pronouncing foci wrong buddy
Yeah h and k is wrong
why?
@@brianmclogan on the final graph there in the wrong place
wrong
it's wrong
Can I go to the bathroom?
No
,
.
This is wrong a will always be greater than b in hyperbola
That's ellipses honey
those learners dont follow
they cant correct those simple error
You should have skipped to the part where you fixed your mistake. I just wasted a whole piece of paper and ten minutes of my time on something you didn’t even get right. Thanks for the waste. Not watching again.