Conic Sections - Free Formula Sheet: bit.ly/4fyZTWA Direct Link to The Full Video: bit.ly/3BrmXSN Full 1 Hour 40 Minute Video: www.patreon.com/MathScienceTutor
You’re literally the only reason I actually pass maths😭 and physics- thanks so much for all your awesome videos and just explaining things so well😭 you’re a heaven sent. God bless you
I'm very thankful to you. I don't know how big the help you've given to me, all I know is I pass all the module I have with learnings because of your videos...
The timing of this video is superb. I am currently having activities about hyperbolas in my math of measurements in 1st yr Civil Eng. Thank you sir! I wished I was able to see your videos when I was taking this way back in shs. Nonetheless, thank you for being our best teacher. Your voice is really soothing 🤧
This video is saving my life right now and I appreciate the work, but in the minute 26:15, the Asymptote equation is y - 3 = ± 3/2 (x +2). This is because it is horizontal not vertical 🤨
Professor Organic Chemistry Tutor, thank you once again for a fantastic explanation and description of Hyperbolas in Calculus Two. Conic Sections, which includes Hyperbolas, are used in multiple courses in Science and Engineering. This is an error free video/lecture on UA-cam TV with the Organic Chemistry Tutor.
Should make some videos on - unit hyperbola - hyperbolic functions - inverse hyperbolic functions - hyperbolic relations / identities - their integrals / derivatives / substitutions
dude transformed me from a dummy who cant understand what the teachers are talking about to actually participating and understanding the lessons they give
If you are referring to the transverse axis, then it is decided by the numerator terms. For example, if the variable y came first it would have a vertical transverse axis. I hope I helped😀
》Theres a question in the end, but the video ends, here's my answer: F(±c,0) [formula] Given: F(±3,0) -----> *c* is 3 here V(±a,0) Given: V(±2,0) -----> *a* is 2 here To find " *b* ": c²=a²+b² 3²=2²+b² 9=4+b² *b²* =5 To convert it in *standard form* : x²/a² - y²/b² =1 (Note: we know its a left and right hyperbola because the focus here is in the x coordinate) Substitute the values *x²/4 - y²/5 =1* Now, to find the *domain* and *range* : D(-inf,-2] U[2, inf) R(-inf, inf)
Conic Sections - Free Formula Sheet: bit.ly/4fyZTWA
Direct Link to The Full Video: bit.ly/3BrmXSN
Full 1 Hour 40 Minute Video: www.patreon.com/MathScienceTutor
Benefial sana
You’re literally the only reason I actually pass maths😭 and physics- thanks so much for all your awesome videos and just explaining things so well😭 you’re a heaven sent. God bless you
Maffs innit
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Sammmmeeee
Hi are you African
@@felixelijah9326 I am
The timing of this video is impeccable.
I recently got my precalculus, and conic sections is my first unit.
How’d you do in the class
Are u in stem
@@emelynsarueda1498 im in stem, you too? Pinoy nga ba naman hahahha
@@MashNoLife anong connect nun sa pagiging pinoy
@@patheticweebs3656 hahahahaha
Math is my worst subject and I can not understand it but you explain it so well, you're truly a genius.
Appreciate how you take the time to write and explain your steps of solving in each instance!
tysmm. I was sick and absent for 3 days and watched your videos to teach myself at home. You explain it perfectly and slowly. Awesome.
You're literally in my list of heroes ri admire, thanks sir for helping us students and explaining in simple terms.
Thank u sm, mas naiintindihan ko to kesa sa teacher namin.
Tomorrow is our math departmental exam. This is a huge help for me thanks man!
Good luck
I really appreciate you, I'm borderline A and being absent for a week bc of covid was a real struggle. Thank you for your service
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agreed
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You are the best in terms of teaching. You are the one who made me to love mathematics in my life ever
I'm very thankful to you. I don't know how big the help you've given to me, all I know is I pass all the module I have with learnings because of your videos...
Best maths and science teacher on the internet.
literally the only reason why i got my hw done! tysm
The timing of this video is superb. I am currently having activities about hyperbolas in my math of measurements in 1st yr Civil Eng. Thank you sir! I wished I was able to see your videos when I was taking this way back in shs. Nonetheless, thank you for being our best teacher. Your voice is really soothing 🤧
Same here first year 1st semester in Civil engineering
I'm doing scholarship maths
This is a real analysis of calculus, continue feeding us with the best calculus explanations.
Analytical geometry exam tomorrow morning and am more than ready to tackle it courtesy of your tutorials.blessings😍
You literally taught me this hyperbola and I'm teaching my students real good.
What my teacher couldnt explain to me for hours u did it in 20 minutes my guy thank you so much
Did you pass as expected?
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I thanked u so many times and I’m doing it again. U help me so much thru online school and now. Thx
Thanks for making the beginning of 11th Grade easier.
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You explained this very well! May Allah bless you.
This video is saving my life right now and I appreciate the work, but in the minute 26:15, the Asymptote equation is y - 3 = ± 3/2 (x +2). This is because it is horizontal not vertical 🤨
it’s correct, what is bro on abt😭
do you even know what vertical and horizontal is
You are the best ... continue with your explain to physic about angular speed , please 🙏...
thank you very much for this! I finally finished my activity 😭
after im done with school I am never touching a math book ever again
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Grabi ka naman
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the more i watch ur vids, the more i realize thta i might have a crush on u tysm for helping me w math
Tf
Damn, he might have a wife already
I have an A this semester once I started watching ur vids. I had an 80% last semester
Professor Organic Chemistry Tutor, thank you once again for a fantastic explanation and description of Hyperbolas in Calculus Two. Conic Sections, which includes Hyperbolas, are used in multiple courses in Science and Engineering. This is an error free video/lecture on UA-cam TV with the Organic Chemistry Tutor.
Thank You so Much Sir I really appreciate your Work 😊💗
the way you explain it simple and clear is fantastic. thanks
this video is so helpful, thank you so much!
Thanks alot you deserve a prize but MAY THE LORD BLESS THE WORK OF YOUR HANDS 💯😇
You have saved my semester thanks be blessed
Man I'm taking accelerated maths couldn't understand this shit when my teacher did it, you are a god send.
Infact prof ,your explanation is always on point and bring more understanding ❤
you explain this much better than my trigonometry professor
you're a gift from God to us, JG
Should make some videos on
- unit hyperbola
- hyperbolic functions
- inverse hyperbolic functions
- hyperbolic relations / identities
- their integrals / derivatives / substitutions
Literally very nice explaination of every single topic .thanku sir ....
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Great stuff!
Well done.
Peter Kelly.
respect♥♥
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Thank you for this, Sir🥺❤️
where do you get the relation of c^2 = a^2 + b^2 ? does it has something to do with pythagorean theory?
I should've search for this earlier its math exam tmr 🙏🏻😭
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dude transformed me from a dummy who cant understand what the teachers are talking about to actually participating and understanding the lessons they give
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Clear as a bell, again. I looked at two other videos and were very confusing.
Shout out to you "" JG "" you are a healer to me .
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Wonderful, Hope there's Parabola alone
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STEM pa. makinig kase sa klase yan tuloy nakatambay ka sa YT.
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I’m trying to become a architect and they say that u need physics and math can u make. A video on it
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Always better than my teachers
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Well explained. Thank you so much sir .
Great work, Thanks.. ❤
Please can you upload a video on derivative of hyperbolic functions please 😔😔
Sir can you please make a video in this problem f(x)= (x+ 1/x)^2 find its derivative. Im really confused thank you
-2(x+1)/x cube
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i love you so much you are a blessing
Well explained sir...thanks a lot
Thank you for this sir
Hi sir
Please assist with the name of the app or software u are using
How to determine the center and orientation of the principal axis of hyperbola?
If you are referring to the transverse axis, then it is decided by the numerator terms. For example, if the variable y came first it would have a vertical transverse axis. I hope I helped😀
What about the equations of the conjugate hyperbola of a horizontal hyperbola and the conjugate hyperbola of a vertical hyperbola?
Thank you so much
The only reason ive gotten 85s and higher on my math tests is because of your videos
Trash
Would you plz add derivatives of hyperbolic functions?
Thank you for this. It really helped me in my reviews💓
Good work, very brilliant I must say
However, there's room for improvement. Sometimes, the wofi gets to clumsy, see to that.
Thanks
Thanks for the lecture
》Theres a question in the end, but the video ends, here's my answer:
F(±c,0) [formula]
Given: F(±3,0) -----> *c* is 3 here
V(±a,0)
Given: V(±2,0) -----> *a* is 2 here
To find " *b* ":
c²=a²+b²
3²=2²+b²
9=4+b²
*b²* =5
To convert it in *standard form* :
x²/a² - y²/b² =1
(Note: we know its a left and right hyperbola because the focus here is in the x coordinate)
Substitute the values
*x²/4 - y²/5 =1*
Now, to find the *domain* and *range* :
D(-inf,-2] U[2, inf)
R(-inf, inf)
so helpful, thank you
Good job
Give us a video about arithmetic circuits
How about (Y+4)² - (X-3)²=1 they don't have a denaminator? Can you give another example? Thanks
Thanks 😊